EBK DELMAR'S STANDARD TEXTBOOK OF ELECT
6th Edition
ISBN: 9781305537125
Author: Herman
Publisher: YUZU
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Chapter 9, Problem 11RQ
To determine
Value of Thevenin Voltage drop across terminals A and B.
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For the circuit shown in figure below, find the unknown currents I1, I2, I3, I4, I5. All the
currents are in Ampere. X1= -9A, X2=9A, X3=5A
X2
12
X1
X3
20 A
20 A
3. From the figure, when the voltage V3 is 10 volts, the voltage VZ1 is 5 volts, the voltage VD8
is 0.7 volts, and the resistances R7, R8 and R9 are 10, 50 and 100 ohms, respectively. Show
the method. Calculate and answer questions in the following blanks.
R7
D8
Z1 7
V3
RB
R9
Current flowing through R7 : Answer..
Freckles flowing through Z1 : Answerŋ
Current flowing through R8 : Answer..
Freckles flowing through D8 : Answen
Current flowing through R9 : Answer..
Supply current V3 : Answerj
SECTION 2 Basic Electric Circuits
R1
Es
R2
FIGURE 9-34 Review Questions 11 through 15.
To answer Questions 11 through 15, refer to the circuit shown in Figure 9–34.
11. In the circuit shown in Figure 9–34, assume that R, has a resistance of 4 N and R2
has a resistance of 20 N. Battery Es has a voltage of 48 V. What is the Thevenin
equivalent voltage for this circuit across Terminals A and B?
ETHEV
%3D
12. What is the equivalent Thevenin resistance for the circuit described in
Question 11?
RTHEV =
Ω
13. In the circuit shown in Figure 9-34, assume that R, has a resistance of 2.5 N and
R, has a resistance of 16 N. Power source Es has a voltage of 20 V. As measured
across Terminals A and B, what would be the equivalent Norton current for this
circuit?
INORTON =
14. What is the equivalent Norton resistance for the circuit described in Question 13?
RNORTON =
Ω
15. Assume that an 8-N load resistance is connected across Terminals A and B for the
circuit described in Question 13. How much…
Chapter 9 Solutions
EBK DELMAR'S STANDARD TEXTBOOK OF ELECT
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- solve the actual value of each resistor using kirchhoff's law. R1 = 10kohmsR2 = 3kohmsR3 = 5kohmsR4 = 15kohmsR5 = 18kohmsA1 = -1.2mAA2 = 1.2mAA3 = -1mAA4 = -150.8uAA5 = 150.8uAV1 = 12VV2 = -3.5VV3 = 5VV4 = 2.2VV5 = -2.7V the VS1 is 20Varrow_forward7. The equivalent total resistance in the circuit in Figure 1 is_ 2200 E=7V- 1000. 4700. 100. 3300 Figure 1 1. 558.90 2. 2160 3. 642.450 4. 82.892 8. The current through the 1002 resistor in the circuit in Figure 1 is_ 1. 84.45mA 2. 70mA 3. 14.89mA 4. 17.51mA 9. The power dissipated by the 3302 resistor in the circuit in Figure 1 isarrow_forwardTo answer Questions 6 through 10, refer to the circuit shown in Figure 9–33 6. How much current flows through R¡? I, = 7. How much current flows through R? I, = 8. How much voltage is dropped across R¡? E, = 9. How much voltage is dropped across R2? E2 10. How much voltage is dropped across R3? E = E2 12 R2 200 2 E1 R1 330 2 E3 13 R3 100 Es1 24 V Es2 10 V GURE 9-33 Review Questions 6 through 10.arrow_forward
- 2. Three resistors R1, R2 and R3 are connected in series parallel with R1 in series with parallel combination of R2 and R3. The whole combination is connected across a 120V DC source. Resistors R1, R2 and R3 takes 750 w, 250 W and 200 W, respectively. Calculate the resistance R2. Why are street lights connected in parallel and not in series, explain.arrow_forwardSolve by Method of Branch Current by using figure 1. | R3=15 R1=5 R5=25 R6=30 Loop1 Loop 2 Loop 3 R4=20 CW Cw ACW R2=103 90 V 60 V 30 V Figure 1arrow_forwardi) For the circuit shown in Figure B16a, R1 Si V1 Ge 3k0 R2 i可 2kQ SIZ R3 4kO Figure B16a Calculate the following a) VI b) i c) 12arrow_forward
- bläi 6 Q3: Calculate voltages between points A,D (V1) and between points B,C (V2) before and after closing switch S A 15V D В Sa 12 C Before closing S V1= 6 v and V2= 9 v, After closing S V1= 9 v and V2= 12 v Before closing S V1= 9 v and V2= 12 v, After closing S V1= 12 v and V2= O 6 v none of the mentioned O Before closing S V1= 9 v and V2= 12 v, After closing S V1= 6 v and V2= 9 O V Before closing S V1= 0 v and V2= 3 v, After closing S V1= 6 v and V2= 3 wwarrow_forwardSolve the illustration below using kirchoff's law. Show your complete solution. Here is the clue: I1 = 4A, I2 = 3A and I3 = 1Aarrow_forwardCalculate the indicated currents and voltages. R1 R6 4 kN 12 kN R7 R8 R238 kN R4 24 k2 E 72 V 9 kN 3 kN R3 R5 R9 b 12kN 12 k2 6 kN O V7=19.626V, Is=7.344A, 15-2.8A O V7=19.636V, Is=7.364A, 15=3A O V7-19.646V, Is=7.364A, 15=2.7A O V7=19.656V, Is=7.354A, 15-2.9Aarrow_forward
- What is the the value of the currents I1, I2 and I3?arrow_forwardWhen applying Kirchhoff's Voltage Law on this circuit, how do you determine the sign of the 5 ohm resistor in the equation? Also, why does the 100 ohm resistor have polarity but the 5 ohm resistor does not?arrow_forwardCalculate the values of Voltages, Currents, and Resistances in the following Series- Parallel Circuit. Write and fill-in in the table the answers. V = 70 volts AM R1= 5 ohms ww R8= 6 ohms VT= V₁= V₂= V3= V4= V5= V6= V7= V8= V9= V10= V11= V12= V13= V14= V15= R9=5 ohms R2= 8 ohms ли M R7 = 12 ohms IT= I₁= I2= I3= I4= I5= 16= I7= I8= I9= I10= I11= I12= I13= I14= I15= R10=14 ohms M R3=5 ohms M RT= R₁= R₂= R3= R4= R5= R6= R7= R8= R9= R10= R11= R12= R13= R14= R15= M44 R11=7 ohms R12 10 ohms M R13-14 ohms M R14=14 ohms M R4 13 ohms M R15= 3 ohms ANL R6=13 ohms 44 M R5=7 ohmsarrow_forward
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