Algebra: Structure And Method, Book 1
Algebra: Structure And Method, Book 1
(REV)00 Edition
ISBN: 9780395977224
Author: Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher: McDougal Littell
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Question
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Chapter 9.7, Problem 14P
To determine

To solve: the system of equations in two variables.

Expert Solution & Answer
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Answer to Problem 14P

The age of Marion is 12 years old now and age of Les is 16 years old now .

Explanation of Solution

Given information:

Marion was 23 as old as Les was. Now she is 34 as old as he is .

Formula used:

Age problem.

Step1. The problem asks for the Bob’s age and Claire’s age now.

Step2. Let b = the Marion’s age .

Let c = the Les‘s age .

Step3. Use the facts of the problem to write two equations.

Step4. Solve the equations.

Calculation:

Consider ,

Let b = the Marion’s age .

Let c = the Les’s age .

    AgeFour year ago
    Marionb4
    Lesc4

According to the equation,

  =b4=23(c4)=3(b4)=2(c4)=3b12=2c8=3b122c+8=0=3b2c4=0                (i)

Also,

  =b=34c                             (ii)

Substituting equation (i) in (ii)

  =3b2c4=0=3(34c)2c4=0=94c2c4=0=9c8c164=0=c16=0=c=16

Putting value of c in equation (i) we get,

  =b=34(16)=b=3(4)=b=12

Hence, the age of Marion is 12 years old now and age of Les is 16 years old now .

Chapter 9 Solutions

Algebra: Structure And Method, Book 1

Ch. 9.1 - Prob. 2WECh. 9.1 - Prob. 3WECh. 9.1 - Prob. 4WECh. 9.1 - Prob. 5WECh. 9.1 - Prob. 6WECh. 9.1 - Prob. 7WECh. 9.1 - Prob. 8WECh. 9.1 - Prob. 9WECh. 9.1 - Prob. 10WECh. 9.1 - Prob. 11WECh. 9.1 - Prob. 12WECh. 9.1 - Prob. 13WECh. 9.1 - Prob. 14WECh. 9.1 - Prob. 15WECh. 9.1 - Prob. 16WECh. 9.1 - Prob. 17WECh. 9.1 - Prob. 18WECh. 9.1 - Prob. 19WECh. 9.1 - Prob. 20WECh. 9.1 - Prob. 21WECh. 9.1 - Prob. 22WECh. 9.1 - Prob. 23WECh. 9.1 - Prob. 24WECh. 9.1 - Prob. 1MRECh. 9.1 - Prob. 2MRECh. 9.1 - Prob. 3MRECh. 9.1 - Prob. 4MRECh. 9.1 - Prob. 5MRECh. 9.1 - Prob. 6MRECh. 9.1 - Prob. 1CECh. 9.1 - Prob. 2CECh. 9.1 - Prob. 3CECh. 9.1 - Prob. 4CECh. 9.2 - Prob. 1OECh. 9.2 - Prob. 2OECh. 9.2 - Prob. 3OECh. 9.2 - Prob. 4OECh. 9.2 - Prob. 5OECh. 9.2 - Prob. 6OECh. 9.2 - Prob. 7OECh. 9.2 - Prob. 8OECh. 9.2 - Prob. 9OECh. 9.2 - Prob. 10OECh. 9.2 - Prob. 11OECh. 9.2 - Prob. 12OECh. 9.2 - Prob. 1WECh. 9.2 - Prob. 2WECh. 9.2 - Prob. 3WECh. 9.2 - Prob. 4WECh. 9.2 - Prob. 5WECh. 9.2 - Prob. 6WECh. 9.2 - 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Prob. 5PCh. 9.6 - Prob. 6PCh. 9.6 - Prob. 7PCh. 9.6 - Prob. 8PCh. 9.6 - Prob. 9PCh. 9.6 - Prob. 10PCh. 9.6 - Prob. 11PCh. 9.6 - Prob. 12PCh. 9.6 - Prob. 13PCh. 9.6 - Prob. 14PCh. 9.6 - Prob. 15PCh. 9.6 - Prob. 16PCh. 9.6 - Prob. 17PCh. 9.6 - Prob. 18PCh. 9.6 - Prob. 19PCh. 9.6 - Prob. 20PCh. 9.6 - Prob. 21PCh. 9.6 - Prob. 22PCh. 9.6 - Prob. 23PCh. 9.6 - Prob. 1MRECh. 9.6 - Prob. 2MRECh. 9.6 - Prob. 3MRECh. 9.6 - Prob. 4MRECh. 9.6 - Prob. 5MRECh. 9.6 - Prob. 6MRECh. 9.6 - Prob. 7MRECh. 9.6 - Prob. 8MRECh. 9.6 - Prob. 9MRECh. 9.7 - Prob. 1OECh. 9.7 - Prob. 2OECh. 9.7 - Prob. 3OECh. 9.7 - Prob. 4OECh. 9.7 - Prob. 5OECh. 9.7 - Prob. 6OECh. 9.7 - Prob. 7OECh. 9.7 - Prob. 8OECh. 9.7 - Prob. 9OECh. 9.7 - Prob. 10OECh. 9.7 - Prob. 11OECh. 9.7 - Prob. 12OECh. 9.7 - Prob. 13OECh. 9.7 - Prob. 14OECh. 9.7 - Prob. 15OECh. 9.7 - Prob. 16OECh. 9.7 - Prob. 17OECh. 9.7 - Prob. 18OECh. 9.7 - Prob. 19OECh. 9.7 - Prob. 20OECh. 9.7 - Prob. 21OECh. 9.7 - Prob. 22OECh. 9.7 - Prob. 1PCh. 9.7 - Prob. 2PCh. 9.7 - 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