Concept explainers
To find minimum, lower quartile, upper quartile, median and maximum.
Answer to Problem 10.6EP
Minimum=2.58
Lower quartile, m1=2.59
Upper quartile, m2=2.71
Median, m=2.65
Maximum=2.83
Explanation of Solution
Given information:
The price of gases at seven stations
$2.63, $2.59, $2.70, $2.58, $2.83, $2.65, $2.71.
Calculation:
Ordered data set
2.58, 2.59, 2.63, 2.65, 2.70, 2.71, 2.83
Using box-and-whisker plot compare above set of data
Minimum=2.58
Lower quartile
2.58, 2.59, 2.63
Median for lower quartile
m1=2.59
Upper quartile
2.70, 2.71, 2.83
Median for upper quartile
m2=2.71
Median
n number of frequencies
n=7
n is odd
Then middle term is median
Median=2.65
Maximum=2.83
Chapter SH Solutions
Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)
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