Chapter 8, Problem 8.44PP

Summary Introduction

To determine:

The preparation of $2\text{L}$ of $1\text{M}$ ${\text{MgCl}}_2$ from a $5\text{M}$ ${\text{MgCl}}_2$ stock solution.

Introduction:

The dilution equation is,

$M_1{V}_1=M_2{V}_2$

Where,

• $M_1$ is the molarity of the initial concentrated solution.
• $V_1$ is the volume of the initial concentrated solution.
• $M_2$ is the molarity of the final diluted solution.
• $V_2$ is the volume of the final diluted solution.

This equation works as it gives the number of moles of solute that is equal in both the solutions when molarity is multiplied by the volume.