Figure P8.33 shows a circuit with a resistor, an inductor, and a capacitor in parallel. Kirchhoff's rules can be used to express the impedance of the system as 1 Z = 1 R 2 + ( ω C − 1 ω L ) 2 where Z = impedance ( Ω ) and ω = the angular frequency. Find the ω that results in an impedance of 75 Ω using both bisection and false position with initial guesses of 1 and 1000 for the following parameters: R = 225 Ω , C = 0.6 × 10 − 6 F, and L = 0.5 H . Determine how many iterations of each technique are necessary to deter-mine the answer to ε s = 0.1 % . Use the graphical approach to explain any difficulties that arise. FIGURE P8.33
Figure P8.33 shows a circuit with a resistor, an inductor, and a capacitor in parallel. Kirchhoff's rules can be used to express the impedance of the system as 1 Z = 1 R 2 + ( ω C − 1 ω L ) 2 where Z = impedance ( Ω ) and ω = the angular frequency. Find the ω that results in an impedance of 75 Ω using both bisection and false position with initial guesses of 1 and 1000 for the following parameters: R = 225 Ω , C = 0.6 × 10 − 6 F, and L = 0.5 H . Determine how many iterations of each technique are necessary to deter-mine the answer to ε s = 0.1 % . Use the graphical approach to explain any difficulties that arise. FIGURE P8.33
Figure P8.33 shows a circuit with a resistor, an inductor, and a capacitor in parallel. Kirchhoff's rules can be used to express the impedance of the system as
1
Z
=
1
R
2
+
(
ω
C
−
1
ω
L
)
2
where
Z
=
impedance
(
Ω
)
and
ω
=
the angular frequency. Find the
ω
that results in an impedance of 75
Ω
using both bisection and false position with initial guesses of 1 and 1000 for the following parameters:
R
=
225
Ω
,
C
=
0.6
×
10
−
6
F, and
L
=
0.5
H
. Determine how many iterations of each technique are necessary to deter-mine the answer to
ε
s
=
0.1
%
. Use the graphical approach to explain any difficulties that arise.
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HOW TO FIND DETERMINANT OF 2X2 & 3X3 MATRICES?/MATRICES AND DETERMINANTS CLASS XII 12 CBSE; Author: Neha Agrawal Mathematically Inclined;https://www.youtube.com/watch?v=bnaKGsLYJvQ;License: Standard YouTube License, CC-BY