Explanation Given information : The tension T required to pull the 200 lb force around the collar is 215 lb. Explanation : Show the free body diagram of the assembly as in Figure (1). Use Figure (1). Take moment about point P . ∑ M P = 0 T 1 ( r + r f ) − T ( r − r f ) = 0 (I) Here, the radius of the collar is r . Determine the radius r f of the friction angle using the formula. r f = ( d 2 ) sin ϕ s (II) Here, the diameter of the collar is d . Determine the angle of static friction ϕ s using the formula. ϕ s = tan − 1 ( μ s ) (III) Conclusion : Substitute 200 lb for T 1 , 1.125 inches for r , and 215 lb for T in Equation (I). 200 ( 1.125 + r f ) − 215 ( 1.125 − r f ) = 0 225 + 200 r f − 241

Masteringengineering -- Access Card -- For Engineering Mechanics: Statics

13th Edition

ISBN: 9780132915793

Author: Russell C. Hibbeler

Publisher: Prentice Hall

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Chapter 8.8, Problem 123P

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The coefficient of static friction at the contacting surface.

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Chapter 8.8, Problem 122P

Chapter 8.8, Problem 124P

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Chapter 8 Solutions

Masteringengineering -- Access Card -- For Engineering Mechanics: Statics

Ch. 8.2 - Determine the friction developed between the 50-kg...Ch. 8.2 - Determine the minimum force P to prevent the 30-kg...Ch. 8.2 - Determine the maximum force P that can be applied...Ch. 8.2 - If the coefficient of static friction at contact...Ch. 8.2 - Determine the maximum force P that can be applied...Ch. 8.2 - Prob. 6FP Ch. 8.2 - Blocks A, B, and C have weights of 50 N, 25 N, and...Ch. 8.2 - If the coefficient of static friction at all...Ch. 8.2 - Using the coefficients of static friction...Ch. 8.2 - Prob. 1P

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The coefficient of static friction at the contacting surface.

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Chapter 8 Solutions