Chapter SH, Problem 7.3EP

To determine

To expression area of triangle as a monomial.

Answer to Problem 7.3EP

  $A=5a^6{b}^5{c}^5$

Explanation of Solution

Given information:

Triangle is right angle triangle

  

Base is $2a^2{b}^3{c}^4$

Perpendicular is ${\text{5a}}^4{\text{b}}^2\text{c}$

Formula used:

Area of Right Angle Triangle, $A=\frac{1}{2}\times base\times perpendicular$

Calculation:

Using formula to calculate area of triangle

  $A=\frac{1}{2}\times (2a^2{b}^3{c}^4)\times (5a^4{b}^{2}c)$

On solving,

  $=(a^2{b}^3{c}^4)\times (5a^4{b}^{2}c)$

Removing parentheses by combining like term

  $=5\times a^2\times a^4\times b^3\times b^2\times c^4\times c$

On solving,

  $A=5a^6{b}^5{c}^5$