CHEMICAL PRINCIPLES (LL) W/ACCESS
CHEMICAL PRINCIPLES (LL) W/ACCESS
7th Edition
ISBN: 9781319421175
Author: ATKINS
Publisher: MAC HIGHER
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Chapter 9, Problem 9C.3BST

(a)

Interpretation Introduction

Interpretation:

The type of isomer represented by the pair [Co(N_CS)4(NH3)5]Cl2 and [Co(NCS_)4(NH3)5]Cl2 has to be given.

Concept Introduction:

Isomers:

The compounds with same molecular formula but differ in the arrangement of the atom are said to be isomers.

Linkage isomers:

Linkage isomerism occurs with ambidentate ligands that are capable of coordinating in more than one way.

Example:

SCN-/NCS-.  The only difference is the atoms bind to the central ion.  The ligand must have more than one donor atom but bind to ion in only one place.

(a)

Expert Solution
Check Mark

Answer to Problem 9C.3BST

The type of isomer represented by the pair [Co(N_CS)4(NH3)5]Cl2 and [Co(NCS_)4(NH3)5]Cl2 is linkage isomerism.

Explanation of Solution

In the isomer, [Co(N_CS)4(NH3)5]Cl2 the NCS ligand is bound to the metal atom through the nitrogen atom while in another complex [Co(NCS_)4(NH3)5]Cl2 the ligand is bound to the metal through the sulphur atom.

The type of isomer represented by the pair [Co(N_CS)4(NH3)5]Cl2 and [Co(NCS_)4(NH3)5]Cl2 is linkage isomerism.

(b)

Interpretation Introduction

Interpretation:

The type of isomer represented by the pair [CrCl(OH2)5]Cl2.H2O and [CrCl2(OH2)4]Cl.2H2O has to be given

Concept Introduction:

Hydrate Isomers:

Hydrate isomers results from replacement of a coordinated group by a solvent molecule in this case it is a water molecule.

(b)

Expert Solution
Check Mark

Answer to Problem 9C.3BST

The type of isomer represented by the pair [CrCl(OH2)5]Cl2.H2O and [CrCl2(OH2)4]Cl.2H2O is hydrate isomer.

Explanation of Solution

The given pair is [CrCl(OH2)5]Cl2.H2O and [CrCl2(OH2)4]Cl.2H2O.  In this pair of isomers the aqua ion which is bound with central atom is exchanged its place with the chloride ligand which present outside the nucleus.  Thus these isomers are hydrate isomers.

The type of isomer represented by the pair [CrCl(OH2)5]Cl2.H2O and [CrCl2(OH2)4]Cl.2H2O is hydrate isomer.

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Students have asked these similar questions
What chemical tests would you use to distinguish between (a) [Co(NH3)5 Br] [SO4] and [Co(NH3) 5 (SO4)] Br, and (b) [CrCl₂ (OH₂)4] Cl-2H₂O and [CrCl(OH₂)5]Cl₂ H₂O? (c) What is the relationship between these pairs of compounds? (d) What isomers are possible for [CrCl₂ (OH₂)4]?
Determine the oxidation state of the coordinated metal atom in each of the following compounds:(a) K[Co(NH3)2(CN)4];           (b) Os(CO)5;             (c) Na[Co(OH2)3(OH)3].
Are [Co(NH3)4Cl2]Cl and [Co(NH3)4Cl]Cl2 isomers of each other? If so, what type of isomers are they?

Chapter 9 Solutions

CHEMICAL PRINCIPLES (LL) W/ACCESS

Ch. 9 - Prob. 9A.9ECh. 9 - Prob. 9A.10ECh. 9 - Prob. 9A.11ECh. 9 - Prob. 9A.12ECh. 9 - Prob. 9A.13ECh. 9 - Prob. 9A.14ECh. 9 - Prob. 9B.1ASTCh. 9 - Prob. 9B.1BSTCh. 9 - Prob. 9B.2ASTCh. 9 - Prob. 9B.2BSTCh. 9 - Prob. 9B.1ECh. 9 - Prob. 9B.2ECh. 9 - Prob. 9B.3ECh. 9 - Prob. 9B.4ECh. 9 - Prob. 9B.5ECh. 9 - Prob. 9B.6ECh. 9 - Prob. 9B.7ECh. 9 - Prob. 9B.8ECh. 9 - Prob. 9B.9ECh. 9 - Prob. 9B.10ECh. 9 - Prob. 9B.11ECh. 9 - Prob. 9B.12ECh. 9 - Prob. 9B.13ECh. 9 - Prob. 9B.14ECh. 9 - Prob. 9B.15ECh. 9 - Prob. 9B.16ECh. 9 - Prob. 9C.1ASTCh. 9 - Prob. 9C.1BSTCh. 9 - Prob. 9C.2ASTCh. 9 - Prob. 9C.2BSTCh. 9 - Prob. 9C.3ASTCh. 9 - Prob. 9C.3BSTCh. 9 - Prob. 9C.4ASTCh. 9 - Prob. 9C.4BSTCh. 9 - Prob. 9C.1ECh. 9 - Prob. 9C.2ECh. 9 - Prob. 9C.3ECh. 9 - Prob. 9C.4ECh. 9 - Prob. 9C.5ECh. 9 - Prob. 9C.6ECh. 9 - Prob. 9C.7ECh. 9 - Prob. 9C.8ECh. 9 - Prob. 9C.9ECh. 9 - Prob. 9C.10ECh. 9 - Prob. 9C.11ECh. 9 - Prob. 9C.12ECh. 9 - Prob. 9C.13ECh. 9 - Prob. 9C.14ECh. 9 - Prob. 9C.15ECh. 9 - Prob. 9C.16ECh. 9 - Prob. 9C.17ECh. 9 - Prob. 9C.18ECh. 9 - Prob. 9C.19ECh. 9 - Prob. 9C.20ECh. 9 - Prob. 9D.1ASTCh. 9 - Prob. 9D.1BSTCh. 9 - Prob. 9D.2ASTCh. 9 - Prob. 9D.2BSTCh. 9 - Prob. 9D.3ASTCh. 9 - Prob. 9D.3BSTCh. 9 - Prob. 9D.4ASTCh. 9 - Prob. 9D.4BSTCh. 9 - Prob. 9D.1ECh. 9 - Prob. 9D.2ECh. 9 - Prob. 9D.3ECh. 9 - Prob. 9D.4ECh. 9 - Prob. 9D.5ECh. 9 - Prob. 9D.6ECh. 9 - Prob. 9D.7ECh. 9 - Prob. 9D.8ECh. 9 - Prob. 9D.9ECh. 9 - Prob. 9D.10ECh. 9 - Prob. 9D.11ECh. 9 - Prob. 9D.12ECh. 9 - Prob. 9D.13ECh. 9 - Prob. 9D.14ECh. 9 - Prob. 9D.15ECh. 9 - Prob. 9D.16ECh. 9 - Prob. 9D.17ECh. 9 - Prob. 9D.18ECh. 9 - Prob. 9D.19ECh. 9 - Prob. 9D.20ECh. 9 - Prob. 9D.21ECh. 9 - Prob. 9D.22ECh. 9 - Prob. 9D.23ECh. 9 - Prob. 9D.24ECh. 9 - Prob. 9D.25ECh. 9 - Prob. 9D.26ECh. 9 - Prob. 9D.27ECh. 9 - Prob. 9D.28ECh. 9 - Prob. 9D.29ECh. 9 - Prob. 9D.30ECh. 9 - Prob. 9D.31ECh. 9 - Prob. 9D.32ECh. 9 - Prob. 9D.33ECh. 9 - Prob. 9D.34ECh. 9 - Prob. 9.1ECh. 9 - Prob. 9.2ECh. 9 - Prob. 9.3ECh. 9 - Prob. 9.4ECh. 9 - Prob. 9.5ECh. 9 - Prob. 9.6ECh. 9 - Prob. 9.7ECh. 9 - Prob. 9.8ECh. 9 - Prob. 9.9ECh. 9 - Prob. 9.10ECh. 9 - Prob. 9.11ECh. 9 - Prob. 9.12ECh. 9 - Prob. 9.13ECh. 9 - Prob. 9.14ECh. 9 - Prob. 9.15ECh. 9 - Prob. 9.16ECh. 9 - Prob. 9.17ECh. 9 - Prob. 9.18ECh. 9 - Prob. 9.19ECh. 9 - Prob. 9.20ECh. 9 - Prob. 9.21ECh. 9 - Prob. 9.23ECh. 9 - Prob. 9.25E
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