Advanced Engineering Mathematics
6th Edition
ISBN: 9781284105902
Author: Dennis G. Zill
Publisher: Jones & Bartlett Learning
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Chapter 8.7, Problem 2E
To determine
To Solve: The given system of equations using Cramer’s rule.
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Problems 74–77 are based on material learned earlier in the course. The purpose of these problems is to keep the material fresh in your
mind so that you are better prepared for the final exam.
74. To graph g(x) = |x + 2| – 3, shift the graph of
f(x) = \x|
units
76. Solve: logs (x + 3) = 2
units
and then
77. Solve the given system using matrices.
number
Teft/right|
number
up/down
Зх + у + 2z %3 1
75. Find the rectangular coordinates of the point whose polar
2x – 2y + 5z =
5
x + 3y + 2z = -9
coordinates are ( 6,
3
5.
By using the matrix methods to solve the following linear system:
I1 + 12 – 13 = 5, 3r1 +x2 – 2r3 = -4,
-I1 + 12 - 2r3 = 3;
Solve each system in Exercises 1–4 by using elementary rowoperations on the equations or on the augmented matrix. Followthe systematic elimination procedure described in this section.. x1 + 5x2 =7 - 2x1- 7x2 = -5
Chapter 8 Solutions
Advanced Engineering Mathematics
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- 1. Use Cramer's rule to solve the following system: 2x₁2x₂ + 3x3 = 0 x₁ + 2x₂ + 3x3 = 8 -2x₁ + 4x₂ + x3 = 6arrow_forward1. Solve the following system of equations using cramer's rule -3x+2y-6z = 6 5x+7y-5z = 6 x+4y-2z = 8arrow_forward2. Find the solution set to the following system of linear equations using Gauss-Jordan elimination. (2.x1 + 7x2 – 12.x3 = -9 x1 + 2x2 – 3.x3 = 0 3x1 + 5x2 – 7x3 = 3 - Determine the rank of the coefficient matrix and the augmented matrix.arrow_forward
- 6. Use Cramer’s Rule to solve for x3 of the linear system 2x1 + x2 + x3 = 63x1 + 2x2 − 2x3 = −2x1 + x2 + 2x3 = −4arrow_forward1. Solve the following system of linear equations by Cramer's Rule, Gauss- Elimination, and Gauss-Jordan X1 + X2 + X3 = 5 X1 + 2X2 +2X3 = 6 X1 + 2X2 + 3X3 = 8arrow_forward1. Use Cramer's rule to solve the following systems X1 + 3x2 -5 а. 2x1 – x2 4 2.x1 + 3x2 + x3 b. 4.x1 + 7x2 + 5x3 8 20 -2x2 + 2x3 I| ||||arrow_forward
- In Exercises 11–14, solve the systems of equations in Z7.arrow_forward4. Use Gaussian elimination with backward substitution to solve the following linear system: 2x1 + x2 – x3 = 5, x1 + x2 – 3x3 = -9, -x1 + x2 + 2x3 = 9;arrow_forward4. Solve by Matrix Inversion. * For this number, solve using X = (A-1)B 2w – 2x + 3y + 4z = 33 3w – 5x – 7y + 3z = 11 4w + 3x – 4y – 5z = 3 5w + 4x + 6y – 2z = 45 1 Add filearrow_forward
- Example 28. Solve the following system of equations by Cramer's rule : - 4y 2x – 5y + 2z = 39 -3x + 2y + z = 1 X - -z = 11arrow_forwardQuestion 5 Is it possible for a system of equations composed of a linear function and a quadratic func- tion to have 2 solutions? It is not possible for a system of equations composed of a linear function and a quadratic function to have 2 solutions. It is possible for a system of equations composed of a linear function and a quadratic function to have 2 solutions. B.arrow_forward2. Solve for x in the given matrix equalitiesarrow_forward
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