   Chapter PL, Problem 1P ### Algebra and Trigonometry (MindTap ...

4th Edition
James Stewart + 2 others
ISBN: 9781305071742

#### Solutions

Chapter
Section ### Algebra and Trigonometry (MindTap ...

4th Edition
James Stewart + 2 others
ISBN: 9781305071742
Textbook Problem
1 views

# PROBLEMSDistance, Time, and Speed An old car has to travel a 2-mile route, uphill and down .Because it is so old, the car can climb the first mile-the ascent-no faster than an average speed of 15mi/h. How fast does the car to travel the second mile-on the descent it can go faster, of course-to achieve an average speed of 30 mi/h for the trip?

To determine

To find:

An old car travel has to travel a 2-mie route, uphill and down. The car can climb the first mile-the ascent-no faster than an average speed of 15 mi/h. How fast does the car have to travel the second mile on the descent it can go faster to achieve an average speed of 30 mi/h for the trip.

Solution:

It can’t go fast enough.

Explanation

Calculation:

The speed of the car when the man drives from home to work=50mi/h.

The speed of the car when the man drives from work to home=30mi/h.

Averagespeed=TotaldistancetraveledTotaltimeelapsed.

d means distance between house and the work place.

The total distance travelled by the man is 2d miles.

t1= The time taken by the man when he travel from home to work.

That is,

50=dt1

t1=d50hours

t2= The time taken by the man when he travel from work to home.

30=dt2

t2=d30hours

Then the total time taken for the journey is t1+t2=d50+d30.

=80d1500

=4d75hours

To find the average speed of the man during his entire trip.

Averagespeed=TotaldistancetraveledTotaltimeelapsed.

=2d4d75

=752mi/h

=37.5mi/h

It can’t go fast enough. Because it exceeds the average speed limit.

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## Chapter PL Solutions 