Interpretation: Whether the given sample is nitrous oxide or not is to be explained.
Concept Introduction : According to the law of multiple proportions, the two elements form more compounds, than the ratios of the second element’s masses, which combined with the fixed first’s element mass will always be ratios of small whole numbers.
Answer to Problem 79A
The ratio of nitrogen to oxygen is 42:26 which is not equal to 7:4. So, the given sample is not nitrous oxide.
Explanation of Solution
It is given that the mass ratio of nitrogen to oxygen is 7:4. It means that 7 g of N will combine with 4 g of oxygen to form nitrous oxide.
The 68 g of the sample contains 42 g of nitrogen. The amount of oxygen is
Therefore, the ratio of nitrogen to oxygen is 42:26 which is not equal to 7:4. So, the given sample is not nitrous oxide.
Chapter 9 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY