Concept explainers
To find: the probability that the hand drawn is a full house.
Answer to Problem 46E
Explanation of Solution
Given:
A full house consists of three of one kind and two of another.
Let E be the event that the hand drawn is a full house.
Total choices for the number that shows on the first three cards is =
Total number of choices of suits for those three cards is =
Total choices for the number that shows on the remaining two cards is =
Total number of choices of suits for those two cards is =
So,
Total number of cards is 52. So, total number of ways to choose 5 cards out of 52 cards is:
Thus, the probability of that the hand drawn is a full house is:
Chapter 9 Solutions
EBK PRECALCULUS W/LIMITS
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning