Bundle: Steel Design, Loose-leaf Version, 6th + Mindtap Engineering, 1 Term (6 Months) Printed Access Card
6th Edition
ISBN: 9781337761505
Author: William T. Segui
Publisher: Cengage Learning
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Question
Chapter 8, Problem 8.4.4P
To determine
The maximum load carried by the weld.
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Determine the maximum service load, P, that can be applied if the live load-to-dead load ratio is 2.0. Each component is a PL 3⁄4 x 7 of A242 steel. The weld is a 1⁄2-inch fillet weld, E70 electrode. a. Use LRFD. b. Use ASD.
A channel C250x37 mm section is welded to a 9 mm gusset plate. Welding is not permitted on the back of the channel. All steel is A36 with Fy=250 MPa and Fu=400 MPa. Use E70electrodes having and Fu=485 MPa (SMAW) process. The maximum length of lap is 250mm. The size of fillet weld is 8mm. Assume the width of slot weld is 22 mm. Size of slot weld is 13mm
Properties of C250x37
A = 4750 mm2
tw = 13.0 mm2
d = 254 mm
a. Determine the force resisted by the slot weld in kN, when the full tensile capacity is 712.5 KN (from the gross yielding capacity using ASD)
Hint: Full tensile Capacity = Force Resisted by Fillet and Slot Weld
Round your answer to 3 decimal places.
Tension Member Design
Problem 1. A channel shape is under 50 kips dead and 100 kips live tensile axial load as shown in the
figure. The member is connected to a gusset plate with 10 inch longitudinal welds. Find the lightest
channel shape to carry the loading. Use only vielding and rupture limit states to design. Use 50 ksi steel
(Fy=50 ksi, Fu=65 ksi).
(a) Assume yielding limit state controls in the design process;
(b) After selecting the lightest section, check the rupture limit state. Do not redesing if needed.
1
Pa=50 kips
PL=100 kips
10"
Chapter 8 Solutions
Bundle: Steel Design, Loose-leaf Version, 6th + Mindtap Engineering, 1 Term (6 Months) Printed Access Card
Ch. 8 - Prob. 8.2.1PCh. 8 - Prob. 8.2.2PCh. 8 - A plate is used as a bracket and is attached to a...Ch. 8 - Prob. 8.2.4PCh. 8 - Prob. 8.2.5PCh. 8 - Prob. 8.2.6PCh. 8 - Prob. 8.2.7PCh. 8 - Prob. 8.2.8PCh. 8 - Prob. 8.2.9PCh. 8 - Prob. 8.2.10P
Ch. 8 - Prob. 8.2.11PCh. 8 - Prob. 8.2.12PCh. 8 - Prob. 8.2.13PCh. 8 - Prob. 8.3.1PCh. 8 - Prob. 8.3.2PCh. 8 - Prob. 8.3.3PCh. 8 - Prob. 8.3.4PCh. 8 - Prob. 8.3.5PCh. 8 - Prob. 8.3.6PCh. 8 - Prob. 8.3.7PCh. 8 - Prob. 8.3.8PCh. 8 - Prob. 8.3.9PCh. 8 - Prob. 8.3.10PCh. 8 - Use an elastic analysis and determine the maximum...Ch. 8 - Use an elastic analysis and determine the maximum...Ch. 8 - Use an elastic analysis and determine the maximum...Ch. 8 - Prob. 8.4.4PCh. 8 - Prob. 8.4.5PCh. 8 - Prob. 8.4.6PCh. 8 - Use an elastic analysis and compute the extra load...Ch. 8 - Use an elastic analysis and compute the extra load...Ch. 8 - Prob. 8.4.9PCh. 8 - Prob. 8.4.10PCh. 8 - Prob. 8.4.11PCh. 8 - Prob. 8.4.12PCh. 8 - Prob. 8.4.13PCh. 8 - Prob. 8.4.14PCh. 8 - Prob. 8.4.15PCh. 8 - Prob. 8.4.16PCh. 8 - Prob. 8.4.17PCh. 8 - Prob. 8.4.18PCh. 8 - a. Use LRFD and design a welded connection for the...Ch. 8 - Prob. 8.4.20PCh. 8 - Prob. 8.5.1PCh. 8 - Prob. 8.5.2PCh. 8 - Prob. 8.5.3PCh. 8 - Prob. 8.5.4PCh. 8 - Prob. 8.5.5PCh. 8 - Prob. 8.6.1PCh. 8 - Prob. 8.6.2PCh. 8 - Prob. 8.6.3PCh. 8 - Prob. 8.6.4PCh. 8 - Prob. 8.7.1PCh. 8 - Prob. 8.7.2PCh. 8 - Prob. 8.7.3PCh. 8 - Prob. 8.8.1PCh. 8 - Prob. 8.8.2PCh. 8 - Prob. 8.8.3PCh. 8 - Prob. 8.8.4P
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Similar questions
- Use an elastic analysis and determine the maximum load in the weld (in kips per inch of length).arrow_forwardThe double T-beam is fabricated by welding the three plates together as shown.  Part A Determine the shear stress in the weld necessary to support a shear force of V=78 kN�=78 kN.arrow_forwardPlease solve correctlyarrow_forward
- a. Determine the design strength of a 1-in length of a 1/4-in fillet weld formed by the shielded metal arc process (SMAW) and E70 electrodes with a minimum tensile strength FEXX = 70 ksi. Assume that load is to be applied parallel to the weld length.b. Repeat part (a) if the weld is 20 in long.c. Repeat part (a) if the weld is 30 in long.arrow_forward7. Use Allowable Strength Design – ASD 8. Use Load and Resistance Factor Design – LRFD Answer everything. Thank you!arrow_forwardSituation 5. The angular section shown below is welded to a 12 mm gusset plate. Both materials are A36 steel with Fy = 250 MPa. The allowable tensile stress is 0.6Fy. The weld is E80 Electrode and 12 mm thickness. INNOVATIONS Properties of L 150x90x12: y = 50 shear stress of weld = 0.3Fu A = 2750 Allowable REVIEW INNOVATIE a K ➜ www A. 234 KN B. 349 KN b 13. What is the value of P without exceeding the allowable tensile the angle? C. 382 kN p. 413 kN 14. Find required length of the weld based on shear? A. 280 mm C. 300 mm D. 380 mm B. 320 mm 15. Find the required value of a? A. 108 mm B. 97.9 mm D. 185 mm NEW INNOVATIONS REVIEW INNOVATIOf REVIEW NEW INNOVATIONSarrow_forward
- A tension plate shown below is used to support suspended load "T". Gusset Plate- F, = 248 MPa Fu = 400 MPa %3D 200 mm a) Determine the allowable tensile capacity of the plate if L= 240 mm. (Assume weld strength is satisfactory).arrow_forwardA tension member splice is made with 14-inch E70 fillet welds as shown in Figure 5. Each side of the splice is welded as shown. All steel is A36. Determine the maximum service load, P, that can be applied if the live load to dead load ratio is 1.5. Note: Assume that the base metal shear strength is adequate (check the yielding strength for the gross area, fracture strength for the effective net area, weld strength and block shear strength). PL 5/8x8 4 in. Figure 5 2 PL 7/16x4arrow_forwardA tension member splice is made with 14-inch E70 fillet welds as shown in Figure 5. Each side of the splice is welded as shown. All steel is A36. Determine the maximum service load, P, that can be applied if the live load to dead load ratio is 1.5. Note: Assume that the base metal shear strength is adequate (check the yielding strength for the gross area, fracture strength for the effective net area, weld strength and block shear strength). P PL 58x8 1 4 in. Figure 5 a. Use LRFD. b. Use ASD. 2 PL 7/16x4 Parrow_forward
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