Explanation Given: The equation of circle, x 2 + y 2 + 12 x + 2 y − 27 = 0 . Formula used: The standard form of the equation of circle with the center at ( h , k ) and radius r , ( x − h ) 2 + ( y − k ) 2 = r 2 . Calculation: The equation of circle is written as, x 2 + y 2 + 12 x + 2 y − 27 = 0 x 2 + 12 x + y 2 + 2 y = 27 x 2 + 2 ( 6 ) x + y 2 + 2 ( 1 ) y = 27 Add 36 and 1 both side of the equation x 2 + 2 ( 6 ) x + 36 + y 2 + 2 ( 1

8th Edition

ISBN: 9780134188515

Author: Crawford

Publisher: YUZU

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Question

Chapter 9.1, Problem 40E

To determine

To calculate: The standard form of the equation, x2+y2+12x+2y−27=0 and find center and radius of each circle.

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Chapter 9.1, Problem 39E

Chapter 9.1, Problem 41E

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Chapter 9 Solutions

EBK INTERMEDIATE ALGEBRA

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Knowledge Booster

The standard form of the equation, x 2 + y 2 + 12 x + 2 y − 27 = 0 and find center and radius of each circle .

Solution Summary: The author compares the given equation with the standard form of the equation of circle, c.

To calculate: The standard form of the equation, x2+y2+12x+2y−27=0 and find center and radius of each circle.

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Chapter 9 Solutions