Applications
43–46. Horizontal oscillators The equation of motion for a spring-block system that lies on a horizontal surface (see figure) is the same as the equation of motion for a vertically suspended system. As before, m is the mass of the block, k is the spring constant, c is the damping coefficient (perhaps due to friction as the block slides on the surface), and Fext is an external force. We let x(t) be the position of the block at time t, where x increases to the right and x = 0 is the position of the block at which the spring is neither stretched nor compressed.
a. Find the position of the block in the following situations.
b. Graph the position function.
c. Describe the type of motion you observe.
45. m = 4 kg, c = 4 kg/s, k = 17 N/m,
Fext = 148 sin t, x(0) = 0, x′(0) = 0
Want to see the full answer?
Check out a sample textbook solutionChapter D2 Solutions
Calculus: Early Transcendentals, 2nd Edition
- Force Tyler and his cousin Kelly have attached a rope to the branch of a tree and tied a board to the other end to form a swing. Tyler sits on the board while his cousin pushes him through an angle of 25.5 and holds him there. If Tyler weighs 95.5 pounds, find the magnitude of the force Kelly must push with horizontally to keep Tyler in static equilibrium. See Figure 1. Figure 1arrow_forwardForce Tyler and his cousin Kelly have attached a rope to the branch of a tree and tied a board to the other end to form a swing. Tyler sits on the board while his cousin pushes him through an angle of 25.5 and holds him there. If Tyler weighs 95.5 pounds, find the magnitude of the force Kelly must push with horizontally to keep Tyler in static equilibrium. See Figure 13.arrow_forward
- Trigonometry (MindTap Course List)TrigonometryISBN:9781305652224Author:Charles P. McKeague, Mark D. TurnerPublisher:Cengage Learning