Chapter 9, Problem 16RE

Explanation of Solution

Computation of (int)(a-b):

• It is given that the value assigned to a is “0.6” and the value assigned to b is “0.3”.
• Whenever there is a type conversion from a wide data to a narrow data, the loss of precision takes place.
• Since, int is narrower than the double, whenever a double is type casted to an int, then the loss of precision takes place...

Explanation of Solution

Computation of (int)(b-a):

• It is given that the value assigned to a is “0.6” and the value assigned to b is “0.3”.
• Whenever there is a type conversion from a wide data to a narrow data, the loss of precision takes place.
• Since, int is narrower than the double, whenever a double is type casted to an int, then the loss of precision takes place...

Explanation of Solution

Result of Double.compare(a, b):

• The method Double.compare(a, b) compares two test values for the order in which they must come.
• If the variable on the left side is less than the right side, then “-1” is returned.
• Otherwise, if the variable on the left side is greater than the right side, then “1” is returned...

Explanation of Solution

Result of Double.compare(b, a):

• The method Double.compare(b, a) compares two test values for the order in which they must come.
• If the variable on the left side is less than the right side, then “-1” is returned.
• Otherwise, if the variable on the left side is greater than the right side, then “1” is returned...