Experiment 19 Lab Report
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Experiment 19: Qualitative Organic Analysis Unknown 1
Valentina Espinosa Canon
Laboratory Partner: Dagmawit Duresa
Professor Memari
September 26th, 2023
2 Espinosa
Materials and Method.
Refer to Memari, Behnoush. CHM 2211L - Broward College-Central. Available from:
VitalSource Bookshelf, (5th Edition). Macmillan Higher Education, 2023.
Results:
Table 1: Raw Data
TEST
RESULTS
H
2
O
Unknown did not dissolve.
HCl
Unknown did not dissolve, solid at the bottom of the test was visible.
NaOH
Unknown dissolved.
NaOCH
3
Bubbles were observed, and then the solution completely dissolved.
Titration results
Melting point was found between 156-157 degrees Celsius.
1.
Trial #1 & #2 same result
Number of moles of NaOH = (mL of base used) × (1/1000 mL) × (molarity of the base)
Number of moles of NaOH = 17.3 mL × (1/1000 mL) × 0.1 M = 0.00173 moles
Molar mass = (mass of sample in grams) / (number of moles of acid)
Molar mass = (0.225 g) / (0.00173 moles) = 130.06 g/mol
Moles of acid = Moles of NaOH (1:1 stoichiometry) = 0.00173 moles
FW = Mass of acid / Moles of acid
FW = 0.225 g / 0.00173 moles
FW ≈ 130.06 g/mol
Unknown #1 = Salicylic acid
Discussion:
3 Espinosa
The purpose of this experiment was to identify an unknown organic compound, which
could be an aldehyde, ketone, or carboxylic acid. Numerous steps were involved in the
identification process, such as determining the boiling point, performing solubility tests, and
performing classification tests.
In order to identify the unknown compound #1, we first needed to determine its boiling
point. We observed a melting point range of 156-157 degrees Celsius for the unknown.
In order to conduct the solubility study, different solvents and solutions were used to test
the unknown's solubility. According to the results, neither water nor hydrochloric acid dissolved
the unknown. Upon mixing NaOH and NaOCH3 solutions, bubbles appeared and the solution
dissolved completely. A carboxylic acid functional group may be present based on these
observations.
FW was calculated by performing a neutralization equivalent experiment to confirm the
presence of carboxylic acid functional groups. The unknown solution was dissolved in ethanol,
titrated with 0.1 M sodium hydroxide using phenolphthalein as the indicator, and 17.3 mL of
NaOH used were recorded. A titration was performed twice, and an average was used to
calculate the results. According to the calculation, FW is approximately 130.06 grams/mole.
According to the observed melting point range and the FW, salicylic acid was identified as the
unknown.
Conclusion:
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Yeast can produce ethanol by the fermentation of glucose (C6H12O6), which is the basis for the production of most alcoholic beverages.
C6H12O6 (aq) → 2 C2H5OH(l) +2 CO2 (g)
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Question 6
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Thermodynamic Data:
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Compound
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5.
Answer ALL parts of this question
The stability of chloramphenicol in eye drops is being
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different temperatures over time is provided below.
Time (day)
-18°C
25°C
40°C
25
28
23
7
27
20
20
30
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21
20
180
23
25
19
(a) Using the data in the tables below assess and
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null hypothesis of the statistical test carried out.
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a. When 52.70 and 44.375 are divided, the answer should be based on 4
Enter the answer with the correct number of digits.
52.70 44.375= 1.188
An error has been détected in your answer. Check for typos,
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Enter the answer with the correct number of digits.
52.70 44.375= 8.32
Submit Answer
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