Chapter 9.1, Problem 5MI

Summary Introduction

To fill:

The correct terms in the given blanks

Introduction:

A cell grows until it reaches its size limit, then it either stops growing or divides. Most cells undergo division. Most cells are less than 100µm in diameter. The ratio of surface area to volume is the key factor that limits the size of a cell. By remaining small cells have a higher ratio of surface area to volume and they can sustain themselves more easily.

Answer to Problem 5MI

As a cell grows larger, its volume increases more rapidly than its surface area, thus surface area- to- volume ratio decreases.

Explanation of Solution

Surface area of a cell refers to the area covered by the plasma membrane through which the nutrients and wastes must pass through. Volume refers to the space taken up by the contents of the cell. To calculate the surface area of the cube, we have to multiply length times width times number of sides. To calculate the volume, we have to multiply length times width times height.

Suppose the length of a cell is 1cm.

  ${\text{Surface area=1×1×6=6cm}}^{\text{2}}$

  ${\text{Volume of cube=1×1×1=6cm}}^{\text{3}}$

  $\text{Ratio of surface area to volume=6:1}$

Now if the cell grows larger to 2cm per side,

  $\text{Length of the cell=2cm}$

  ${\text{Surface area=2×2×6=24cm}}^{\text{2}}$

  ${\text{Volume of cube=2×2×2=8cm}}^{\text{3}}$

  $\text{Ratio of surface area to volume=24:8=3:1}$

The new ratio of 3:1 is less than 6:1. Therefore we can say that as the cell grows larger the ratio of surface area to volume decreases.

As the cell grows larger the surface area and volume, both increase. The volume increases more rapidly than the surface area and so the cell has difficulty in transporting nutrients and waste products. But the overall ratio of surface area to volume decreases with increase in size of the cell.