Chapter 8.3, Problem 8QR

To determine

To find : the area of plane region.

Answer to Problem 8QR

The area of plane region is $\frac{\sqrt{15}{x}^2}{4}$ .

Explanation of Solution

Given information : The area of an isosceles triangle with two sides of length $2x$ and one side of length of $x$ .

Calculation :

An isosceles triangle with two sides of length $2x$ and one side of length of $x$ ,

The line giving the height of the triangle will bisect the base into two equal halves of length $\raisebox{1ex}{$x$}\!\left/ \!\raisebox{-1ex}{$2$}\right.$ .

The height of triangle as $\frac{\sqrt{15}{x}^2}{4}$ .

The area of the triangle is given by:

  $\frac{\sqrt{15}{x}^2}{4}$