To find the Maclaurin series of
Answer to Problem 36E
The Maclaurin expansion of the function is
Explanation of Solution
Given information:
Formula used: The Maclaurin expansion of the function:
Calculation : The Maclaurin expansion of the function becomes as:
Graph:Using graphingutility to sketch the graph.
Enter the expression:
From the above graph, it is concluded that both the function and the Taylor’s polynomial having same origin. Also, the graph of both the functions are same upto certain value.
Hence, the Maclaurin expansion of the function:
Also, the radius of convergence is
Chapter 8 Solutions
Single Variable Calculus: Concepts and Contexts, Enhanced Edition
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning