Concept explainers
Calculate the consolidation settlement under the center of mat foundation.
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The consolidation settlement under the center of mat foundation is
Given information:
The length of the foundation is
The width of the foundation is
The depth of the foundation
The load value Q is
The preconsolidation pressure
The depth values are
Calculation:
Find the consolidation settlement at the center of the foundation using the relation.
Find the stress
Height of clay
Find the net load per unit area using the relation.
Find the average stress increase in the clay layer below the corner of each rectangular area.
For
Refer to Figure 6.11, “Influence factor
Take the influence factor
For
Refer to Figure 6.11, “Influence factor
Take the influence factor
Find the consolidation settlement at the center of the foundation using the relation.
Therefore, the consolidation settlement under the center of mat foundation is
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Principles of Foundation Engineering (MindTap Course List)
- A water tower is founded on a circular ring type foundation. The width of the ring is 4 m and its internal radius is 8 m. Assuming the distributed load per unit area as 300 kN/m2, determine the vertical pressure at a depth of 6 m below the center of the foundation.arrow_forward2.An oil storage tank 35 m in diameter is located 2 m below the surface of a deposit of clay 32 m thick, the water table being at the surface: the net foundation pressure is 105 kN/m2. A firm stratum underlies the clay. The average value of mv for the clay is 0.14 m^2/MN and that of pore pressure coefficient A is 0.65. The undrained value of Young’s modulus is estimated to be 40 MN/m^2 Determine the total settlement under the centre of the tank.arrow_forwardA 5 m-thick clay (Gs = 2.65, water content = 0.28) is overlain by a 4.50m-thick layer of sand (Gs = 2.60, e = 0.70, S = 0.85). The ground water table is located 4.50 m from the ground surface. Compute for the following: 1. At what depth would the vertical effective stress be equal to 120 kPa? 2. What is the vertical effective stress at a depth 9 m below the ground surface? 3. The depth of excavation required to reduce the effective stress at the bottom of the clay layer by 100 kPa. Question 1: A. 1.94 Question 1: B. 3.99 Question 1: C. 6.44 Question 1: D. 8.49 Question 2: A. 168.9 Question 2: B. 44.1 Question 2: C. 120.1 Question 2: D. 124.8 Question 3: A. 1.83 Question 3: B. 7.67 Question 3: C. 3.17 Question 3: D. 6.33arrow_forward
- A 5 m-thick clay (Gs = 2.65, water content = 0.28) is overlain by a 4.50m-thick layer of sand (Gs = 2.60, e = 0.70, S = 0.85). The ground water table is located 4.50 m from the ground surface. Compute for the following: 1. At what depth would the vertical effective stress be equal to 120 kPa? 2. What is the vertical effective stress at a depth 9 m below the ground surface? 3. The depth of excavation required to reduce the effective stress at the bottom of the clay layer by 100 kPa.arrow_forwardA 300 mm 450 mm plate was used in carrying out a plate loading test in a sand, during which the plate settled 5 mm under the applied pressure of 250 kN/m2. a. What is the coefficient of subgrade reaction for a 300 mm wide square plate? b. What would be the coefficient of subgrade reaction of a 2 m 3 m foundation?arrow_forwardA flexible circular area of radius 3.3 m. is uniformly loaded by q = 341 kN/m². Determine the increase in vertical stress, 3.2 m. deep at its center.arrow_forward
- From the figure shown, the soil layer beneath the 203m dam has Kx = 0.3m/day and Kz = 0.4m/day. Determine the following: • Uplift force per unit length (kN/m) • Seepage through the foundation (m^3 /day)arrow_forwardA rectangular footing (4.89 x 4.38 m.) is placed 1.21 m. below the ground surface. The soil arrangement is composed of sand (ground) for the first 6.52 meters and followed by clay for the next 6.98 meters. The force acting on the footing is 10,293 kN. Determine the resulting stress increase at the midheight of the consolidating layer in kPa. Assume a 2V:1H pressure diagram. Unit weight of sand = 16.1 kN/m3. Unit weight of clay = 18.7 kN/m3. Use stored value. Answer in five decimal places.arrow_forwardSolve Problem 7.8 using Eq. (7.29). Ignore the post-construction settlement. 7.8 Solve Problem 7.4 with Eq. (7.20). Ignore the correction factor for creep. For the unit weight of soil, use γ = 115 lb/ft3. 7.4 Figure 7.3 shows a foundation of 10 ft × 6.25 ft resting on a sand deposit. The net load per unit area at the level of the foundation, qo, is 3000 lb/ft2. For the sand, μs = 0.3, Es = 3200 lb/in.2, Df = 2.5 ft, and H = 32 ft. Assume that the foundation is rigid and determine the elastic settlement the foundation would undergo. Use Eqs. (7.4) and (7.12).arrow_forward
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