Principles of Foundation Engineering, SI Edition
9th Edition
ISBN: 9781337672085
Author: Das, Braja M., SIVAKUGAN, Nagaratnam
Publisher: Cengage Learning
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Chapter 9, Problem 9.18P
To determine
Plot the expected additional settlement against the water table rise and discuss the rate of rise in the additional settlement with the water table rise.
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10.6
Estimate the increase in vertical stress at 0.5 m depth intervals, within the clay layer, below point A
(See figure below). The foundation exerts a uniform vertical stress of 120 kPa at ground level. Using
these values estimate the settlement due to the clay layer. (Hand in any graphs used)
5m
5m
2m
3m
Very Dense Sand
2m
1.5m
Clay E=3.5 MPa
2m
Bedrock
Soil profile
A
Plan of building
3m
Soil profile and plan for Question 4
3m
FA
Answer in three decimal places please
Chapter 9 Solutions
Principles of Foundation Engineering, SI Edition
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- please use 3 decimal places for the answerarrow_forwardA circular foundation 2m in diameter is shown in the figure below. A normallyconsolidated clay layer 5m thick is located below the foundation. Determine the consolidation settlement of the clay. 1- method 2:1 2- consolidation settlement Cc methodarrow_forwardAnswer in three decimal places pleasearrow_forward
- Ignoring the given Es-data and considering that the supporting soil is clean, normally consolidated sand with the following available data:arrow_forwardThe plan of a rectangular foundation shown in figure transmits a uniform contact pressure of 120 kN/m². Determine the vertical stress induced by this loading at point B under a depth of 5 m. (40 marks) 25.0- 15.0 6.0- 4.0 B•arrow_forwardAnswer the following question with all steps pleasearrow_forward
- A square column foundation with base of 1.35 m is shown in the figure. It carries an axial load of 488 kN and has its bottom resting on the ground water table located h1 = 1.4 m. below the ground surface. h2 = 0.9 m and h3 = 2.6 m. Compute the average increase in pressure in KPa in the clay layer below the center of foundation using the 2:1 method. |P Dry Sand h1 Wet Sand Clay h3 Soil Properties: Unit Weight of Dry Sand = 15.8 KN/m3 Saturated Unit Weight of Sand = 19.1 KN/m3 Saturated Unit Weight of Clay = 18.7 KN/m3 Compression Index = 0.264 Swell Index = 1/5Cc *arrow_forwardA footing of size 2m x 2m transferring a pressure of 200 kN/m2, is placed at depth of 1.5 m below the ground as shown in the figure (not drawn to the scale). The clay stratum is normally consolidated. The clay has specific gravity of 2.65 and compression index of 0.3. 200 kN/m? 1.5 m GWT Ya = 15 kN/m 18 kN/m elemiu 1 m Silty Sand Ysat = 10.5 m 1.5 m Clay Yat = 17 kN/m Dense Sand Consideration 2:1 (vertical to horizontal) method of load distribution and yw primary consolidation settlement (in mm, round off to two decimal places) of the clay stratum is 10kN/m, thearrow_forwardA circular foundation (D = 6 m) is built on a construction site where the soil profile is shown in Figure 5 below. The circular foundation applies a uniform pressure of 80 kPa to the surface of clay. The properties of the clay are: Specific gravity, G₁ Saturated unit weight at Compression index Ce Recompression index Cr Consolidation coefficient, c Over-consolidation ratio, OCR 10 m 6m Ø Clay Impervious rock Figure 5 2.6 20 kN/m³ 0.25 0.10 2.5 m²/year 1.2 (b) Calculate the stress increase at the center of the clay layer and 1) beneath the foundation center and 2) beneath the edge of the foundation; (c) Calculate the consolidation settlement beneath the center of the foundation due to the stress increase; (d) Determine the settlement at the center of the clay after 1 year of applying the pressure; (e) A 50 mm thick clay sample was taken from the site and consolidated in the oedometer, how long it will take for the clay to reach 90% consolidation?arrow_forward
- A footing of size 2m×2m transferring a pressure of 200 kN/m², is placed at a depth of 1.5 m below the ground as shown in the figure (not drawn to the scale). The clay stratum is normally consolidated. The clay has specific gravity of 2.65 and compression index of 0.3. 1.5m 1m 1.5 m 200 kN/m² Silty sand Clay Ya =15kN/m³ Y sat = 18kN/m³ Y sat = 17 kN/m³ GWT $0.5 m Dense sand Considering 2:1 (vertical to horizontal) method of load distribution and Y₁ = 10kN/m³, the primary consolida- tion settlement (in mm, round off to two decimal places) of the clay stratum isarrow_forward"please resolve the question but using method 2:1" note / the value load (q) is KN/m2 is stree not load method 2:1 q/(B+z) why the q * area b is circular "note in the picture solve the question but please solve in method 2:1"arrow_forward3decimal places on final answerarrow_forward
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