For the following exercises, express the equation for the hyperbola as two functions , withy as a function of x. Express as simply as possible. Use a graphing calculator to sketch the graph of the two functions on the same axes. 58. ( x − 2 ) 2 16 − ( y + 3 ) 2 25 = 1
For the following exercises, express the equation for the hyperbola as two functions , withy as a function of x. Express as simply as possible. Use a graphing calculator to sketch the graph of the two functions on the same axes. 58. ( x − 2 ) 2 16 − ( y + 3 ) 2 25 = 1
For the following exercises, express the equation for the hyperbola as two functions, withy as a function of x. Express as simply as possible. Use a graphing calculator to sketch the graph of the two functions on the same axes.
58.
(
x
−
2
)
2
16
−
(
y
+
3
)
2
25
=
1
Expression, rule, or law that gives the relationship between an independent variable and dependent variable. Some important types of functions are injective function, surjective function, polynomial function, and inverse function.
To design the interior surface of a huge stainless-steel tank, you revolve the curvey = x3, 0 ≤ x ≤ 3, about the y-axis. The container, with dimensions in meters, is partiallyfilled with seawater, a cubic meter of which weighs 10,000 N. The depth of the water is 1m.How much work will it take to empty the tank by pumping the water to the tank’s top?
Consider the following function.
t(x)=(x−4)2+7
Step 4 of 4:
Graph the parabola.
(1) By substituting x = 20 into the equation of the parabola, findthe coordinates of the point where the line x = 20 meets theparabola.
(2) Using your answer to part (d)(ii)(1), explain whether the ballgoes higher than a tree of height 8.5 m that stands 20 m fromDominic and lies in the path of the ball.
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, algebra and related others by exploring similar questions and additional content below.
Finding The Focus and Directrix of a Parabola - Conic Sections; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=KYgmOTLbuqE;License: Standard YouTube License, CC-BY