CM1011 Exp6_Titration_Fa23
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Name ______________________________________ Section __________________ Experiment 6 Acid-Base Titration CM1001 Fall 2023 1 Acid-Base Titration In your text (Chang and Goldsby 7
th
Ed): 4.3
Acid-Base Reactions 4.6
Solution Stoichiometry Extra reading: 17.3
A closer look at Acid-Base Titrations 17.4
Acid-Base Indicators Background: Titration
is a method of quantitative analysis in which a solution of known concentration (the standard solution or titrant
) is gradually added from a burette to a measured quantity of unknown solution (
analyte
) until the reaction is complete (
equivalence
point
). The equivalence point is also called the stoichiometric point, as it is where the number of moles of titrant is in the stoichiometric ratio (from the coefficients in the balanced reaction equation) with the number of moles of the analyte present in the sample. The titrant is typically delivered from a burette, which accurately measures volume. If the analyte is a solid, it must be weighed, then dissolved in the solvent. A small amount of an indicator is added (if applicable), and then the solution of the analyte is titrated. Since the titration will determine the number of moles of analyte, typically the mass of the solid and the number of moles of solid is used to determine the molar mass. If the analyte is a solution, a known volume must be used, a small amount of indicator is added (if applicable), and then the solution is titrated. Since the titration will determine the number of moles of solute in the analyte, typically the volume of the solution and the number of moles of the solute are used to determine the concentration. In acid-base titration, an acid-base neutralization reaction occurs between the titrant, typically a strong base, and the analyte, usually an acid with unknown concentration or molar mass. When the number of moles of the added strong base is at the stoichiometric ratio with the number of moles of the acid, the reaction is complete and the equivalence point is reached. An instrument or a visual change must be used to indicate the endpoint of the titration (when one stops adding titrant). In acid-base titration, an indicator, in very small amount,
is
added to
the analyte solution to indicate the endpoint. An indicator is a compound that have different colors when it is in an acid solution or base solution. When the indicator changes color, the amount of the base added is just slightly more than the amount needed to reach the equivalence point. At this point the reaction is just slightly beyond completion, so the titration should end (thus, the endpoint). If the endpoint is carefully identified, it is very close to the equivalence point. Overview of the Procedure: You will be given a NaOH solution, whose concentration is only known approximately (about 0.1 M). The first step, in Part I, is to standardize
the NaOH, i.e. titrate the NaOH solution against a well-characterized acid, to determine the concentration of the NaOH to 4 significant figures. Once this determination is made, your calculated molarity of NaOH is used in the calculations of the titrations in Parts II and III, where the total acidity in a sample of vinegar and a sample of fruit juice are determined, respectively.
Name ______________________________________ Section __________________ Experiment 6 Acid-Base Titration CM1001 Fall 2023 2 Part I. KHP (potassium hydrogen phthalate, KHC
$
H
%
O
%
, MW 204.2 g/mol) is a weak acid that is used to make solutions of very well-characterized concentrations, and hence it is a useful primary standard
. It is a solid under normal lab conditions, it can be highly purified, it does not easily oxidize, and it has a high MW, resulting in good precision and accuracy when weighing convenient sample sizes. KHP is a monoprotic acid, reacting 1:1 mole ratio with NaOH: KHC
$
H
%
O
%
(aq) + NaOH (aq) à
KNaC
$
H
%
O
%
(aq) + H
)
O
(l) Sample calculation of a standardization run: A student is given a starting solution of NaOH to standardize, known to be approximately 0.1 M. It took 19.98 mL of the approximately 0.1 M NaOH solution to reach the equivalence point with a solution of KHP that was prepared with 0.4168 g KHP. What is the concentration of the NaOH, to 4 s.f.? 0.4168 g/ (204.2 g/mol) = 2.041 x 10
-3
moles KHP 2.041 x 10
-3
moles KHP x [
1
mol NaOH/
1
mol KHP] = 2.041 x 10
-3
moles NaOH 2.041 x 10
-3
moles NaOH/ 0.01998 L = 0.1022 M NaOH
Note: You cannot leave out the 1:1 mole ratio in the calculation because that is how moles of KHP are converted to moles of NaOH. Once the concentration of the NaOH titrant is known, the titrant is used to titrate samples of vinegar and fruit juice, to determine the unknown concentration of total acid in each of these samples. Part II. White vinegar will be titrated with the standardized NaOH. White vinegar is a dilute solution of a single acid (acetic acid, HC
)
H
*
O
)
, a monoprotic acid), so the data from the titration can be used to determine the concentration of acetic acid in the vinegar. Hydrogen ions from the HC
)
H
*
O
)
react with hydroxide ions from the NaOH in a 1:1 mole ratio to produce water and sodium acetate in the overall reaction: HC
)
H
*
O
)
(aq) + NaOH (aq) à
H
)
O
(l) + NaC
)
H
*
O
)
(aq) A general form for this type of reaction, a monoprotic acid (HA) with NaOH is: HA (aq) + OH
-
(aq) à
H
)
O
(l) + A
,
(aq) or HA (aq) + NaOH (aq) à
H
)
O
(l) + NaA
Name ______________________________________ Section __________________ Experiment 6 Acid-Base Titration CM1001 Fall 2023 3 Sample calculation of a run to determine the concentration of a monoprotic acid: A 10.00 mL sample of an unknown monoprotic acid solution is titrated, using the standardized 0.1022 M NaOH solution. It took 20.04 mL of the NaOH to reach the equivalence point. What is the concentration of the monoprotic acid, HA, to 4 s.f.? 0.1022 M NaOH x 0.02004 L = 2.008 x 10
-3
moles NaOH 2.008 x 10
-3
moles NaOH x [
1
mol HA / 1
mol NaOH] = 2.008 x 10
-3
moles HA 2.008 x 10
-3
moles HA/ 0.01000 L = 0.2008 M HA
Note: You cannot leave out the 1:1 mole ratio in the calculation because that is how moles of NaOH are converted to moles of HA. Part III Lemon juice will be titrated with the standardized NaOH. Fruit juices typically have multiple organic acids, such as citric, ascorbic (vitamin C), tartaric, oxalic, malic, etc. However, citric acid (
H
*
C
-
H
.
O
/
, a triprotic acid) is the dominant acid in lemon and lime juice. The calculations in this titration will assume that the determination of total acidity is due only to citric acid. This approximation will give the maximum
amount of citric acid in the lemon juice, or total acidity as equivalent to citric acid. The three hydrogen ions from the citric acid react with hydroxide ions from the NaOH in a 1:3 mole ratio to produce water and sodium citrate in the overall reaction: H
*
C
-
H
.
O
/
(aq) + 3 NaOH (aq) à
3 H
)
O
(l) + Na
*
C
-
H
.
O
/
(aq) A general form for this type of reaction, a triprotic acid (
H
*
A) with NaOH: H
*
A (aq) + 3 OH
-
(aq) à
3 H
)
O
(l) + A
*,
(aq) or H
*
A (aq) + 3 NaOH (aq) à
3 H
)
O
(l) + Na
*
A
(aq) Sample calculation of a run to determine the concentration of a triprotic acid: A 2.00 mL sample of the unknown citric solution is titrated, using the standardized 0.1022 M NaOH solution. It took 18.67 mL of the NaOH to reach the equivalence point. What is the concentration of the triprotic acid, H
3
A to 3 s.f.? 0.1022 M NaOH x 0.01867 L = 1.908 x 10
-3
moles NaOH 1.908 x 10
-3
moles NaOH x [
1
mol H
*
A/
3
mol NaOH] = 6.360 x 10
-4
moles H
*
A
6.360 x 10
-4
moles H
*
A/ 0.00200 L = 0.318 M ࠵?
࠵?
A Note: These sample calculations for monoprotic and triprotic acids are for illustration. They are not clues to the actual concentrations in the samples.
Name ______________________________________ Section __________________ Experiment 6 Acid-Base Titration CM1001 Fall 2023 4 Experimental Procedure: Review:
Reading a burette, Exp. 1 (
http://www.chem.tamu.edu/class/fyp/mathrev/mr-sigfg.htmL) Fig. 1 Reading a burette Burette Read at the bottom of the meniscus. The smallest division on the burette is 0.1 mL. Therefore, our reading needs to have the estimated digit in the hundredth place. A good volume reading is 20.38 ± 0.02 mL. A reading of 20.35 mL ± 0.05 mL is also acceptable. Look at the pictures of a burette below. Note that the numbers get bigger as you go down the burette. This is different from the beaker or the graduated cylinder. This is because the liquid leaves the burette at the bottom Always read a burette at eye level. The rings on the burette aid in reading the meniscus without parallax error, or incorrect volume reading due to looking above or below eye level, as shown in Fig. 2 below. When reading volume with a meniscus, always read the bottom of the meniscus. Using either a white card with a black bar on it or a plain white card (moving up from underneath) behind the burette will help highlight the bottom of the meniscus, as shown in Fig. 3 below. Fig. 2 Fig. 3 Note that the ring in the back of the buret can be seen, looking up at the 5 mL mark and down at the 7 mL mark.
Name ______________________________________ Section __________________ Experiment 6 Acid-Base Titration CM1001 Fall 2023 5 Fig. 4. Experimental setup
↑ Always wear goggles! – 5 pts safety deduction each time you are asked by the instructor or TA to put your goggles on.
NaOH is corrosive and can damage eyes, skin, and clothing. If contact accidentally occurs, rinse the affected parts with large amounts of water. Funnel (optional) for filling. Remove the funnel after the burette is filled. In this experiment, NaOH is the ONLY substance that goes in the burette. Burette clamp. Use to adjust the height of the burette so meniscus is at eye level. Reading at an angle results in parallax error. Erlenmeyer flask, containing a) acid to be titrated b) 2-
3 drops phenolphthalein c) water, as diluent or solvent White paper, to enable better detection of the faint
pink endpoint
Name ______________________________________ Section __________________ Experiment 6 Acid-Base Titration CM1001 Fall 2023 6 Preliminaries You should first view the Burette Technique video posted along with this handout on the Brightspace course site. Set up the apparatus as in Fig. 4. Take a large beaker and, with a pencil, label it “WASTE” on the white patch on the side. Use this for on-bench disposal of burette rinses and finished titrations. Take a 150 mL beaker, label it “NaOH”, and use it to get about 100 mL of the approximately 0.1 M NaOH from the stock solution in the hood. Put the waste beaker under the burette instead of an Erlenmeyer flask, and rinse the burette twice, using about 25 mL each time. (Note that the “off” position for the stopcock is when the handles of the stopcock are perpendicular to the long axis of the burette). Swirl the funnel to wash the rinse NaOH down the sides of the burette. Any time you will fill a burette with a funnel, you might have to lift the funnel slightly so the liquid flows freely. Once the burette has been rinsed, with the waste beaker still under the burette (to collect any accidental overflow), fill it to your eye level (must be above the 20-mL mark), lifting the funnel to keep from overflowing. Turn the stopcock full on, to blow the air out of the tip. If there is a residual air bubble, open the stopcock so the liquid flows freely and tap or gently
jiggle the burette, to knock the bubbles out. Ask your instructor for help if you are not able to get rid of the bubbles. Once the air bubbles are cleared, fill to back up to your eye level. Your burette is now ready to start titrating. As needed use your “NaOH” beaker to get refills. Part I. Standardization of NaOH solution. 1.
The actual molarity of the approximately 0.1 M NaOH must be determined by titration to 3-4 s.f., remember the actual number of s.f. is dictated by the s.f. of the worst (lowest number of s.f.) piece of data. Obtain a small weighing boat (keep this boat to be reused for all the KHP trials). Tare the balance with the boat and weigh approximately 0.4 g of KHP (potassium hydrogen phthalate, KHC
$
H
%
O
%
, MW 204.2 g/mol) on one of the analytical balances. The sample does not have to be exactly 0.4000 g, but the mass should be recorded to 0.0001 g (ex. 0.3976 g, 0.4010 g, etc.) record the mass on the Data Sheet, Part I, Step 1
. (Do the calculations of the number of moles later, at home). 2.
Carefully transfer the KHP sample into a 250 mL Erlenmeyer flask, and use the DI water bottle to rinse any residual crystals into the flask. Add about 50 mL of deionized water and 2-3 drops of phenolphthalein indicator to the KHP solution. Swirl or stir with a glass rod until all of the solid is dissolved. Record the initial volume reading of the burette on the Data Sheet, Part I, Step 2. It is not critical what the starting point is, as long as the meniscus is on the burette scale and above the 20-mL mark, since you will need at least 20 mL for each titration.
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Related Questions
II only
O both I & II
ОШ only
QUESTION 13
Consider an acid-base titration in which the base is dispensed from a burette into a flask containing an acid. If any drops of
the base adhere to the inner walls of the flask, but do not actually mix with the solution, the calculated acid concentration
would be
O the same as the actual value.
O lower than the actual value.
O higher than the actual value.
Need more information
Click Save and Submit to save and submit, Click Save All Answers to save all answers.
Save Al
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II. Titrating HCI Solution with
NaOH Solution
1. Prepare a titration curve. Plot pH (on the y-axis)
versus volume of NaOH solution added (on the x-axis).
If your initial buret reading was not 0.00 mL, remember
to subtract your actual initial reading from each of your
subsequent buret readings before plotting the titration
data.
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CHE 1560- General Chemistry II Laboratory
Experiment 8: Solubility Product Make Up Assignment
BEAKER 2
BEAKER 3
M of NH3 solution
5 M
Initial reading of buret
0 mL
10.4 mL
(NH3) (mL)
Final reading of buret (NH3) 10.4 mL
(mL)
19.8 mL
Total volume of solution
30.4 mL
29.4 mL
after titration
Total moles of C2042-
Molarity of C2042-
Total moles of Cd2+
Moles of [Cd(NH3)42+]
Molarity of [Cd(NH3)42+]
Moles of NH3 added by
titration
Moles of NH3 that did not
react with Cd2+
Molarity of NH3 that did not
react with Cd2+
Kr for [Cd(NH3)42+]
Average K for [Cd(NH3)42+]
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This is about determinition of acid content in vinegar through titration, please answer the questions. Please answer only the items nummber 4-5. i only put other questions for guide.
1. What is the purpose of standardization?
2. What is the primary standard used (name and formula)? ANS: KHP
3. Suppose that the KHP is not completely dry. Will the reported molar concentration of the sodium hydroxide solution be higher, lower, or unaffected? Explain.
4. In preparing the buret for titration the final rinse is with the NaOH titrant rather than with distilled water. Explain.
5. The procedure suggests the addition of only 2 drops of phenolphthalein. What will be the effect to the analysis if larger amount of phenolphthalein is added?
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Why you should not start a titration with zero mL as an initial volume?
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A student titrates samples of a base with a standardised acid. The titration values obtained for each sample is given in Figure 5. What is the average titration value in cm³ that the student should use in further calculations? *
Your answer
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based on the data tables provided, what is % CH3COOH in vinegar
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Quantity of Acetic Acid in Salad Dressing
Titration Results: 1000
μL aliquots of salad dressing against a sodium hydroxide solution
Please only fill in 3 concordant results!
Titration number:
1
2
3
Error
Final burette reading (mL)
7.9
15
22.2
±0.05 mL
Initial burette reading (mL)
0.9
7.9
17
±0.05 mL
Titre (mL)
7
7.1
7.2
±0.10 mL
Average (mean) volume of concordant titres: 7.1
Concentration of Acetic Acid (M) (to 3 sig figs): 6.88
mL
IM
Concentration of Acetic Acid (as %w/v) (to 3 sig figs):
%
Note: %w/v = (g/mL) x 100%
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Pls help ASAP on both questions.
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4.
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Second slide:
A Picture from the internet of a Titration. The words
titration, primary and secondary standard defined.
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At the beginning of a titration, the acetic acid burette reads 0.30 mL. At the end of the titration. thé burette reads 27.70 mL. What volume had been added to the flask? Answer to two places past the decimal.
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صورة من ??
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14.00
4. A student titrates 20.0 ml of an acid
pH vs. Volume NaOH Added
13.00
solution with 0.500 M NaOH and gets the
graph shown below.
12.00
Determine the
11.00
concentration of the acid.
10.00
pH 9.00
8.00
7.00
6.00
5.00
4.00
0.0
2.0
4.0
6.0
8.0
10.0
12.0
14.0
Volume of 0.500 M NaOH Added
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What is the concentration of an HNO3 solution in percent by mass that was
determined to have a concentration of 0.669 M in a titration experiment? Assume a
density of 1.00 g/mL.
Your Answer:
Answer
units
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4
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I'm stuck all those questions need help
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1
2
3
4
Questions 1-4 refer to the same strong acid/strong base (SA/SB) titration.
A 25.00 mL solution of 0.200 M hydroiodic acid (HI) is being titrated with 0.200 M sodium hydroxide (NaOH). What is the initial solution pH (when 0.00 mL of titrant have been
added) (Two decimal places)
Type your answer...
Questions 1-4 refer to the same strong acid/strong base (SA/SB) titration.
A 25.00 mL solution of 0.200 M hydroiodic acid (HI) is being titrated with 0.200 M sodium hydroxide (NaOH). What is the solution pH (when 15.00 mL of titrant have been
added? (Two decimal places)
Type your answer...
Questions 1-4 refer to the same strong acid/strong base (SA/SB) titration.
A 25.00 mL solution of 0.200 M hydroiodic acid (HI) is being titrated with 0.200 M sodium hydroxide (NaOH). What is the solution pH at the equivalence point? (Two decimal
places)
Type your answer...
Questions 1-4 refer to the same strong acid/strong base (SA/SB) titration.
A 25.00 mL solution of 0.200 M hydroiodic acid (HI) is…
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25
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7) What is the molarity of a 12.46 mL sulfuric acid solution if 18.22 mL of 0.100 M potassium hydroxide is required to reach the endpoint as indicated by a titration .
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EXPERIMENT 5; Acid-Base Titration
A.
Trial 1
Trial
2
Trial 3
5.210 g
Mass of KHP
5.210 g
5.210 g
(C3H,O4)
Mole of KHP
Initial Burette
0.00
0.50
5.00
Volume NaOH (mL)
Final Burette
31.00
26.25
29.95
Volume NaOH (mL)
Total Volume of
NaOH (mL)
Moles of NaOH
Molarity of NaOH
(mol/L)
Calculate the average Molarity of NaOH
B. Titration of Vinegar (HC,H3O2)
A 2.352 g sample of Vinegar is titrated with 0.08751M
NaOH, and it requires 22.31 mL of NaOH to reach the
endpoint. Calculate the mass percent of acetic acid
(HC,H;O,) in the vinegar sample?
Hint for Calculation of Mass percent of Vinegar
(HC,H;O2)
1. Calculate mole of HC,H;O2 from concentration
(M) and volume of NaOH (L)
needed to titrate Vinegar
2. Calculate mass (g) of Vinegar from mole of
Vinegar
3. Mass % Vinegar = (calculated mass Vinegar/
2.352 g) X 100
C. A solution of malonic acid, H;C;H¿O4 ¸was
standardized by titration with 0.100 M NaOH solution.
If 20.76 mL of the NaOH solution were required to
neutralize completely 13.15 mL of…
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Analytical chemistry
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Please help with explanation.
(Gpt/Ai wrong answer not allowed)
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Use the following two titration curves to answer each of the following statements. Select the choice that completes
the statement correctly.
Graph A
Graph B
14.
14
рH 7
pH 7
25
25
volume of titrant added (mL)
volume of titrant added (mL)
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How does a redox titration differ from an acid base titration in general? How did this
titration differ from the acetic acid titration lab specifically?
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Make sure has correct significant di
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1
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I Review I Constants I P
III LI IS LILI alivin, ti e connceIILI aliun UI Dase iS KNOWN aliu Can Ue useu LU Caiculale e uiKN
Learning Goal:
concentration:
To calculate the concentration of a solution using
moles of base moles of acid
concentration of base
concentr
acid-base titration data.
In an acid-base titration an acid (or base) of
known concentration is aaded to a base (or acid) of
unknown concentration until the number of moles of
H and OH are equal, a condition called the
equivalence point. Since you know the number of
moles of HT (or OH) that you added, you can
Part A
How many moles of Ba(OH)2 are present in 205 mL of 0.600 M Ba(OH),?
Express your answer with the appropriate units.
determine the number of moles of OH
(or H) in
View Available Hint(s)
the unknown solution.
For example, a solution containing 1 mol of
H2 SO4 contains 2 mol of ionizable hydrogen
atoms, and would therefore require 2 mol of
NaOH for neutralization.
A
?
M
0.123
Previous Answers Request Answer
Submit…
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[References]
Use the References to access important values if needed for this question.
An aqueous solution of hydroiodic acid is standardized by titration with a 0.146 M solution of barium hydroxide.
If 20.2 mL of base are required to neutralize 12.4 mL of the acid, what is the molarity of the hydroiodic acid solution?
M hydroiodic acid
Submit Answer
Try Another Version
1 item attempt remaining
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Suppose a student performed a similar standardization titration experiment. Below is the calculated concentration of NaOH from each of their titrations.
Titration #1
Titration #2
Titration #3
Concentration of NaOH (M)
0.9554
0.9540
0.9551
Using the 3 concentrations, calculate the average concentration of the student's NaOH solution and calculate the ± error in parts per thousand (ppt). Show the complete calculation. Express your final answer in the form of average (with units) ± error in ppt. use the right significant figures
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In a titration, what volume (in milliliters) of 0.250M NaOH is required
to neutralize 40.0 mL of 0.1125M HCl?
Select one:
a. 18.0 mL
b. 5.56 mL
c. 200 mL
d. 13.6 mL
e. 180 mL
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Acid Base Titrations
Given the information below, calculate the acid concentration: show work and use correct number of significant figures
Unknown acid ID#: ____HCl_____(concentration unknown)
Concentration of NaOH: 0.10 M
Initial Buret reading (mL) : 4.0
Final Buret reading (mL): 14.2
Volume of NaOH added (mL): 10.2
Calculated acid concentration (M): ???
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multiple choice pls answer directly 2,3,6,7
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The following tabulated data is provided to answer this question and the remaining questions
in the quiz. The post lab data will appear each page so that you can refer back to this data,
as needed. Review the data, then answer the first question below.
The equation is H2SO4 + NaOH → Na2SO4 + H20 (note, this equation is unbalanced)
The last two rows are left blank because they will be filled in by your calculations.
Titration Lab
Trial 1 Trial 2 Trial 3
Volume of Acid Used
20.0 mL 20.2 mL 20.8 mL
Molarity of Acid Used
0.05 M 0.05 M 0.05 M
Initial Buret Reading
0.00 mL 0.00 mL 0.00 mL
Final Buret Reading
20.7 mL 21.0 mL 21.5 mL
Volume of NaOH Used
Molarity of NaOH Solution
What is the correct balanced equation for the neutralization reaction?
Select one:
O a. H2SO4 + NaOH → Na2SO4 + H2O
O b. H2SO4 + 3 NaOH → Na2SO4 + 3 H2O
c. H2SO4 + NaOH → Na2SO4 + 2 H20
O d. H2SO4 + 2 N2OH → N22SO4 + 2 H2O
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- II only O both I & II ОШ only QUESTION 13 Consider an acid-base titration in which the base is dispensed from a burette into a flask containing an acid. If any drops of the base adhere to the inner walls of the flask, but do not actually mix with the solution, the calculated acid concentration would be O the same as the actual value. O lower than the actual value. O higher than the actual value. Need more information Click Save and Submit to save and submit, Click Save All Answers to save all answers. Save Alarrow_forwardII. Titrating HCI Solution with NaOH Solution 1. Prepare a titration curve. Plot pH (on the y-axis) versus volume of NaOH solution added (on the x-axis). If your initial buret reading was not 0.00 mL, remember to subtract your actual initial reading from each of your subsequent buret readings before plotting the titration data.arrow_forwardCHE 1560- General Chemistry II Laboratory Experiment 8: Solubility Product Make Up Assignment BEAKER 2 BEAKER 3 M of NH3 solution 5 M Initial reading of buret 0 mL 10.4 mL (NH3) (mL) Final reading of buret (NH3) 10.4 mL (mL) 19.8 mL Total volume of solution 30.4 mL 29.4 mL after titration Total moles of C2042- Molarity of C2042- Total moles of Cd2+ Moles of [Cd(NH3)42+] Molarity of [Cd(NH3)42+] Moles of NH3 added by titration Moles of NH3 that did not react with Cd2+ Molarity of NH3 that did not react with Cd2+ Kr for [Cd(NH3)42+] Average K for [Cd(NH3)42+]arrow_forward
- This is about determinition of acid content in vinegar through titration, please answer the questions. Please answer only the items nummber 4-5. i only put other questions for guide. 1. What is the purpose of standardization? 2. What is the primary standard used (name and formula)? ANS: KHP 3. Suppose that the KHP is not completely dry. Will the reported molar concentration of the sodium hydroxide solution be higher, lower, or unaffected? Explain. 4. In preparing the buret for titration the final rinse is with the NaOH titrant rather than with distilled water. Explain. 5. The procedure suggests the addition of only 2 drops of phenolphthalein. What will be the effect to the analysis if larger amount of phenolphthalein is added?arrow_forwardWhy you should not start a titration with zero mL as an initial volume?arrow_forwardA student titrates samples of a base with a standardised acid. The titration values obtained for each sample is given in Figure 5. What is the average titration value in cm³ that the student should use in further calculations? * Your answerarrow_forward
- based on the data tables provided, what is % CH3COOH in vinegararrow_forwardQuantity of Acetic Acid in Salad Dressing Titration Results: 1000 μL aliquots of salad dressing against a sodium hydroxide solution Please only fill in 3 concordant results! Titration number: 1 2 3 Error Final burette reading (mL) 7.9 15 22.2 ±0.05 mL Initial burette reading (mL) 0.9 7.9 17 ±0.05 mL Titre (mL) 7 7.1 7.2 ±0.10 mL Average (mean) volume of concordant titres: 7.1 Concentration of Acetic Acid (M) (to 3 sig figs): 6.88 mL IM Concentration of Acetic Acid (as %w/v) (to 3 sig figs): % Note: %w/v = (g/mL) x 100%arrow_forwardPls help ASAP on both questions.arrow_forward
- 4.arrow_forwardSecond slide: A Picture from the internet of a Titration. The words titration, primary and secondary standard defined.arrow_forwardAt the beginning of a titration, the acetic acid burette reads 0.30 mL. At the end of the titration. thé burette reads 27.70 mL. What volume had been added to the flask? Answer to two places past the decimal.arrow_forward
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