Chapter 8.5, Problem 10E

a.

To determine

To find the force applied when compressing the scale 1/8 inches weight.

Answer to Problem 10E

300 lb someone who compressing the scale 1/8 inches.

Explanation of Solution

Given information: A bathroom scale is compressed 1/16 in. when a 150-lb person stands on its.

Calculation:

As per the given problem,

We know that if a 150 lb person compresses the spring 1/16 inches, then a person weighting double that amount will compress the spring double, i.e.

  $150\times 2=300$

Hence, 300 lb someone who compressing the scale 1/8 inches.

b.

To determine

To find the work done in compressing the scale of 1/8 inches.

Answer to Problem 10E

18.75 lb-in. work is done in compresses the scale 1/8 inches.

Explanation of Solution

Given information: A bathroom scale is compressed 1/16 in. when a 150-lb person stands on its.

Calculation:

As per the given problem,

The amount of work done in compressing the spring 1/8 inch is given by the integral,

  $\begin{array}{l}{\displaystyle {\int }_0^{1/8}2400xdx}\\ =18.75\end{array}$

Hence, 18.75 lb-inches work is done in compresses the scale 1/8 inches.