Explanation Given: Compression ratio ( r ) is 14 . Cut-off ratio ( r c ) is 1.2 . Pressure ratio ( r p ) is 1.5 . Initial temperature of the cycle ( T 1 ) is 20 ° C . Initial pressure of the cycle ( P 1 ) is 80 kPa . Calculation: Draw the P − v diagram of the cycle as in Figure (1). Refer Table A-2, “Ideal-gas specific heats of various common gases”, obtain the properties of the air. R = 0.287 kPa ⋅ m 3 / kg ⋅ K c v = 0.718 kJ / kg ⋅ K c p = 1.005 kJ / kg ⋅ K k = 1.4 Calculate the specific volume at state 1 ( v 1 ) . v 1 = R T 1 P 1 = ( 0.287 kPa ⋅ m 3 / kg ⋅ K ) ( 293 K ) 80 kPa = 1.051 m 3 / kg Calculate the specific volume at state 2 ( v 2 ) . v 2 = v 1 r = 1.051 m 3 / kg 14 = 0.07508 m 3 / kg Calculate the pressure at state 2 ( P 2 ) . P 2 = P 1 ( v 1 v 2 ) k = P 1 ( r ) k = ( 80 kPa ) ( 14 ) 1.4 − 1 = 3219 kPa Calculate the maximum pressure in the cycle ( P 3 ) . P 3 = P x = r p P 2 = ( 1.5 ) ( 3219 kPa ) = 4829 kPa Thus, the maximum gas pressure of the cycle is 4829 kPa . Calculate the temperature at state 2 ( T 2 ) . T 2 = T 1 ( v 1 v 2 ) k − 1 = T 1 ( r ) k − 1 = ( 293 K ) ( 14 ) 1.4 − 1 = 842 K Calculate the temperature at state x ( T x ) . T x = T 2 ( P 3 P 2 ) = ( 842 K ) ( 4829 kPa 3219 kPa ) = 1263 K Calculate the specific volume at state 3 ( v x )

5th Edition

ISBN: 9781259151323

Author: CENGEL

Publisher: MCGRAW HILL BOOK COMPANY

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Question

Chapter 9, Problem 48P

To determine

The thermal efficiency, amount of heat added, the maximum gas pressure and temperature of the cycle.

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Chapter 9, Problem 47P

Chapter 9, Problem 49P

Chapter 9 Solutions

EBK FUNDAMENTALS OF THERMAL-FLUID SCIEN

Ch. 9 - Prob. 1P Ch. 9 - What is the difference between air-standard...Ch. 9 - Prob. 3P Ch. 9 - Prob. 4P Ch. 9 - Prob. 5P Ch. 9 - Prob. 6P Ch. 9 - Prob. 7P Ch. 9 - Prob. 8P Ch. 9 - Prob. 9P Ch. 9 - Prob. 10P

Ch. 9 - Prob. 11P Ch. 9 - Prob. 12P Ch. 9 - Prob. 13P Ch. 9 - Prob. 15P Ch. 9 - Prob. 16P Ch. 9 - Prob. 17P Ch. 9 - Prob. 18P Ch. 9 - Prob. 19P Ch. 9 - Prob. 20P Ch. 9 - Prob. 21P Ch. 9 - Prob. 22P Ch. 9 - Prob. 23P Ch. 9 - Prob. 24P Ch. 9 - Prob. 25P Ch. 9 - Prob. 26P Ch. 9 - Prob. 27P Ch. 9 - Prob. 28P Ch. 9 - Prob. 29P Ch. 9 - Prob. 30P Ch. 9 - Prob. 31P Ch. 9 - Prob. 33P Ch. 9 - Prob. 34P Ch. 9 - Prob. 35P Ch. 9 - Prob. 36P Ch. 9 - Prob. 37P Ch. 9 - Prob. 38P Ch. 9 - Prob. 39P Ch. 9 - Prob. 40P Ch. 9 - Prob. 41P Ch. 9 - Prob. 42P Ch. 9 - Prob. 43P Ch. 9 - Prob. 44P Ch. 9 - Prob. 45P Ch. 9 - Prob. 46P Ch. 9 - Prob. 47P Ch. 9 - Prob. 48P Ch. 9 - Prob. 49P Ch. 9 - Prob. 50P Ch. 9 - Prob. 51P Ch. 9 - Prob. 52P Ch. 9 - Prob. 53P Ch. 9 - Prob. 55P Ch. 9 - Prob. 56P Ch. 9 - Prob. 57P Ch. 9 - Prob. 58P Ch. 9 - Prob. 60P Ch. 9 - Prob. 61P Ch. 9 - Prob. 62P Ch. 9 - Prob. 63P Ch. 9 - Prob. 64P Ch. 9 - Prob. 65P Ch. 9 - Prob. 66P Ch. 9 - Prob. 67P Ch. 9 - A simple Brayton cycle using air as the working...Ch. 9 - Prob. 70P Ch. 9 - Consider a simple Brayton cycle using air as the...Ch. 9 - Prob. 72P Ch. 9 - Prob. 73P Ch. 9 - Prob. 74P Ch. 9 - A gas-turbine power plant operates on a simple...Ch. 9 - Prob. 77P Ch. 9 - Prob. 78P Ch. 9 - Prob. 79P Ch. 9 - Prob. 80P Ch. 9 - Prob. 81P Ch. 9 - Prob. 82P Ch. 9 - Prob. 83P Ch. 9 - Prob. 84P Ch. 9 - Prob. 85P Ch. 9 - Prob. 86P Ch. 9 - Prob. 87P Ch. 9 - Prob. 89P Ch. 9 - Prob. 90P Ch. 9 - Prob. 91P Ch. 9 - Prob. 92P Ch. 9 - Prob. 93P Ch. 9 - Prob. 94P Ch. 9 - Prob. 95P Ch. 9 - Prob. 96P Ch. 9 - Prob. 97P Ch. 9 - Prob. 98P Ch. 9 - Prob. 99P Ch. 9 - Prob. 100P Ch. 9 - Prob. 101P Ch. 9 - Prob. 102P Ch. 9 - Prob. 103P Ch. 9 - Prob. 104P Ch. 9 - Prob. 105P Ch. 9 - Prob. 106P Ch. 9 - Prob. 107P Ch. 9 - Refrigerant-134a is used as the working fluid in a...Ch. 9 - Prob. 109P Ch. 9 - A simple ideal Rankine cycle with water as the...Ch. 9 - Prob. 111P Ch. 9 - Prob. 112P Ch. 9 - Prob. 113P Ch. 9 - Prob. 114P Ch. 9 - Prob. 115P Ch. 9 - Prob. 116P Ch. 9 - Prob. 117P Ch. 9 - Prob. 119P Ch. 9 - Prob. 120P Ch. 9 - Prob. 121P Ch. 9 - Prob. 122P Ch. 9 - Prob. 123P Ch. 9 - Prob. 124P Ch. 9 - Prob. 125P Ch. 9 - Prob. 127P Ch. 9 - Prob. 128P Ch. 9 - Prob. 129P Ch. 9 - Prob. 130P Ch. 9 - Prob. 131P Ch. 9 - Prob. 132P Ch. 9 - Why is the reversed Carnot cycle executed within...Ch. 9 - Prob. 134P Ch. 9 - Prob. 135P Ch. 9 - Refrigerant-134a enters the condenser of a...Ch. 9 - Prob. 137P Ch. 9 - Prob. 138P Ch. 9 - Prob. 139P Ch. 9 - Prob. 140P Ch. 9 - Prob. 141P Ch. 9 - Prob. 142P Ch. 9 - Prob. 143P Ch. 9 - Prob. 144P Ch. 9 - Prob. 145P Ch. 9 - Prob. 146P Ch. 9 - Prob. 148P Ch. 9 - Prob. 149P Ch. 9 - A commercial refrigerator with refrigerant-134a as...Ch. 9 - Prob. 151P Ch. 9 - Prob. 153P Ch. 9 - Prob. 154P Ch. 9 - Prob. 155P Ch. 9 - Prob. 156P Ch. 9 - Prob. 157P Ch. 9 - Prob. 158P Ch. 9 - Prob. 159P Ch. 9 - Refrigerant-134a enters the condenser of a...Ch. 9 - Prob. 161P Ch. 9 - Prob. 162P Ch. 9 - Prob. 164RQ Ch. 9 - Prob. 165RQ Ch. 9 - Prob. 166RQ Ch. 9 - Prob. 167RQ Ch. 9 - Prob. 168RQ Ch. 9 - A Brayton cycle with a pressure ratio of 12...Ch. 9 - Prob. 170RQ Ch. 9 - Prob. 171RQ Ch. 9 - Prob. 172RQ Ch. 9 - Prob. 173RQ Ch. 9 - Prob. 175RQ Ch. 9 - Prob. 176RQ Ch. 9 - Prob. 177RQ Ch. 9 - Prob. 178RQ Ch. 9 - Prob. 179RQ Ch. 9 - Prob. 180RQ Ch. 9 - Prob. 181RQ Ch. 9 - Prob. 182RQ Ch. 9 - Prob. 183RQ Ch. 9 - Prob. 184RQ Ch. 9 - Prob. 185RQ Ch. 9 - Prob. 186RQ Ch. 9 - A large refrigeration plant is to be maintained at...Ch. 9 - An air conditioner with refrigerant-134a as the...

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