Mindtap Electrical, 4 Terms (24 Months) Printed Access Card For Herman's Delmar's Standard Textbook Of Electricity, 6th (mindtap Course List)
6th Edition
ISBN: 9781305634312
Author: Herman, Stephen L.
Publisher: Cengage Learning
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Chapter 9, Problem 13RQ
To determine
The equivalent Norton current for the given circuit.
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For the circuit shown in Figure B16a,
R1
Si
V1
3kQ
10 V
R2
2k0
Ge
R3
4 kQ
2V
Figure B16a
Calculate the following
a) VI
b) i
c) i2
in
2. Three resistors R1, R2 and R3 are connected in series parallel with R1 in series with parallel
combination of R2 and R3. The whole combination is connected across a 120V DC source. Resistors
R1, R2 and R3 takes 750 w, 250 W and 200 W, respectively. Calculate the resistance R2. Why are
street lights connected in parallel and not in series, explain.
Calculate the values of Voltages, Currents, and Resistances in the following Series-
Parallel Circuit. Write and fill-in in the table the answers.
V = 70 volts
AM
R1= 5 ohms
ww
R8= 6 ohms
VT=
V₁=
V₂=
V3=
V4=
V5=
V6=
V7=
V8=
V9=
V10=
V11=
V12=
V13=
V14=
V15=
R9=5 ohms
R2= 8 ohms
ли
M
R7 = 12 ohms
IT=
I₁=
I2=
I3=
I4=
I5=
16=
I7=
I8=
I9=
I10=
I11=
I12=
I13=
I14=
I15=
R10=14 ohms
M
R3=5 ohms
M
RT=
R₁=
R₂=
R3=
R4=
R5=
R6=
R7=
R8=
R9=
R10=
R11=
R12=
R13=
R14=
R15=
M44
R11=7 ohms
R12 10 ohms
M
R13-14 ohms
M
R14=14 ohms
M
R4 13 ohms
M
R15= 3 ohms
ANL
R6=13 ohms
44
M
R5=7 ohms
Chapter 9 Solutions
Mindtap Electrical, 4 Terms (24 Months) Printed Access Card For Herman's Delmar's Standard Textbook Of Electricity, 6th (mindtap Course List)
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- Power equation and power balance Consider the circuit with elements shown below -IA ↑ A t - 3V+ B + 2V - 2. The power associated with element B is 3. The power associated with element E is 2A 4. The total power absorbed in the circuit is IT-1A -IA For this circuit above, please answer the following questions by filling in the blanks below 1. The power associated with element A is W. W. W. IV. D W. 4V + E 5. Is the total power balanced in this circuit. Please answer with a yes or no 12 Aarrow_forwardWhen SW1 (or the switch) is closed, the current of I1 is 2A. Assume that SW1 is open, determine the Norton equivalent circuit as seen by RL. Note: Answer must not be in terms of the unknown voltage Vs, and unknown current Is.arrow_forward7. The equivalent total resistance in the circuit in Figure 1 is_ 2200 E=7V- 1000. 4700. 100. 3300 Figure 1 1. 558.90 2. 2160 3. 642.450 4. 82.892 8. The current through the 1002 resistor in the circuit in Figure 1 is_ 1. 84.45mA 2. 70mA 3. 14.89mA 4. 17.51mA 9. The power dissipated by the 3302 resistor in the circuit in Figure 1 isarrow_forward
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