Spring22 Simple Harmonic Motion Lab Online
docx
School
University of Texas, San Antonio *
*We aren’t endorsed by this school
Course
1611
Subject
Chemistry
Date
Dec 6, 2023
Type
docx
Pages
4
Uploaded by kylarroyer
Analysis of Simple Harmonic Motion Lab
Table 1 (20 points for first and third columns)
Mass (kg)
Weight (N)
Displacement, Δy (m)
0.050 kg
0.491 N
0.13 m
0.075
0.736
0.19
0.100
0.981
0.25
0.125
1.226
0.32
0.150
1.472
0.38
0.175
1.717
0.43
0.200
1.962
0.50
0.225
2.207
0.56
0.250
2.453
0.62
0.275
2.698
0.68
0.300
2.943
0.74
1.
Calculate the weight for each mass and fill in the middle column. Show the work for one
of these calculations to receive credit. (5 points)
-
Weight = mass x gravity
-
Weight = 0.05 kg x 9.81 m/s
2
= 0.49 N
2.
Using Excel or some other graphing program, plot Weight vs Displacement. Use the
trendline to find the slope of your graph. The slope is the Spring Constant of this spring.
Record the value of the slope in the space provided below. Turn in this graph with the
lab worksheet. Make sure the trendline is displayed on the graph.
1
Measured Spring Constant, k (N/m):
___4.0131 N/m___ (10 points)
Table 2 (5 points)
Mass (kg)
0.100 kg
Time (s)
9.95 s
Calculate the experimental value of the period of oscillation by simply dividing the time you
measured by 10.
Average Period, T
avg
(s)
:__0.995 s__
1.
Using 0.100 kg as the mass, and the value of your experimental force constant, calculate
the theoretical value of the period for your spring mass system. (5 points)
2.
Calculate the % error between your experimental and calculated period. (5 points)
2
3.
In theory, relative to the equilibrium position, where is the mass when its speed is at its
maximum? (10 points)
-
When the displacement is zero, at equilibrium position, the speed is a maximum. So, the
mass is at zero displacement or equilibrium position.
4.
In theory, relative to the equilibrium position, where is the mass when its speed is zero?
(10 points)
-
When the displacement is at maximum, or the spring is fully compressed, the speed is
zero. So, the mass is at maximum displacement or fully compressed.
5.
In theory, relative to the equilibrium position, where is the mass when its acceleration is
at its maximum? (10 points)
-
When the displacement is at maximum, fully compressed, the acceleration is at
maximum. So, the mass is at maximum displacements when its acceleration is at its
maximum.
6.
In theory, relative to the equilibrium position, where is the mass when its acceleration is
zero? (10 points)
-
When the displacement is zero, at equilibrium position, the acceleration is zero. There is
no force acting on the mass at equilibrium position, so the acceleration is zero.
3
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
7.
Do the results of our experiment confirm theoretical predictions?
Explain your answer.
(10 points)
-
Yes, the results of our experiment confirm theoretical predictions. Based upon our
calculated percentage error of 0.32%, this is an extremely low error. Meaning that our
experimental period value is almost the same as the theoretical period value.
4
Related Documents
Related Questions
Using the thermodynamic information in the ALEKS Data tab, calculate the standard reaction free energy of the following chemical reaction:
4Fe (s)+30, (g)→ 2Fe,0, (s)
Round your answer to zero decimal places.
kJ
x10
Continue
O2021 McGraw Hill LLC. All Rights Reserved. Terms
arrow_forward
7:27
Done
Photo
Dimensional Analysis Worksheet
NAME: madsoo mcucker
1. 261 J» kJ
11. 22.4 kg/L to dag/mL
2. 3.0 x 1022 molecules → mol
12. 0.74 miles/min to dm/sec
3. 9,474 mm cm
13. 1.42 g/cm? to mg/mm?
4. 0.73 mol → L
14. 10095 ft/s to miles/s
5. 5.93 cm m2
15. 9.81 mg/L to lbs/cm
6. 498.82 L - molecules
16. 8.41 kJ/mol to cal/L
7. 1.00 ft hm
17. 3.8 Mg → Ibs
8. 1.0 year - minutes
18. 7.68 g/mol → ng/molecules
9. 175 lbs cg
19. 8.24 atm/cm to torr/ft
10. 4.65 km - in
20. 25 m/s to miles hr
arrow_forward
In the technique of high performance liquid chromatography (HPLC) the peak area response for a particular analyte is directly proportional to concentration
Analgesic tablets typically consist of aspirin and caffeine as the active ingredients, the remainder made up of inert binding material. The concentrations of aspirin and caffeine may be
routinely monitored using HPLC, whereby the peak areas obtained from a solution of the tablet are compared with those obtained from standard solutions of the analytes.
In an analysis to determine the concentration of caffeine in such a tablet, the following data were recorded:
Solutions Analysed:
Tablet Sample:
Mass of tablet (dissolved in 250 cm methano): 0.523 g
Caffeine Standard:
Mass of caffeine (diessolved in 500 cm methanol) 0.105 g
HPLC results:
Solution
Peak Area (catfeine)
1. Tablet Sample
325
2. Caffeine Std.
865
The concentration of caffeine in the tablet (expressed as a mass (w/wl percentage) was
Oa 1.89
Ob 13.4
O 3.77
Od. 267
Oe 7.54
You…
arrow_forward
on the last part of the problem where it is x=( 10-10 x 0.25)1/2=5x10-6 M
When I plug that into my calculator I get 1.25 an not 5x10-6 what am I doing wrong
arrow_forward
Question:
Using a method for the determination of % CaO in limestone the following results were obtained for a NIST Certified Reference Sample (CRM):
% Cao
50.38, 50.20, 50.31, 50.22 50.41
Five samples were obtained from a railcar of limestone. The analysis of the samples gave the following results:
% CaO
55.01, 59.61, 58.82, 64.39, 62.49
a) Determine the variance due to sampling.
b) If the samples taken from the railcar had a mass of 0.500 g, what mass
arrow_forward
B
NA
BH2 bh3
S =
6
6H
Calculator:
NA indicates
neutral axis
Section Modulus I Beam Universal
Calculator
For the next four questions (including this one)
ignore k and k1 in your calculations.
Using the same table, enter the value for B in
inches. (three sig figs)
arrow_forward
Icalate Hi
BeHot)+6el2( +2Bels() +oHel(②)
using Hess Law
Bel310+3H2O→H2B/23(g) +3=-122.5K)
B2H6(+6H2O(P)→2HB+6H2(火)
→トニ-4734人)
Male B₂ HO
H2(+244145)
Siven
+3HP
Im Belz
arrow_forward
Perform the calculations and determine the absolute and percent relative uncertainty. Express each answer with the correct number of significant figures. To avoid rounding errors, do not round your answers until the very end of your calculations.
arrow_forward
The density of water varies with temperature.
T / oC Density / g mL–1
19.00 0.998405
20.00 0.998203
What is the density of water at 19.75ºC found by linear interpolation?
Question 4 options:
0.998304 g mL–1
0.998254 g mL–1
0.998355 g mL–1
arrow_forward
What is the slope of the calibration curve (first four options), the Y-intercept of the
calibration curve (second four options), and the R² value of the calibration curve
(final four options) to four significant figures on each?
arrow_forward
Y
Submit
Part C
[OH-] = 5.4 x 10-4 M
Express your answer using two decimal places.
pH =
Request Answer
Part D
[VD| ΑΣΦ
VO
Submit
Request Answer
[OH-] = 0.004 M
Express your answer using one decimal place.
pH =
ΠΕ ΑΣΦ
ha
?
Address
arrow_forward
8:45
Convert 7.6 cm³ to m³
STARTING AMOUNT
ADD FACTOR
x( )
(1000) ³
0.01
(0.1) ³
(0.01) ³
0.076
(1) ³
0.1
1
100
1000
Question 29 of 40
(100) ³
7.6 x 10-4
7.6
7.6 x 10-6
X
ANSWER
m³
cm³
m
cm
Tap here or pull up for additional resources
..lLTE
Submit
RESET
5
arrow_forward
Please correct answer and don't use hand raiting
arrow_forward
i cant seem to get the right answer for this, could you please explain how i use the constant? like how do i enter it in the calculator
arrow_forward
Please answer as soon as possibly and I will leave a like.
arrow_forward
For the numbers 116.0, 97.9, 114.2, 106.8 and 108.3, use the Q-test, decide whether the number 97.9 should be discarded.
arrow_forward
Please complete the rest of the chart below using the data given
formual that maybe useful:
q = m c delta T
arrow_forward
TRial 1
Trial 2
Trial 3
0.1 N HCl
0.1 N NaOH
0.1 N HCl
0.1 N NaOH
0.1 N HCl
0.1 N NaOH
Final reading (ml) of the buret
20.00
19.90
40.00
39.70
20.00
45.30
Initial reading (ml) of the buret
0.00
0.00
20.00
19.90
0.00
25.50
Volume Used (ml) for the trial
Compute for 1.00 ml HCl in terms of ml. NaOH for EACH Trial.
Compute for 1.00 ml NaOH in terms of ml. HCl for EACH Trial.
arrow_forward
Fill in the remaining columns except kj/mole
arrow_forward
Calculate the mean and 90% confidence interval for the
data set.
Sample Value
1
8.0626
8.0650
3
8.0583
4
8.0564
8.0571
6.
8.0600
mean:
étv A A
hulu
2.
5.
arrow_forward
SEE MORE QUESTIONS
Recommended textbooks for you

Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Related Questions
- Using the thermodynamic information in the ALEKS Data tab, calculate the standard reaction free energy of the following chemical reaction: 4Fe (s)+30, (g)→ 2Fe,0, (s) Round your answer to zero decimal places. kJ x10 Continue O2021 McGraw Hill LLC. All Rights Reserved. Termsarrow_forward7:27 Done Photo Dimensional Analysis Worksheet NAME: madsoo mcucker 1. 261 J» kJ 11. 22.4 kg/L to dag/mL 2. 3.0 x 1022 molecules → mol 12. 0.74 miles/min to dm/sec 3. 9,474 mm cm 13. 1.42 g/cm? to mg/mm? 4. 0.73 mol → L 14. 10095 ft/s to miles/s 5. 5.93 cm m2 15. 9.81 mg/L to lbs/cm 6. 498.82 L - molecules 16. 8.41 kJ/mol to cal/L 7. 1.00 ft hm 17. 3.8 Mg → Ibs 8. 1.0 year - minutes 18. 7.68 g/mol → ng/molecules 9. 175 lbs cg 19. 8.24 atm/cm to torr/ft 10. 4.65 km - in 20. 25 m/s to miles hrarrow_forwardIn the technique of high performance liquid chromatography (HPLC) the peak area response for a particular analyte is directly proportional to concentration Analgesic tablets typically consist of aspirin and caffeine as the active ingredients, the remainder made up of inert binding material. The concentrations of aspirin and caffeine may be routinely monitored using HPLC, whereby the peak areas obtained from a solution of the tablet are compared with those obtained from standard solutions of the analytes. In an analysis to determine the concentration of caffeine in such a tablet, the following data were recorded: Solutions Analysed: Tablet Sample: Mass of tablet (dissolved in 250 cm methano): 0.523 g Caffeine Standard: Mass of caffeine (diessolved in 500 cm methanol) 0.105 g HPLC results: Solution Peak Area (catfeine) 1. Tablet Sample 325 2. Caffeine Std. 865 The concentration of caffeine in the tablet (expressed as a mass (w/wl percentage) was Oa 1.89 Ob 13.4 O 3.77 Od. 267 Oe 7.54 You…arrow_forward
- on the last part of the problem where it is x=( 10-10 x 0.25)1/2=5x10-6 M When I plug that into my calculator I get 1.25 an not 5x10-6 what am I doing wrongarrow_forwardQuestion: Using a method for the determination of % CaO in limestone the following results were obtained for a NIST Certified Reference Sample (CRM): % Cao 50.38, 50.20, 50.31, 50.22 50.41 Five samples were obtained from a railcar of limestone. The analysis of the samples gave the following results: % CaO 55.01, 59.61, 58.82, 64.39, 62.49 a) Determine the variance due to sampling. b) If the samples taken from the railcar had a mass of 0.500 g, what massarrow_forwardB NA BH2 bh3 S = 6 6H Calculator: NA indicates neutral axis Section Modulus I Beam Universal Calculator For the next four questions (including this one) ignore k and k1 in your calculations. Using the same table, enter the value for B in inches. (three sig figs)arrow_forward
- Icalate Hi BeHot)+6el2( +2Bels() +oHel(②) using Hess Law Bel310+3H2O→H2B/23(g) +3=-122.5K) B2H6(+6H2O(P)→2HB+6H2(火) →トニ-4734人) Male B₂ HO H2(+244145) Siven +3HP Im Belzarrow_forwardPerform the calculations and determine the absolute and percent relative uncertainty. Express each answer with the correct number of significant figures. To avoid rounding errors, do not round your answers until the very end of your calculations.arrow_forwardThe density of water varies with temperature. T / oC Density / g mL–1 19.00 0.998405 20.00 0.998203 What is the density of water at 19.75ºC found by linear interpolation? Question 4 options: 0.998304 g mL–1 0.998254 g mL–1 0.998355 g mL–1arrow_forward
- What is the slope of the calibration curve (first four options), the Y-intercept of the calibration curve (second four options), and the R² value of the calibration curve (final four options) to four significant figures on each?arrow_forwardY Submit Part C [OH-] = 5.4 x 10-4 M Express your answer using two decimal places. pH = Request Answer Part D [VD| ΑΣΦ VO Submit Request Answer [OH-] = 0.004 M Express your answer using one decimal place. pH = ΠΕ ΑΣΦ ha ? Addressarrow_forward8:45 Convert 7.6 cm³ to m³ STARTING AMOUNT ADD FACTOR x( ) (1000) ³ 0.01 (0.1) ³ (0.01) ³ 0.076 (1) ³ 0.1 1 100 1000 Question 29 of 40 (100) ³ 7.6 x 10-4 7.6 7.6 x 10-6 X ANSWER m³ cm³ m cm Tap here or pull up for additional resources ..lLTE Submit RESET 5arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Principles of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning

Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning