EBK EXPLORING CHEMICAL ANALYSIS
EBK EXPLORING CHEMICAL ANALYSIS
5th Edition
ISBN: 9781319416942
Author: Harris
Publisher: VST
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Chapter 8, Problem 8.30P
Interpretation Introduction

Interpretation:

The value of pH 0.050MNaCN has to be found.

Concept Introduction:

pH:

pH is a scale used to specify how acidic or basic a solution is.  It ranges from 0-14. pH 7.0 is considered as neutral solution, pH more than 7.00 is taken as basic solution whereas pH less than 7.0 is considered as acidic solution (at 25oC).  It is the measurement of activity of free H+ and OH- in solution.

  pH=log[H3O+]

  pOH=log[OH]

From ionization constant of water Kw=[H+][OH-]

Ionization constant of water at 25οC Kw=1×1014.

Less the pH more is the acidity of the solution.

Expert Solution & Answer
Check Mark

Answer to Problem 8.30P

The value of pH is 10.9.

Explanation of Solution

As known, KaofHCN is 6.2×1010.

The value of KbofHCN is calculated as,

    Kb=KwKa=1×10-146.2×1010=1.613×10-5.

In water:

  CN-+H2OHCN+OH-(0.050)00(0.050x)xx

From the above equation,

  Kb=[HCN][OH-][CN-]1.613×10-5=x20.050x=(1.613×10-5)(0.050)=0.08065×10-5=8.98×10-4.

The value of pOH is calculated as,

  pOH=log[OH-]=log(8.98×10-4)=3.0.pH=14pOH=143.0=11

Therefore, the value of pH is 11.

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