PYTHON CODE: In order to beat AlphaZero, Grandmaster Hikaru is improving her chess calculation skills.Today, Hikaru took a big chessboard with N rows (numbered 1 through N) and N columns (numbered 1 through N). Let's denote the square in row r and column c of the chessboard by (r,c). Hikaru wants to place some rooks on the chessboard in such a way that the following conditions are satisfied:• Each square of the board contains at most one rook.• There are no four rooks forming a rectangle. Formally, there should not be any four valid integers r1, c1, r2, c2 (≠r2,c1≠c2) such that there are rooks on squares (r1,c1), (r1,c2 (r2,c1)and (r2,c2).• The number of rooks is at least 8N.Help Hikaru find a possible distribution of rooks. If there are multiple solutions, you may find any one. It is guaranteed that under the given constraints, a solution always exists.InputThe first line of the input contains a single integer T denoting the number of test cases. The first and only line of each test…

Part 2: Binary Arithmetic One of the most common operations we perform on binary numbers (and all numbers) is addition. It can be cumbersome to convert your binary numbers to decimal just to add them and convert them back, so instead we will be learning how to add binary numbers directly. Binary addition works the same way as decimal addition, with the added restriction that each digit can only go up to 1. Let's consider the possibilities for adding the values of any 2 single digits together: 0 + 0 0 + 1 1 + 0 1 + 1 0 1 1 10 (remember that 10 in binary represents the number 2) In that last case, the result is larger than a single digit. When adding larger binary numbers, that means we have to carry the 1 over to the next column. This presents us with another new case: what happens if we have 1 + 1 + carried 1? In that case, the result is 11, which means that column's result is 1, and we carry 1 to the next column. Below is an example of adding two binary numbers that shows all…

9.5.1: Use the addChoice method to add any needed instance variables. Provide a different implementation of ChoiceQuestion. Instead of storing the choices in an array list, the addChoice method should add the choice to the question text. For this purpose, an addLine method has been added to the Question class.   ChoiceQuestion.java: /**   A question with multiple choices.*/public class ChoiceQuestion extends Question{   // Add any needed instance variables, but don't store the choices   // The choices should be added to the text of the superclass   /* Your code goes here */      /**      Constructs a choice question with a given text and no choices.      @param questionText the text of this question   */   public ChoiceQuestion(String questionText)   {      /* Your code goes here */   }    /**      Adds an answer choice to this question.      @param choice the choice to add      @param correct true if this is the correct choice, false otherwise   */   public void…

Q#2 Write a recursive function zeroCount ( int a[ ],  int s, int e) that receives an array of integers a [], a start index s, and an end index e. The function should return the number of zeros in that array between s and e. int zeroCount ( int a[ ],  int s, int e);  Trace your function given the following array and function call. Draw your steps. int a[ ] = {1, 0, 0, 5}; int zeros = zeroCount(a, 0, 3); language c++

12. Consider the recursive function int gcd( int a, int b) int gcd( int a, int b){ if (b > a) return gcd(b,a); if ( b == 0 ) return a; return gcd( b, a% b); } How many invocation (calls) of the gcd() function will be made by the call gcd(72, 30)?

Java Programming- Need the code-   Suppose we have a string holding the text of an entire book. If we want to analyze segments of the text, it is inefficient to make substrings. Instead, we should just store a reference to the original text and the starting and ending positions. Design a class Segment that does this, and have it implement the CharSequence interface of the standard library. Write a test program in which you demonstrate that you can pass your Segment objects to methods that accept CharSequence instances, such as String.join and PrintStream.append.

WRITE CODE IN C LANGUANGE On their way down the river, Jojo and Lili saw two frogs each in position X1 and X2. The two frogs are seen jumping happily towards the same direction that is come to Jojo. After watching the two frogs, Joio and Lili saw that the speed the two frogs are different. The first frog to start jumping from position X1 has a speed of v1, while the second frog that starts to jump from position X2 has a speed of V2. Joig guess that "YES" both frogs will be in the same position in a certain time T, while Bibi guessing "NO" the two frogs will never be in the same position in time. Help Joio and Lili calculate the frog's movements to determine whether the guess they are right

CODE IN PYTHON In an alternate reality, chemistry Professors Hodge and Sibia have teamed up to design a chemical compound X such that when X is added to Dan’s favorite food (saltine crackers), it’ll make him despise it. For this, they are working with 6 kinds of extracts: Singleton Extracts: berries (B), green veggies (G), dairy (D) Combination Extracts: icecream (I), salad (S), and cheese sauce (C) Like regular food, mixing two extracts of the same kind will result in an extract of the same kind (eg. mixing berries B with berries B will result in berries B). Mixing two singleton extracts will result in a combination extract, using these rules: Berries (B) + Green Veggies (G) = Salad (S) Berries (B) + Dairy (D) = Icecream (I) Green Veggies (G) + Dairy (D)= Cheese Sauce (C) Mixing two combination extracts will result in a singleton extract closest to them. For example, Icecream (I) + Salad (S) is closest to Berries (B) since both Icecream and Salad extracts require using Berry…

Count consecutive summers def count_consecutive_summers(n): Like a majestic wild horse waiting for someone to come and tame it, positive integers can be broken down as sums of consecutive positive integers in various ways. For example, the integer 42 often used as placeholder in this kind of discussions can be broken down into such a sum in four different ways: (a) 3 + 4 + 5 + 6 + 7 + 8 + 9, (b) 9 + 10 + 11 + 12, (c) 13 + 14 + 15 and (d) 42. As the last solution (d) shows, any positive integer can always be trivially expressed as a singleton sum that consists of that integer alone. Given a positive integer n, determine how many different ways it can be expressed as a sum of consecutive positive integers, and return that count. The count of how many different ways a positive integer n can be represented as a sum of consecutive integers is also called its politeness, and can be alternatively computed by counting how many odd divisors that number has. However, note that the linked…