Concept explainers
(a)
To find: the number of points would expect a roll to add to the score.
(a)
Answer to Problem 34RE
2.5 points
Explanation of Solution
Each of the results has a 1/6 chance of being observed (1, 2, 3, 4, and 5).
Given that all the rolls were not 6's, we would predict a roll to a score of around 6 so that apply something to current score.
(b)
To find: a roll will be required to deduct from the score the amount of points.
(b)
Answer to Problem 34RE
0
Explanation of Solution
If there were to roll a 6, it would have scored 0, regardless of previous rolls. Therefore, it would expect a roll to remove from the score the entire current score, leading to a score of 0.
(c)
To find: the score would another roll break ever on the basis of given in part (a) and (b).
(c)
Answer to Problem 34RE
0
Explanation of Solution
For the first time on roll 6, can hope to get a 6 (since the chance of observing 6 is 1/6). To get a positive score and the predicted score, roll 5 times; if roll 5 times, it would be 1 + 2 + 3 + 4 + 5= 15 = 15. So, another roll will even break at this score, as the next possible result would be a 6 that results in a score of 0.
(d)
To Explain: the strategy for this result suggests.
(d)
Explanation of Solution
The approach of this outcome implies that stop when the score hits 15 points.
Chapter PIV Solutions
Stats: Modeling the World Nasta Edition Grades 9-12
Additional Math Textbook Solutions
Statistics: The Art and Science of Learning from Data (4th Edition)
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Introductory Statistics
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