Introduction To General, Organic, And Biochemistry
12th Edition
ISBN: 9781337571357
Author: Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher: Cengage Learning
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Chapter 9.5, Problem 9.6QC
Problem 9-6
A radioactive isotope in a 9.0-mL vial has an intensity of 300. mCi. A patient is required to take 50. mCi intravenously. How much liquid should be used for the injection?
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Chapter 9 Solutions
Introduction To General, Organic, And Biochemistry
Ch. 9.3 - Problem 9-1 Iodine-139 is a beta emitter. Write an...Ch. 9.3 - Problem 9-2 Thorium-223 is an alpha emitter. Write...Ch. 9.3 - Prob. 9.3QCCh. 9.3 - Problem 9-4 Thallium-201, a radioisotope used to...Ch. 9.4 - Problem 9-5 Barium-122 has a half-life of 2...Ch. 9.5 - Problem 9-6 A radioactive isotope in a 9.0-mL vial...Ch. 9.5 - Prob. 9.7QCCh. 9 - What is the relationship between frequency and...Ch. 9 - How does energy relate to frequency and...Ch. 9 - Prob. 3P
Ch. 9 - 9-10 Microwaves are a form of electromagnetic...Ch. 9 - Prob. 5PCh. 9 - Prob. 6PCh. 9 - Prob. 7PCh. 9 - 9-14 Write the symbol for a nucleus with the...Ch. 9 - Prob. 9PCh. 9 - Prob. 10PCh. 9 - Prob. 11PCh. 9 - Prob. 12PCh. 9 - Prob. 13PCh. 9 - Prob. 14PCh. 9 - Prob. 15PCh. 9 - Prob. 16PCh. 9 - Prob. 17PCh. 9 - Prob. 18PCh. 9 - Prob. 19PCh. 9 - Prob. 20PCh. 9 - Prob. 21PCh. 9 - Prob. 22PCh. 9 - Prob. 23PCh. 9 - Prob. 24PCh. 9 - Prob. 25PCh. 9 - Prob. 26PCh. 9 - Prob. 27PCh. 9 - Prob. 28PCh. 9 - Prob. 29PCh. 9 - Prob. 30PCh. 9 - Prob. 31PCh. 9 - Prob. 32PCh. 9 - 9-39 If you work in a lab containing radioisotopes...Ch. 9 - Prob. 34PCh. 9 - Prob. 35PCh. 9 - Prob. 36PCh. 9 - Prob. 37PCh. 9 - Prob. 38PCh. 9 - Prob. 39PCh. 9 - Prob. 40PCh. 9 - Prob. 41PCh. 9 - Prob. 42PCh. 9 - Prob. 43PCh. 9 - Prob. 44PCh. 9 - Prob. 45PCh. 9 - Prob. 46PCh. 9 - Prob. 47PCh. 9 - Prob. 48PCh. 9 - Prob. 49PCh. 9 - Prob. 50PCh. 9 - Prob. 51PCh. 9 - Prob. 52PCh. 9 - Prob. 53PCh. 9 - Prob. 54PCh. 9 - Prob. 55PCh. 9 - Prob. 56PCh. 9 - Prob. 57PCh. 9 - Prob. 58PCh. 9 - Prob. 59PCh. 9 - Prob. 60PCh. 9 - Prob. 61PCh. 9 - Prob. 62PCh. 9 - Prob. 63PCh. 9 - Prob. 64PCh. 9 - Prob. 65PCh. 9 - Prob. 66PCh. 9 - Prob. 67PCh. 9 - Prob. 68PCh. 9 - Prob. 69PCh. 9 - Prob. 70PCh. 9 - Prob. 71PCh. 9 - Prob. 72PCh. 9 - Prob. 73PCh. 9 - Prob. 74PCh. 9 - Prob. 75PCh. 9 - Prob. 76PCh. 9 - Prob. 77PCh. 9 - Prob. 78PCh. 9 - Prob. 79PCh. 9 - 9-86 is effective in prostate cancer therapy when...Ch. 9 - Prob. 81PCh. 9 - Prob. 82PCh. 9 - Prob. 83PCh. 9 - Prob. 84PCh. 9 - Prob. 85PCh. 9 - Prob. 86PCh. 9 - Prob. 87PCh. 9 - Prob. 88PCh. 9 - Prob. 89PCh. 9 - Prob. 90PCh. 9 - Prob. 91PCh. 9 - Prob. 92PCh. 9 - Prob. 93PCh. 9 - Prob. 94PCh. 9 - Prob. 95P
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Problem 9-2 Thorium-223 is an alpha emitter. Write an equation for this nuclear reaction and identify the product formed.arrow_forwardProblem 9-1 Iodine-139 is a beta emitter. Write an equation for this nuclear reaction and identify the product formed.arrow_forwardPotassium-44 decays by beta emission with a half-life of 22 minutes. A 125mg sample of the isotope is allowed to decay for 88 minutes. What mass of K-44 in mg remains in the sample after the 88 minutes? a. 7.81mg b. 15.6mg c. 31.5mg d. 62.5mg e. no correct responsearrow_forward
- Please only type answer 1. If the HVL of lead for 60Co is 0.49 inches, what thickness of lead would be required to reduce 600 mrem/h of radiation to 2 mrem/h? [Note: A rule of thumb is that it takes 2 inches of lead to reduce the dose rate by a factor of 10.] 2. If the HVL of concrete for 60Co = is 2.6 inches, what thickness of concrete would be required to reduce 600 mrem/h of radiation to 2 mrem/h? 3. Calculate the activity remaining in a vial that originally contained 5 mCi of 32P three weeks ago. None of the sample has been extracted. [Note: 3 weeks equals 7 days; t0.5 for 32P = 14.3 days.]arrow_forwardProblem 9-5 Barium-122 has a half-life of 2 minutes. Suppose you obtained a sample weighing 10.0 g and it takes 10 minutes to set up an experiment in which the barium-122 is to be used. How many grams of barium-122 will remain at the point when you begin the experiment?arrow_forwardProblem 9-4 Thallium-201, a radioisotope used to evaluate heart function in exercise stress tests, decays by electron capture and gamma emission. Write an equation for this nuclear decay and identify the product.arrow_forward
- A worker receives a dose of 8.5 units of radiation at a distance of 5.0m from the source. What will the dose be at a distance of 5m? (Estimated Answer 100)arrow_forwardA sealed flask contains saturated sodium iodide with excess solid at the bottom of the flask. If a sample of radioactively labelled NaI(s) is added to the system, the most likely observation after 24 hours will be Select one: A. neither the NaI(s) nor the only the NaI(aq) will register as radioactive B. both the NaI(s) and the NaI(aq) will register as radioactive C. only the NaI(aq) will register as radioactive D. only the NaI(s) will register as radioactive Use the following information to answer the next question. Crystals of magnesium phosphate and glucose, C6H12O6(s), were dissolved together in a beaker of distilled water. All the entities that will be present when the two compounds are added to water are Select one: A. Mg2+(s), PO43-(s), C6H12O6(aq), H2O(l) B. Mg2+(aq), PO43-(aq), C6H12O6(s), H2O(l) C. Mg3(PO4)2(aq), C6H12O6(s), H2O(l) D. Mg3(PO4)2(s), C6H12O6(aq), H2O(l)arrow_forwardHow did you get this? k===0.693t1/20.69315 hrs0.0462 hrs−1k=0.693t1/2=0.69315 hrs=0.0462 hrs 0.693 a 102.0 nanogram(ng) sample of sodium-24 was stored in a lead-lined cabinet for 2.5 days How much sodium-24 remained? The half-life os sodium -24 is 15 hours _________ ng sodium -24 remain check_circle Expert Answer thumb_up thumb_down Step 1 Radioactive decay is a first order reaction. Conversion of days into hours: 1 day2.5 days===24 hrs2.5×2460 hrs1 day=24 hrs2.5 days=2.5×24=60 hrs Calculation of k: k===0.693t1/20.69315 hrs0.0462 hrs−1k=0.693t1/2=0.69315 hrs=0.0462 hrs-1 Step 2 Radioactive decay is a first order reaction, therefore: [A]=[Ao] e−kt[A]=[Ao] e-kt where [A] is the final amount remained at time t, [Ao] is the initial amount. Putting values: [A]====102.0 ng×e−0.0462 hrs−1×60 hrs102.0 ng×e−2.772102.0 ng×0.062546.38 ng[A]=102.0 ng×e-0.0462 hrs-1×60 hrs=102.0 ng×e-2.772=102.0 ng×0.06254=6.38 ng Thus 6.38 ng of sodium-24 remained.arrow_forward
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