CHEM 212:STUDENT SOLUTION MANUAL
CHEM 212:STUDENT SOLUTION MANUAL
8th Edition
ISBN: 9781260304473
Author: SILBERBERG
Publisher: MCGRAW-HILL CUSTOM PUBLISHING
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Chapter 9, Problem 9.4P

(a)

Interpretation Introduction

Interpretation:

The more metallic element among Na and Cs is to be determined.

Concept introduction:

The metallic character is characterized by the tendency of metals to lose their outermost valence shell electrons. Greater the ease of electron removal, higher will be the electropositivity of the corresponding elements and vice versa.

The metallic character is characterized by the tendency of metals to lose their outermost valence shell electrons.

Down the group, the number of shells increases with the increase in the atomic number and the outermost valence electrons becomes farther from the nucleus and therefore can be removed easily. So the metallic character increases from top to bottom in a group.

Along the period, the electrons are added in the same outer shell and the effective nuclear charge increases due to which the electrons are attracted to the nucleus by strong electrostatic forces of attraction. Therefore the removal of the electron becomes difficult which results in the decrease of metallic character in a period.

(b)

Interpretation Introduction

Interpretation:

The more metallic element among Mg and Rb is to be determined.

Concept introduction:

The metallic character is characterized by the tendency of metals to lose their outermost valence shell electrons. Greater the ease of electron removal, higher will be the electropositivity of the corresponding elements and vice versa.

The metallic character is characterized by the tendency of metals to lose their outermost valence shell electrons.

Down the group, the number of shells increases with the increase in the atomic number and the outermost valence electrons becomes farther from the nucleus and therefore can be removed easily. So the metallic character increases from top to bottom in a group.

Along the period, the electrons are added in the same outer shell and the effective nuclear charge increases due to which the electrons are attracted to the nucleus by strong electrostatic forces of attraction. Therefore the removal of the electron becomes difficult which results in the decrease of metallic character in a period.

(c)

Interpretation Introduction

Interpretation:

The more metallic element among As and N is to be determined.

Concept introduction:

The metallic character is characterized by the tendency of metals to lose their outermost valence shell electrons. Greater the ease of electron removal, higher will be the electropositivity of the corresponding elements and vice versa.

The metallic character is characterized by the tendency of metals to lose their outermost valence shell electrons.

Down the group, the number of shells increases with the increase in the atomic number and the outermost valence electrons becomes farther from the nucleus and therefore can be removed easily. So the metallic character increases from top to bottom in a group.

Along the period, the electrons are added in the same outer shell and the effective nuclear charge increases due to which the electrons are attracted to the nucleus by strong electrostatic forces of attraction. Therefore the removal of the electron becomes difficult which results in the decrease of metallic character in a period.

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Chapter 9 Solutions

CHEM 212:STUDENT SOLUTION MANUAL

Ch. 9.5 - Prob. 9.5AFPCh. 9.5 - Prob. 9.5BFPCh. 9 - Prob. 9.1PCh. 9 - Prob. 9.2PCh. 9 - What is the relationship between the tendency of a...Ch. 9 - Prob. 9.4PCh. 9 - Prob. 9.5PCh. 9 - State the type of bonding—ionic, covalent, or...Ch. 9 - State the type of bonding—ionic, covalent, or...Ch. 9 - State the type of bonding—ionic, covalent, or...Ch. 9 - Prob. 9.9PCh. 9 - Prob. 9.10PCh. 9 - Prob. 9.11PCh. 9 - Prob. 9.12PCh. 9 - Prob. 9.13PCh. 9 - Give the group number and condensed electron...Ch. 9 - Give the group number and condensed electron...Ch. 9 - Prob. 9.16PCh. 9 - Prob. 9.17PCh. 9 - Prob. 9.18PCh. 9 - Prob. 9.19PCh. 9 - Prob. 9.20PCh. 9 - Prob. 9.21PCh. 9 - Prob. 9.22PCh. 9 - Prob. 9.23PCh. 9 - Prob. 9.24PCh. 9 - Prob. 9.25PCh. 9 - For each pair, choose the compound with the larger...Ch. 9 - Prob. 9.27PCh. 9 - For each pair, choose the compound with the...Ch. 9 - Prob. 9.29PCh. 9 - Use the following to calculate of NaCl: Compared...Ch. 9 - Use the following to calculate of MgF2: Compared...Ch. 9 - Prob. 9.32PCh. 9 - Born-Haber cycles were used to obtain the first...Ch. 9 - Prob. 9.34PCh. 9 - Prob. 9.35PCh. 9 - Prob. 9.36PCh. 9 - How does the energy of the bond between a given...Ch. 9 - When liquid benzene (C6H6) boils, does the gas...Ch. 9 - Prob. 9.39PCh. 9 - Prob. 9.40PCh. 9 - Prob. 9.41PCh. 9 - Prob. 9.42PCh. 9 - The text points out that, for similar types of...Ch. 9 - Why is there a discrepancy between an enthalpy of...Ch. 9 - Which of the following gases would you expect to...Ch. 9 - Which of the following gases would you expect to...Ch. 9 - Use bond energies to calculate the enthalpy of...Ch. 9 - Prob. 9.48PCh. 9 - Prob. 9.49PCh. 9 - Prob. 9.50PCh. 9 - Prob. 9.51PCh. 9 - What is the general relationship between IE1 and...Ch. 9 - Is the H—O bond in water nonpolar covalent, polar...Ch. 9 - Prob. 9.54PCh. 9 - How is the partial ionic character of a bond in a...Ch. 9 - Using the periodic table only, arrange the...Ch. 9 - Prob. 9.57PCh. 9 - Prob. 9.58PCh. 9 - Prob. 9.59PCh. 9 - Prob. 9.60PCh. 9 - Use Figure 9.21 to indicate the polarity of each...Ch. 9 - Prob. 9.62PCh. 9 - Prob. 9.63PCh. 9 - Prob. 9.64PCh. 9 - Prob. 9.65PCh. 9 - Prob. 9.66PCh. 9 - Prob. 9.67PCh. 9 - Prob. 9.68PCh. 9 - Prob. 9.69PCh. 9 - Prob. 9.70PCh. 9 - Prob. 9.71PCh. 9 - Geologists have a rule of thumb: when molten rock...Ch. 9 - Prob. 9.73PCh. 9 - Use Lewis electron-dot symbols to represent the...Ch. 9 - Prob. 9.75PCh. 9 - Prob. 9.76PCh. 9 - By using photons of specific wavelengths, chemists...Ch. 9 - Prob. 9.78PCh. 9 - Prob. 9.79PCh. 9 - Prob. 9.80PCh. 9 - Prob. 9.81PCh. 9 - Prob. 9.82PCh. 9 - Prob. 9.83PCh. 9 - Find the longest wavelengths of light that can...Ch. 9 - The work function (ϕ) of a metal is the minimum...Ch. 9 - Prob. 9.86PCh. 9 - Prob. 9.87PCh. 9 - Prob. 9.88PCh. 9 - In a future hydrogen-fuel economy, the cheapest...Ch. 9 - Prob. 9.90PCh. 9 - Prob. 9.91P
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