Physical Chemistry
Physical Chemistry
2nd Edition
ISBN: 9781133958437
Author: Ball, David W. (david Warren), BAER, Tomas
Publisher: Wadsworth Cengage Learning,
Question
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Chapter 8, Problem 8.60E
Interpretation Introduction

(a)

Interpretation:

The ionic strength for 0.0055molalHCl solution is to be calculated.

Concept introduction:

The ionic strength is given by the formula given below.

I=12i=1ionsmizi2

In the above expression, mi is the molality of the i th ion and zi2 is the square of charge on the ions. In a chemical reaction, the ionic strength is calculated as the sum of products of molality and square of charge on the ions.

Interpretation Introduction

(b)

Interpretation:

The ionic strength for 0.075molalNaHCO3 is to be calculated.

Concept introduction:

The ionic strength is given by the formula given below.

I=12i=1ionsmizi2

In the above expression, mi is the molality of the i th ion and zi2 is the square of charge on the ions. In a chemical reaction, the ionic strength is calculated as the sum of products of molality and square of charge on the ions.

Interpretation Introduction

(c)

Interpretation:

The ionic strength for 0.0250molalFe(NO3)2 is to be calculated.

Concept introduction:

The ionic strength is given by the formula given below.

I=12i=1ionsmizi2

In the above expression, mi is the molality of the i th ion and zi2 is the square of charge on the ions. In a chemical reaction, the ionic strength is calculated as the sum of products of molality and square of charge on the ions.

Interpretation Introduction

(d)

Interpretation:

The ionic strength for 0.0250Fe(NO3)3 is to be calculated.

Concept introduction: The ionic strength is given by the formula given below

I=12i=1ionsmizi2

In the above expression, mi is the molality of the i th ion and zi2 is the square of charge on the ions. In a chemical reaction, the ionic strength is calculated as the sum of products of molality and square of charge on the ions.

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Chapter 8 Solutions

Physical Chemistry

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