BuyFind

Single Variable Calculus: Concepts...

4th Edition
James Stewart
Publisher: Cengage Learning
ISBN: 9781337687805
BuyFind

Single Variable Calculus: Concepts...

4th Edition
James Stewart
Publisher: Cengage Learning
ISBN: 9781337687805

Solutions

Chapter B, Problem 37E
To determine

To calculate: To find the equation of circle that satisfies the given condition

Expert Solution

Answer to Problem 37E

Equation of circle is x2+y26x+2y15=0

Explanation of Solution

Given information: Centre (3,1) and radius 5

Formula Used:

Equation of circle with center as (h,k) and radius r is given as

  (xh)2+(yk)2=r2

Calculation:

Given the below details:

  Center,(h,k)=(3,1)Radius,r=5

Equation of circle is given as

  (xh)2+(yk)2=r2

Substituting the values in above equation:

  (x3)2+(y(1))2=52(x3)2+(y+1)2=52x2+96x+y2+1+2y=25x2+y26x+2y+(9+125)=0x2+y26x+2y15=0

Conclusion:

Hence, equation of circle is x2+y26x+2y15=0

Have a homework question?

Subscribe to bartleby learn! Ask subject matter experts 30 homework questions each month. Plus, you’ll have access to millions of step-by-step textbook answers!