Chapter 9, Problem 9.49AP

Interpretation Introduction

Interpretation:

$Mass/volume$ percent concentration and molarity of glucose has to be identified.

Concept introduction:

In order to express the concentration, many units have been used. One among them is

$\text{Mass/volume}\text{percent}\text{concentration(m/v)\%}$ , defined as number of grams of solute dissolved in $\text{100mL}$ of solution.

$\text{(m/v)\% =}\frac{\text{Mass of solute(g)}}{Volume\text{of}\text{solution(mL)}}\text{×100}$

Molarity, defined as number of moles of solute divided by number of liters of solution.

Given by,

$Molarity(M)=\frac{Numberofmoles}{Litersofsolution}$