Chapter 9, Problem 66A

Interpretation Introduction

(a)

Interpretation:

To balance given reaction.

${\left({\text{NH}}_{\text{4}}\right)}_{\text{2}}{\text{Cr}}_{\text{2}}{\text{O}}_7\left(s\right)\to {\text{Cr}}_{\text{2}}{\text{O}}_3\left(s\right)+{\text{N}}_2\left(g\right)+{\text{H}}_{\text{2}}\text{O}\left(g\right)$

Concept introduction:

Chemical equation is the symbolic description of a chemical reaction that products and reactants are indicating in terms of their chemical formula.

Answer to Problem 66A

The balance equation is as follows:

${\left({\text{NH}}_{\text{4}}\right)}_{\text{2}}{\text{Cr}}_{\text{2}}{\text{O}}_7\left(s\right)\to {\text{Cr}}_{\text{2}}{\text{O}}_3\left(s\right)+{\text{N}}_2\left(g\right)+4{\text{H}}_{\text{2}}\text{O}\left(g\right)$

Explanation of Solution

The given equation is as follows:

${\left({\text{NH}}_{\text{4}}\right)}_{\text{2}}{\text{Cr}}_{\text{2}}{\text{O}}_7\left(s\right)\to {\text{Cr}}_{\text{2}}{\text{O}}_3\left(s\right)+{\text{N}}_2\left(g\right)+{\text{H}}_{\text{2}}\text{O}\left(g\right)$

From the above reaction there are 8 hydrogen atoms in reactant side and in produce side there are 2 hydrogen atoms. There are 7 oxygen atoms in reactant side and in product side there are 4 oxygen atoms. To balance the equation adds 4 with water molecule. Now the balance equation is as follows:

${\left({\text{NH}}_{\text{4}}\right)}_{\text{2}}{\text{Cr}}_{\text{2}}{\text{O}}_7\left(s\right)\to {\text{Cr}}_{\text{2}}{\text{O}}_3\left(s\right)+{\text{N}}_2\left(g\right)+4{\text{H}}_{\text{2}}\text{O}\left(g\right)$

(b)

Interpretation Introduction

Interpretation:

To balance given reaction.

${\text{CO}}_2\left(g\right){\text{+H}}_{\text{2}}\text{O}\left(l\right)\to {\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_6\left(s\right)+{\text{O}}_2\left(g\right)$

Concept introduction:

Chemical equation is the symbolic description of a chemical reaction that products and reactants are indicating in terms of their chemical formula.

Answer to Problem 66A

The balance equation is as follows:

${\text{6CO}}_2\left(g\right){\text{+6H}}_{\text{2}}\text{O}\left(l\right)\to {\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_6\left(s\right)+6{\text{O}}_2\left(g\right)$

Explanation of Solution

From the above reaction there is only 1 carbon atom in the reactant side and in the produce side there are 6 carbon atoms. There are 3 oxygen atoms in the reactant side and in product side there are 8 oxygen atoms and hydrogen is deficient by 10 atoms in reactant side. To balance hydrogen and carbon atom add 6 with water molecule and another 6 with carbon dioxide molecule. There are 18 oxygen atoms in reactant side and 8 in the product side. Add 6 with oxygen molecule to balance oxygen. The balance equation is as follows:

${\text{6CO}}_2\left(g\right){\text{+6H}}_{\text{2}}\text{O}\left(l\right)\to {\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_6\left(s\right)+6{\text{O}}_2\left(g\right)$