Chemistry: Atoms First V1
Chemistry: Atoms First V1
1st Edition
ISBN: 9781259383120
Author: Burdge
Publisher: McGraw Hill Custom
Question
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Chapter 9, Problem 9.68QP

(a)

Interpretation Introduction

Interpretation:

The masses of given solutes require to prepare 250mL of 0.100M for the respective given solutions should be determined.

Concept introduction:

Mole:

Mole of the solute in the solution is given by the multiplication of concentration and volume in liter.

Mole=concentration(M)×volume(L)

Mass:

The mass of solute present in the solution is given by multiplication of mole and molar mass of the solute.

Mass=Mole×Molarmass

(a)

Expert Solution
Check Mark

Answer to Problem 9.68QP

The mass of solutes require to prepare 250mL of 0.100M solution is 6.49gCsI

Explanation of Solution

Given,

Record the given data,

The molarities for solutions are 0.100M

The volumes for solution are 250mL

Determine the mole for given 250mL of 0.100M solutions

Mole=0.1000.250L=0.0250mole

Determine the mass of CsI required to prepare 250mL of 0.100MCsI solution.

From the standard data the molar mass of CsI is 259.81 g/mol

=0.0250molCsI×259.81 g CsI1molCsI=6.49gCsI

  • The calculated mole and molar mass of the solute is substituted in the above equation to give the required mass of solute to prepare 250mL of 0.100M solution.
  • Therefore, the require mass of CsI to prepare 250mL of 0.100MCsI solution is 6.49g.

(b)

Interpretation Introduction

Interpretation:

The masses of given solutes require to prepare 250mL of 0.100M for the respective given solutions should be determined.

Concept introduction:

Mole

Mole of the solute in the solution is given by the multiplication of concentration and volume in liter.

Mole=concentration(M)×volume(L)

Mass

The mass of solute present in the solution is given by multiplication of mole and molar mass of the solute.

Mass=Mole×Molarmass

(b)

Expert Solution
Check Mark

Answer to Problem 9.68QP

The mass of solute require to prepare 250mL of 0.100M solution is 2.452 g H2SO4.

Explanation of Solution

Given,

Record the given data,

The molarities of solutions are 0.100M

The volumes of solution are 250mL

Determine the mole of given 250mL of 0.100M solutions

Mole=0.1000.250L=0.0250mole

Determine the mass of H2SO4 require to prepare 250mL of 0.100M H2SO4 solutions.

From the standard data the molar mass of H2SO4 is 98.079 g/mol

=0.0250molH2SO4×98.079 g H2SO41molH2SO4=2.452gH2SO4

  • The calculated mole and molar mass of the solute is substituted in the above equation to give the require mass of solute to prepare 250mL of 0.100M solution.
  • The require mass of H2SO4 to prepare the 250mL of 0.100M solution is 2.452g.

(c)

Interpretation Introduction

Interpretation:

The masses of given solutes require to prepare 250mL of 0.100M for the respective given solutions should be determined.

Concept introduction:

Mole:

Mole of the solute in the solution is given by the multiplication of concentration and volume in liter.

Mole=concentration(M)×volume(L)

Mass:

The mass of solute present in the solution is given by multiplication of mole and molar mass of the solute.

Mass=Mole×Molarmass

(c)

Expert Solution
Check Mark

Answer to Problem 9.68QP

The mass of solutes require to prepare 250mL of 0.100M solution is 2.65 g Na2CO3.

Explanation of Solution

Given,

Record the given data,

The molarities of solutions are 0.100M

The volumes of solution are 250mL

Determine the mole of given 250mL of 0.100M solutions

Mole=0.1000.250L=0.0250mole

Determine the mass of Na2CO3 require to prepare 250mL of 0.100MNa2CO3 solution.

From the standard data the molar mass of Na2CO3 is 105.99 g

=0.0250molNa2CO3×105.99 g Na2CO31molNa2CO3=2.65gNa2CO3

  • The calculated mole and molar mass of the solute is substituted in the above equation to give the required mass of solute to prepare 250mL of 0.100M solution.
  • The require mass of Na2CO3 to prepare 250mL of 0.100MNa2CO3 solution is 2.65g.

(d)

Interpretation Introduction

Interpretation:

The masses of given solutes require to prepare 250mL of 0.100M for the respective given solutions should be determined.

Concept introduction:

Mole

Mole of the solute in the solution is given by the multiplication of concentration and volume in liter.

Mole=concentration(M)×volume(L)

Mass

The mass of solute present in the solution is given by multiplication of mole and molar mass of the solute.

Mass=Mole×Molarmass

(d)

Expert Solution
Check Mark

Answer to Problem 9.68QP

The mass of solutes require to prepare 250mL of 0.100M solution is 7.355 g K2Cr2O7

Explanation of Solution

Given,

Record the given data,

The molarities of solutions are 0.100M

The volumes of solution are 250mL

Determine the mole of given 250mL of 0.100M solutions

Mole=0.1000.250L=0.0250mole

Determine the mass of K2Cr2O7 require to prepare 250mL of 0.100M K2Cr2O7 given solutions.

From the standard data the molar mass of K2Cr2O7 is 294.185 g

=0.0250molK2Cr2O7×294.185 gK2Cr2O71molK2Cr2O7=7.355g K2Cr2O7

  • The calculated mole and molar mass of the solute is substituted in the above equation to give the require mass of solute to prepare 250mL of 0.100M solution.
  • The require mass of K2Cr2O7 to prepare 250mL of 0.100M K2Cr2O7 solution is 7.355g.

(e)

Interpretation Introduction

Interpretation:

The masses of given solutes require to prepare 250mL of 0.100M for the respective given solutions should be determined.

Concept introduction:

Mole:

Mole of the solute in the solution is given by the multiplication of concentration and volume in liter.

Mole=concentration(M)×volume(L)

Mass:

The mass of solute present in the solution is given by multiplication of mole and molar mass of the solute.

Mass=Mole×Molarmass

(e)

Expert Solution
Check Mark

Answer to Problem 9.68QP

The mass of solute require to prepare 250mL of 0.100M solution is 3.951 g KMnO4

Explanation of Solution

Given,

Record the given data,

The molarities of solutions are 0.100M

The volumes of solution are 250mL

Determine the mole of given 250mL of 0.100M solutions

Mole=0.1000.250L=0.0250mole

Determine the mass of KMnO4 require to prepare 250mL of 0.100M KMnO4 given solutions.

From the standard data the molar mass of KMnO4 is 158.034 g

=0.0250molKMnO4×158.034 gKMnO41molKMnO4=3.951g KMnO4

  • The calculated mole and molar mass of the solute is substituted in the above equation to give the require mass of solute to prepare 250mL of 0.100M solution.
  • The require mass of KMnO4 to prepare 250mL of 0.100MKMnO4 solution is 3.951g.

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Chapter 9 Solutions

Chemistry: Atoms First V1

Ch. 9.2 - Using Tables 9.2 and 9.3, identify a compound that...Ch. 9.2 - Prob. 9.3WECh. 9.2 - Prob. 3PPACh. 9.2 - Prob. 3PPBCh. 9.2 - Which diagram best represents the result when...Ch. 9.2 - Prob. 9.2.1SRCh. 9.2 - Prob. 9.2.2SRCh. 9.2 - Prob. 9.2.3SRCh. 9.2 - Prob. 9.2.4SRCh. 9.2 - Prob. 9.2.5SRCh. 9.3 - Prob. 9.4WECh. 9.3 - Prob. 4PPACh. 9.3 - Prob. 4PPBCh. 9.3 - Prob. 4PPCCh. 9.3 - Prob. 9.3.1SRCh. 9.3 - Prob. 9.3.2SRCh. 9.3 - Prob. 9.3.3SRCh. 9.3 - Prob. 9.3.4SRCh. 9.4 - Prob. 9.5WECh. 9.4 - Prob. 5PPACh. 9.4 - Prob. 5PPBCh. 9.4 - Write the balanced equation for the reaction...Ch. 9.4 - Prob. 9.6WECh. 9.4 - Using the activity series, predict which of the...Ch. 9.4 - Prob. 6PPBCh. 9.4 - Prob. 6PPCCh. 9.4 - Prob. 9.7WECh. 9.4 - Predict which of the following reactions will...Ch. 9.4 - Prob. 7PPBCh. 9.4 - Prob. 7PPCCh. 9.4 - Prob. 9.4.1SRCh. 9.4 - Prob. 9.4.2SRCh. 9.4 - Prob. 9.4.3SRCh. 9.4 - Prob. 9.4.4SRCh. 9.5 - Prob. 9.8WECh. 9.5 - Prob. 8PPACh. 9.5 - Prob. 8PPBCh. 9.5 - Prob. 8PPCCh. 9.5 - Prob. 9.9WECh. 9.5 - Prob. 9PPACh. 9.5 - Prob. 9PPBCh. 9.5 - Prob. 9PPCCh. 9.5 - Starting with a 2.0-M stock solution of...Ch. 9.5 - Starting with a 6.552-M stock solution of HNO3,...Ch. 9.5 - Five standard solutions of HBr are prepared by...Ch. 9.5 - Prob. 10PPCCh. 9.5 - Prob. 9.11WECh. 9.5 - Prob. 11PPACh. 9.5 - Prob. 11PPBCh. 9.5 - Prob. 11PPCCh. 9.5 - Prob. 9.12WECh. 9.5 - Calculate the hydronium ion concentration in a...Ch. 9.5 - Prob. 12PPBCh. 9.5 - Prob. 12PPCCh. 9.5 - Prob. 9.13WECh. 9.5 - Prob. 13PPACh. 9.5 - Prob. 13PPBCh. 9.5 - Prob. 13PPCCh. 9.5 - Prob. 9.5.1SRCh. 9.5 - Prob. 9.5.2SRCh. 9.5 - Prob. 9.5.3SRCh. 9.5 - Prob. 9.5.4SRCh. 9.5 - Prob. 9.5.5SRCh. 9.5 - Prob. 9.5.6SRCh. 9.6 - Prob. 9.14WECh. 9.6 - Prob. 14PPACh. 9.6 - Prob. 14PPBCh. 9.6 - Which diagram best represents the solution...Ch. 9.6 - Prob. 9.15WECh. 9.6 - Prob. 15PPACh. 9.6 - What volume (in mL) of a 0.2550 M NaOH solution...Ch. 9.6 - Prob. 15PPCCh. 9.6 - Prob. 9.16WECh. 9.6 - Prob. 16PPACh. 9.6 - Prob. 16PPBCh. 9.6 - Prob. 16PPCCh. 9.6 - Prob. 9.17WECh. 9.6 - Prob. 17PPACh. 9.6 - What is the molar mass of a diprotic acid if 30.5...Ch. 9.6 - Prob. 17PPCCh. 9.6 - Prob. 9.6.1SRCh. 9.6 - Prob. 9.6.2SRCh. 9.6 - Prob. 9.6.3SRCh. 9.6 - Prob. 9.6.4SRCh. 9 - Define solute, solvent, and solution by describing...Ch. 9 - What is the difference between a nonelectrolyte...Ch. 9 - Prob. 9.3QPCh. 9 - Prob. 9.4QPCh. 9 - Prob. 9.5QPCh. 9 - Prob. 9.6QPCh. 9 - You are given a water-soluble compound X. Describe...Ch. 9 - Prob. 9.8QPCh. 9 - Prob. 9.9QPCh. 9 - Prob. 9.10QPCh. 9 - Which of the following diagrams best represents...Ch. 9 - Prob. 9.12QPCh. 9 - Prob. 9.13QPCh. 9 - Describe hydration. What properties of water...Ch. 9 - What is the difference between a molecular...Ch. 9 - Prob. 9.16QPCh. 9 - Prob. 9.17QPCh. 9 - Prob. 9.18QPCh. 9 - Which reaction is represented by the net ionic...Ch. 9 - Prob. 9.20QPCh. 9 - Characterize the following compounds as soluble or...Ch. 9 - Write ionic and net ionic equations for the...Ch. 9 - Write ionic and net ionic equations for the...Ch. 9 - Prob. 9.24QPCh. 9 - Which of the following processes will likely...Ch. 9 - List the general properties of acids and bases.Ch. 9 - Prob. 9.27QPCh. 9 - Prob. 9.28QPCh. 9 - Prob. 9.29QPCh. 9 - What factors qualify a compound as a salt? Specify...Ch. 9 - Identify the following as a weak or strong acid or...Ch. 9 - Prob. 9.32QPCh. 9 - Prob. 9.33QPCh. 9 - Prob. 9.34QPCh. 9 - Prob. 9.35QPCh. 9 - Prob. 9.36QPCh. 9 - Prob. 9.37QPCh. 9 - Prob. 9.38QPCh. 9 - Describe how the activity series is organized, and...Ch. 9 - Prob. 9.40QPCh. 9 - Prob. 9.41QPCh. 9 - For the complete redox reactions represented here,...Ch. 9 - Prob. 9.43QPCh. 9 - Prob. 9.44QPCh. 9 - Prob. 9.45QPCh. 9 - Prob. 9.46QPCh. 9 - Give the oxidation numbers for the underlined...Ch. 9 - Give the oxidation numbers for the underlined...Ch. 9 - Prob. 9.49QPCh. 9 - Prob. 9.50QPCh. 9 - Prob. 9.51QPCh. 9 - Prob. 9.52QPCh. 9 - Prob. 9.53QPCh. 9 - Prob. 9.54QPCh. 9 - Prob. 9.55QPCh. 9 - Which of the following would result in the actual...Ch. 9 - Why cant we prepare the solution by first filling...Ch. 9 - Prob. 9.3VCCh. 9 - Prob. 9.4VCCh. 9 - Prob. 9.56QPCh. 9 - Prob. 9.57QPCh. 9 - Prob. 9.58QPCh. 9 - Prob. 9.59QPCh. 9 - Prob. 9.60QPCh. 9 - Prob. 9.61QPCh. 9 - Prob. 9.62QPCh. 9 - Prob. 9.63QPCh. 9 - Prob. 9.64QPCh. 9 - Prob. 9.65QPCh. 9 - Prob. 9.66QPCh. 9 - Prob. 9.67QPCh. 9 - Prob. 9.68QPCh. 9 - Prob. 9.69QPCh. 9 - Prob. 9.70QPCh. 9 - Prob. 9.71QPCh. 9 - Prob. 9.72QPCh. 9 - Prob. 9.73QPCh. 9 - Prob. 9.74QPCh. 9 - Prob. 9.75QPCh. 9 - Prob. 9.76QPCh. 9 - Prob. 9.77QPCh. 9 - Prob. 9.78QPCh. 9 - Prob. 9.79QPCh. 9 - Prob. 9.80QPCh. 9 - Prob. 9.81QPCh. 9 - Prob. 9.82QPCh. 9 - Complete the following table for a solution at...Ch. 9 - (a) What is the Na+ concentration in each of the...Ch. 9 - (a) Determine the chloride ion concentration in...Ch. 9 - Prob. 9.86QPCh. 9 - Determine the resulting nitrate ion concentration...Ch. 9 - Prob. 9.88QPCh. 9 - Absorbance values for five standard solutions of a...Ch. 9 - Which best represents the before-and-after...Ch. 9 - Prob. 9.91QPCh. 9 - Describe the basic steps involved in gravimetric...Ch. 9 - Explain why distilled water must be used in the...Ch. 9 - Describe the basic steps involved in an acid-base...Ch. 9 - Prob. 9.95QPCh. 9 - Prob. 9.96QPCh. 9 - Would the volume of a 0.10 M NaOH solution needed...Ch. 9 - Prob. 9.98QPCh. 9 - Prob. 9.99QPCh. 9 - The concentration of Cu2+ ions in the water (which...Ch. 9 - How many grams of NaCl are required to precipitate...Ch. 9 - Prob. 9.102QPCh. 9 - Prob. 9.103QPCh. 9 - Prob. 9.104QPCh. 9 - Prob. 9.105QPCh. 9 - Which of the following best represents the...Ch. 9 - Prob. 9.107QPCh. 9 - Prob. 9.108QPCh. 9 - Prob. 9.109QPCh. 9 - Prob. 9.110QPCh. 9 - Prob. 9.111QPCh. 9 - A 5.00 102 mL sample of 2.00 M HCl solution is...Ch. 9 - Calculate the volume of a 0.156 M CuSO4 solution...Ch. 9 - Prob. 9.114QPCh. 9 - Prob. 9.115QPCh. 9 - Prob. 9.116QPCh. 9 - Prob. 9.117QPCh. 9 - Prob. 9.118QPCh. 9 - Prob. 9.119QPCh. 9 - Prob. 9.120QPCh. 9 - Prob. 9.121QPCh. 9 - Prob. 9.122QPCh. 9 - Prob. 9.123QPCh. 9 - Prob. 9.124QPCh. 9 - Classify the following reactions according to the...Ch. 9 - Prob. 9.126QPCh. 9 - Prob. 9.127QPCh. 9 - Prob. 9.128QPCh. 9 - Prob. 9.129QPCh. 9 - Prob. 9.130QPCh. 9 - Prob. 9.131QPCh. 9 - Prob. 9.132QPCh. 9 - Prob. 9.133QPCh. 9 - Prob. 9.134QPCh. 9 - Prob. 9.135QPCh. 9 - Prob. 9.136QPCh. 9 - The concentration of lead ions (Pb2+) in a sample...Ch. 9 - Prob. 9.138QPCh. 9 - Prob. 9.139QPCh. 9 - Prob. 9.140QPCh. 9 - Prob. 9.141QPCh. 9 - Prob. 9.142QPCh. 9 - Prob. 9.143QPCh. 9 - The following are common household compounds: salt...Ch. 9 - Prob. 9.145QPCh. 9 - A 0.8870-g sample of a mixture of NaCl and KCl is...Ch. 9 - Prob. 9.147QPCh. 9 - Prob. 9.148QPCh. 9 - Acetylsalicylic acid (HC9H7O4) is a monoprotic...Ch. 9 - Prob. 9.150QPCh. 9 - Prob. 9.151QPCh. 9 - Prob. 9.152QPCh. 9 - Prob. 9.153QPCh. 9 - Prob. 9.154QPCh. 9 - Prob. 9.155QPCh. 9 - Prob. 9.156QPCh. 9 - Prob. 9.157QPCh. 9 - Prob. 9.158QPCh. 9 - Prob. 9.159QPCh. 9 - Prob. 9.160QPCh. 9 - Prob. 9.161QPCh. 9 - Prob. 9.162QPCh. 9 - Give a chemical explanation for each of the...Ch. 9 - Prob. 9.164QPCh. 9 - The following cycle of copper experiment is...Ch. 9 - Use the periodic table framework given here to...Ch. 9 - A 22.02-mL solution containing 1.615 g Mg(NO3)2 is...Ch. 9 - Because the acid-base and precipitation reactions...Ch. 9 - Prob. 9.1KSPCh. 9 - Prob. 9.2KSPCh. 9 - Prob. 9.3KSPCh. 9 - Prob. 9.4KSP
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