Algebra: Structure And Method, Book 1

(REV)00 Edition

ISBN: 9780395977224

Author: Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Publisher: McDougal Littell

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Question

Chapter 9.3, Problem 21P

To determine

To find: The number of each kind of coins.

Expert Solution & Answer

Answer to Problem 21P

The number of nickel is 4 , dimes is 14 and quarter is 12 .

Explanation of Solution

Given:

The total coins is 30 .

The worth of all the coins is $4.60 .

The dimes are two more than quarters.

Calculation:

Consider the number of dimes is d , quarters is q and nickel is n . Then the total coins is,

n+d+q=30n=30−(d+q)

Consider the dimes are two more than nickel that is,

d=2+q

Consider the total value of the coins is,

0.05n+0.1d+0.25q=4.605n+10d+25q=460n+2d+5q=92

Solve further as,

(30−(d+q))+2d+5q=92d+4q=62

Then,

2+q+4q=625q=60q=12

Then, the number of dimes is,

d=2+12=14

Then, the number of nickel is,

n=30−(14+12)=4

Thus, the number of nickel is 4 , dimes is 14 and quarter is 12 .

Chapter 9.3, Problem 20P

Chapter 9.3, Problem 22P

Chapter 9 Solutions

Algebra: Structure And Method, Book 1

Ch. 9.1 - Prob. 1OE Ch. 9.1 - Prob. 2OE Ch. 9.1 - Prob. 3OE Ch. 9.1 - Prob. 4OE Ch. 9.1 - Prob. 5OE Ch. 9.1 - Prob. 6OE Ch. 9.1 - Prob. 7OE Ch. 9.1 - Prob. 8OE Ch. 9.1 - Prob. 9OE Ch. 9.1 - Prob. 1WE

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