Chapter 8, Problem 8.42UKC

Interpretation Introduction

Interpretation:

The $\left[{\text{H}}_{\text{3}}{\text{O}}^{\text{+}}\right]$ and concentration of ${\text{OH}}^{\text{-}}$ ion in the pancreas if the $\text{pH}$ is $\text{8}\text{.2}$ has to be calculated.

Concept Introduction:

The $\text{pH}$ of the solution is calculated using the formula,

  $\text{pH=-log}\left[{\text{H}}_{\text{3}}{\text{O}}^{\text{+}}\right]$

Concentration of ${\text{H}}_{\text{3}}{\text{O}}^{\text{+}}$ is antilogarithm of $\text{pH}\text{.}$  The concentration is calculated as,

  $\left[{\text{H}}_{\text{3}}{\text{O}}^{\text{+}}\right]{\text{=10}}^{\text{-pH}}$

The ion-product constant for water $\left({\text{K}}_{\text{w}}\right)$ is calculated using the formula,

  ${\text{K}}_{\text{w}}\text{=}\left[{\text{H}}_{\text{3}}{\text{O}}^{\text{+}}\right]\left[{\text{OH}}^{\text{-}}\right]$

The value of ${\text{K}}_{\text{w}}$ is $\text{1}{\text{.0×10}}^{\text{-14}}$ for all aqueous solution at ${\text{25}}^{\text{o}}\text{C}\text{.}$