Assignment #4 Solution (2)
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Therapeu�cs Engineering CHE 380/580 Assignment #
4
Due 2
/
6
/24, 11 am on BBlearn Name: 1.
You generate a pep�de with the sequence KSLWPWKY. You purify it with HPLC and want to determine how much you made. A�er dissolving it in 1 mL of pure water, you read it on a spectrophotometer in a 0.3 cm diameter cuvete. You get the following reading
(shown as trace A on this graph). a.
What is the pep�de concentra�on?
The ex�nc�on coefficient is 12660 cm
-1 M-
1 (from two tryptophans and one tyrosine). Using beer’s law and the cuvete size of 0.3 cm and es�ma�ng the absorp�on at 280 nm of 1.8, we can calculate 1.8= (12660)*(0.3)* C C= 4.7 x10
-4 M or 0.47 mM. b.
If the ideal yield was 1 mg, what was the efficiency of the reac�on?
Calcula�ng a molecular weight of 1107 g/mol, using 1 mL of water, we calculate we have a total of 0.47 uMols of pep�de, which comes to 0.52 mg, amoun�ng to a 52% yield.
2. From the example ESI
-
MS spectrum, can you
iden�fy at least one
peak tha
t corresponds to an exact mass of:
(Show your reasoning)
a)
1201.77 Da?
401.596 is a triple charged product peak (410.596
-
1)*3= 1201.77
b)
1206.09
Da?
626.0353 is a double charge product with two sodium adducts (626.0353
- 22.99) *2 = 1206.09
3. What is the difference between Disassocia�on constant (Kd) and Effec�ve Dose 50 (EC50)?
Kd describes the concentra�on of the ligand required for binding, while EC50 is the concentra�on required for a physiological effect
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Related Questions
urses/
2951
2. A linear standard curve of KMnO4 is prepared from a set of standard solutions by plotting
absorbance (y) vs. concentration (x). Use Logger Pro (as described in the Data Analysis for this
experiment), or Google Sheets/Excel, to plot this standard curve using the data in Table 1. Help with
spreadsheets [PDF]
Table 1: Data for the standard curve of KMnO4
Absorbance Concentration (M)
0.372
6.00 x 10-4
0.298
0.223
0.149
0.0744
After plotting the standard curve, enter its slope below (not the equation of the line). Report your
answer to 3 significant figures. If your answer ends in one or more zeros, use scientific notation.
Slope =
4.80 x 10-4
3.60 x 10-4
2.40 x 10-4
1.20 x 10-4
M-1
M
3. Suppose that an unknown sample is analyzed spectrophotometrically at the same wavelength that
was used for the standard curve and the absorbance was found to be 0.186. Use the standard curve
to find the concentration of the unknown. Hint:
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Internal standard. A solution containing 3.47 mM X (analyte) and 1.72 mM S (standard) gave peak areas of 3 473 and 10 222, respectively, in a chromatographic analysis. Then 1.00 mL of 8.47 mM S was added to 5.00 mL of unknown X, and the mixed solution was diluted to 10.0 mL. This solution gave peak areas of 5 428 and 4 431 for X and S, respectively. (a) Find the response factor for X relative to S in Equation 5-9. (b) Find [S] (mM) in the 10.0 mL of mixed solution. (c) Find [X] (mM) in the 10.0 mL of mixed solution.(d) Find [X] in the original unknown.
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Internal standard. A mixture containing 12.8 mM analyte (X) and 44.4 mM standard (S) gave chromatographic peak areas of 306 for X and 511 for S. A second solution containing an unknown quantity of X plus 55.5 mM S had peak areas of 251 for X and 563 for S. Find [X] in the second solution.
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Provide the names for the following (3 points each):
a) Blank 1
b) Blank 2
c) Blank 3
Last saved 8:04:23 PM
Questions Filter (8)
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| | |
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НО
CH3 H
|||
дн
receipt-6935.20227....book
Н
w
0.
ACEC $20 Week 13....pdf
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Find the Mass Spec
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MS: m/z=148 (M,100%),149 (11%)
IR (liquid film): 3077‐2835 (multitude of weak peaks) 1640(m),1611(m),1511(s),1301(m),1247(s),1176(s),1038(s),922(m),914(m) and 810(m)cm^-1
There are no absorptions in the 3100-‐4000cm^-1 region of the spectrum. (m=medium absorption, s=strong absorption).
Choose (circle) the best structure for estragole (W) from the four possible structures (1-4)shown below. Explain briefly how you eliminated each of the incorrect structures for W.
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CPU/RAM
ProctorU e Proctor
e Proctoru
o.com/collab/ui/session/join/43918c0bf9cb421ca7b98b0075f5f239
Firefox Ex
SPECTROSCOPY
1. If the concentration of solute in a solution is high, the Absorbance will
be high or low and why?
2. Was the spectroscopy experiment qualitative or quantitative analysis?
3. If we have 12M HCI and we need 3 L of 1M HCI, how much 12 M
should we use?
4. What does Molarity mean?
5. When must safety goggles be worn?
6. If you make a mistake recording data, what must you do?
spec hw.pptx (2/3)
..%
An
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Questions 1 and 2
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Bradford assay was used to determine bovine serum albumin (BSA) concentrations. The method works by binding
Coomassie Brilliant Blue dye to protein standards and unknown, leading to a shift in the absorbance maximum of the dye.
A stock solution of BSA is available (10 mg/ml) from which the protein standards were prepared. Bradford reagent, 290 ul,
was pipetted into a transparent 96-well microplate. 10 ul of the protein dilution was added followed by mixing in the wells.
After 5 min of incubation at room temperature, the plate was read in spectrum mode with the absorbance spectrometer of
the microplate reader. The spectrum of the dye not bound to protein was also determined. Create a standard curve or
regression equation that related the protein concentration and absorbance. An unknown BSA sample was prepared the
same way as the standard and the OD was 0.35. determine the original concentration of the protein solution.
The measurements can be seen below.
0.0625
Protein
Concentration…
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3) 3-Methylbutyramide
100
relative intensity
.8888
relative abundance
.88
CHINO
101
298 888
mass charge (m2)
CaH₁N
60
4) n-Butylamine
100
60
CHOCHOCHS
R98 8
mass charge (m/z)
MW=101.15
MW-73.13
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please explain which compound this is
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What is 4d?
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A3
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A 10.00-g sample containing an analyte was
transferred to a 250-mL volumetric flask and
diluted to volume. When a 10.00-mL aliquot of the
resulting solution was diluted to 25.00 mL it was
found to give a signal of o.235 (arbitrary units). A
second 10.00-mL aliquot was spiked with 10.00 mL
of a 1.00- ppm standard solution of the analyte and
diluted to 25.0o mL. The signal for the spiked
sample was found to be o.502. Calculate the weight
percent of analyte in the original sample.
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Wgat is the name is Na
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A 10.00 g sample containing an analyte was transferred to a 250 mL volumetric flask and diluted to volume. When a 10.00 mL aliquot of the resulting solution was diluted to 25.00 mL it was found to give a signal of 0.235 (arbitrary units). A second 10.00 mL aliquot was spiked with 10.00 mL of a 1.00 ppm standard solution of the analyte and diluted to 25.00 mL. The signal for the spiked sample was found to be 0.502.
Calculate the weight percent of analyte in the original sample.
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100
MASS SPECTRUM
80
60
40
20
0.0
10
20
30
40
50
60
m/z
NIST Chemistry WebBook (https://webbook.nist.gov/chemistry)
1. What is the M'?
2. What is the m/z of the base peak?
3. Does it contain chlorine? Explain your answer.
Rel. Intensity
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Using the lab instructions and data table with data, please help me complete part 1 and 2 of my lab worksheet
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Provide a structure of the fragment in the mass spec producing the peak at 139 m/z and a structure for the fragment that was lost.
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How do I find the [FeSCN]^2+ value?
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0.200 M
0.00200 M
Test Tube No.
[FESCN2*1std (M)
Absorbance
Fe(NO3)3 (mL)
KSCN (mL)
17.98
1.97
0.815
5 (Standard)
Edit
Edit
Edit
NG 1
Info
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1
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An analyst injects a 2µL sample of unknown into a GC-TCD and observed the following:Peak # 1 Rt = 2.011 min Response = 41334 unitsFollowing the above injection, the analyst mixes 1mL of unknown with10 µL of pure toluene, and after injecting 2 µL sample observes the following:Peak # 1 Rt = 2.010 min Response = 41117 unitsPeak # 2 Rt = 3.502 min Response = 25667 unitsFollowing this injection, the analyst mixes 1mL of unknown with10 µL of pure hexane, and after injecting 2 µL sample observes the following:Peak # 1 Rt = 2.021 min Response = 48335 unitsBased on the above data, determine the identity and concentration (in ppm) of the unknown solution NOTE: density of toluene = 0.87g/mL, density of hexane = 0.66g/mL
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A GC separation was conducted on a sample containing a
14)
pesticide analyte, Pymetozine. This sample was treated with an
internal standard of chlorobenzene, giving a concentration of 15.0
ppm. A 1.0 uL injection onto the GC gave an FID response of 1012
for chlorobenzene and 3411 for Pymetozine. A 1.0 uL standard
solution of 30.0 ppm chlorobenzene with 15.0 ppm of Pymetozine
was injected giving response of 899 and 2791 respectively. What is
the concentration of Pymetozine in the sample?
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A3
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The concentration of purified OXA-M290 is tested with a BCA assay. Serial dilutions of a bovine serum albumin (BSA) stock solution are prepared, then pipetted into a 96-well plate; each dilution of the BSA standard is tested in triplicate. Then, bicinchoninic acid and Cu2+ ions are added to all of the wells of the plate. After incubating the plate for 1 hour, a microplate reader is used to measure the absorbance of all of the wells in the plate at 560 nm. This generates the following data:
BSA conc. (μg/mL), Replicate 1 Absorbance, Replicate 2 Absorbance, Replicate 3 Absorbance
40, 1.360, 1.403, 1.481
20, 0.750, 0.745, 0.810
10, 0.380, 0.344, 0.398
5, 0.198, 0.160, 0.183
2.5, 0.090, 0.100, 0.085
1.25, 0.038, 0.043, 0.051
0.625, 0.024, 0.028, 0.019
Prepare a calibration curve using these data. You can use Excel, R, SPSS or an equivalent graphing software.
In this graph, plot absorbance (y-axis) against the concentration of the protein standard (x-axis). Calculate and plot…
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Related Questions
- urses/ 2951 2. A linear standard curve of KMnO4 is prepared from a set of standard solutions by plotting absorbance (y) vs. concentration (x). Use Logger Pro (as described in the Data Analysis for this experiment), or Google Sheets/Excel, to plot this standard curve using the data in Table 1. Help with spreadsheets [PDF] Table 1: Data for the standard curve of KMnO4 Absorbance Concentration (M) 0.372 6.00 x 10-4 0.298 0.223 0.149 0.0744 After plotting the standard curve, enter its slope below (not the equation of the line). Report your answer to 3 significant figures. If your answer ends in one or more zeros, use scientific notation. Slope = 4.80 x 10-4 3.60 x 10-4 2.40 x 10-4 1.20 x 10-4 M-1 M 3. Suppose that an unknown sample is analyzed spectrophotometrically at the same wavelength that was used for the standard curve and the absorbance was found to be 0.186. Use the standard curve to find the concentration of the unknown. Hint:arrow_forwardInternal standard. A solution containing 3.47 mM X (analyte) and 1.72 mM S (standard) gave peak areas of 3 473 and 10 222, respectively, in a chromatographic analysis. Then 1.00 mL of 8.47 mM S was added to 5.00 mL of unknown X, and the mixed solution was diluted to 10.0 mL. This solution gave peak areas of 5 428 and 4 431 for X and S, respectively. (a) Find the response factor for X relative to S in Equation 5-9. (b) Find [S] (mM) in the 10.0 mL of mixed solution. (c) Find [X] (mM) in the 10.0 mL of mixed solution.(d) Find [X] in the original unknown.arrow_forwardInternal standard. A mixture containing 12.8 mM analyte (X) and 44.4 mM standard (S) gave chromatographic peak areas of 306 for X and 511 for S. A second solution containing an unknown quantity of X plus 55.5 mM S had peak areas of 251 for X and 563 for S. Find [X] in the second solution.arrow_forward
- Provide the names for the following (3 points each): a) Blank 1 b) Blank 2 c) Blank 3 Last saved 8:04:23 PM Questions Filter (8) aming1.png н-с-с-с-н | | | CI H НО CH3 H ||| дн receipt-6935.20227....book Н w 0. ACEC $20 Week 13....pdfarrow_forwardFind the Mass Specarrow_forwardMS: m/z=148 (M,100%),149 (11%) IR (liquid film): 3077‐2835 (multitude of weak peaks) 1640(m),1611(m),1511(s),1301(m),1247(s),1176(s),1038(s),922(m),914(m) and 810(m)cm^-1 There are no absorptions in the 3100-‐4000cm^-1 region of the spectrum. (m=medium absorption, s=strong absorption). Choose (circle) the best structure for estragole (W) from the four possible structures (1-4)shown below. Explain briefly how you eliminated each of the incorrect structures for W.arrow_forward
- CPU/RAM ProctorU e Proctor e Proctoru o.com/collab/ui/session/join/43918c0bf9cb421ca7b98b0075f5f239 Firefox Ex SPECTROSCOPY 1. If the concentration of solute in a solution is high, the Absorbance will be high or low and why? 2. Was the spectroscopy experiment qualitative or quantitative analysis? 3. If we have 12M HCI and we need 3 L of 1M HCI, how much 12 M should we use? 4. What does Molarity mean? 5. When must safety goggles be worn? 6. If you make a mistake recording data, what must you do? spec hw.pptx (2/3) ..% Anarrow_forwardQuestions 1 and 2arrow_forwardBradford assay was used to determine bovine serum albumin (BSA) concentrations. The method works by binding Coomassie Brilliant Blue dye to protein standards and unknown, leading to a shift in the absorbance maximum of the dye. A stock solution of BSA is available (10 mg/ml) from which the protein standards were prepared. Bradford reagent, 290 ul, was pipetted into a transparent 96-well microplate. 10 ul of the protein dilution was added followed by mixing in the wells. After 5 min of incubation at room temperature, the plate was read in spectrum mode with the absorbance spectrometer of the microplate reader. The spectrum of the dye not bound to protein was also determined. Create a standard curve or regression equation that related the protein concentration and absorbance. An unknown BSA sample was prepared the same way as the standard and the OD was 0.35. determine the original concentration of the protein solution. The measurements can be seen below. 0.0625 Protein Concentration…arrow_forward
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Recommended textbooks for you
- Principles of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning