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CHEM-302

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Chemistry

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Dec 6, 2023

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Lab Report Experiment 11 – Spectrophotometric determination of %Co in purple Co compound Chemical reaction: Strong heating Co(III)(NH 3 ) x Cl y (s) Co(II)Cl 2 + NH 3 (g) + N 2 (g) + NH 4 Cl (purple Co compd.) Note: In this reaction, the oxidation number of Co in the purple compound was converted from +3 to +2 after heating. Data Table: 1. Calibration curve – absorbance vs molarities of Co(II) standards Table 1: Beer’s law data C stock = 0.09998M (from EDTA titration) max = 511 nm (from spectrum) Solution # V s (mL) V t (mL) Dilution factor (DF) C f = C s x DF Absorbance 1 5 25 1/5 0.01998 0.0883 2 10 25 2/5 0.03998 0.1877 3 15 25 3/5 0.05998 0.2867 4 20 25 4/5 0.07998 0.3856 Stock 25 25 5/5 Stock 0.4846 Sample calculation of the concentration of diluted solution: Solution #1: 1/5*0.09998=0.019996M Figure 1: Calibration graph (Beer’s law graph): Abs. vs. concentration (attach the graph)
Fitting equation: 4.9525x-0.0105 Slope of the line: 4.9525 olar extinction coefficient (   including the units) = 4.9525 2. Determine % Co in the Purple Co Compound Table 2: %Co in purple Co compound # of Trials 1 2 3 Mass of purple Co weighed (g) 0.3905 0.3960 0.3910 Absorbance of Co solution 0.3258 0.3062 0.3156 Molar conc. of Co from calibration curve 0.06790 0.06394 0.06572 mol of Co = MV (v = 25 mL) 0.001697 0.001598 0.001643 Mass (g) of Co in purple Co = mole x AM 1.000*10^-1 9.420&10^-2 9.682*10^-2 % Co in purple Co compound 25.61% 24.15% 24.76% Average % and sd 24.84% 0.733 Sample calculation of % Co: 0.3905*0.025L= 0.001697 0.001697*58.93= 1.000*10^-1 1.000*10^-1/0.3905= 25.61% (25.61%+24.15%+24.76%)/3= 24.84% ( 25.61 24.84 ) 2 +( 24.15 24.84 ) 2 +( 24.76 24.84 ) 2 3 1 = 0.733
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