Empirical Lab Hutchinase1

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Appalachian State University *

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1110

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Chemistry

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Dec 6, 2023

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docx

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Introductory Chemistry 1110 Empirical Formula of a Hydrate experiment Lab reports are due the week of Oct. 23 rd – 27 th , 2023 Your lab report must contain the following information: Experimental data may be collected with other students in introductory chemistry labs. However, I understand that sharing information required for a lab report or unknown submission (including but not limited to word processing or spreadsheet files, calculations, graphs, conclusions and additional problems at the end of the lab report) with other students is a violation of the University Academic Integrity Code. __ hutchinsae1@appstate.edu_ __________________________________ Signature (or ASU email address, to indicate signature if an electronic copy is submitted) 1. An abstract section for this experiment (refer to your lab manual for details and an example). In this lab, I started by obtaining an unknown salt substance and heated it up using a rod and the bunsen burner. I did this 2x for 10 minutes to get all or most of the water out of the substance. I weighed the substance and calculated my water percentage to find which unknown substance I had. 2. Give your unknown number and the empirical formula for your hydrated salt: Unknown number: 443157 Formula: MnSO4 3. A completed Table 1 with all the raw and calculated data (like the one found in the lab manual). Table 1 Unknown Number 443157 Identity of Dehydrated Salt MnSO 4 Mass of empty dish 40.467g Mass of dish + hydrated salt 52.362g a) first heating 50.990g b) second heating 50.987g Mass of hydrated salt 11.895g Mass of dehydrated salt 10.520g Mass of water lost 1.3750g Wt. % of water in hydrated salt 11.559% Moles of dehydrated salt 0.070 mol Moles of water driven off 0.076 mol Empirical formula of hydrated salt MnSO 4 * H 2 O 4. Show the calculation for obtaining the mass of your hydrated salt used.
52.362g - 40.467g = 11.895g 5. Show the calculation for obtaining the mass of your dehydrated salt left after the second heating. 50.987g - 40.467g = 10.520g 6. Show the calculation for obtaining the mass of water that was driven off from the heating. 11.895g - 10.520g =1.375g 7. Show the calculation for obtaining the weight percent of water that was in your hydrated salt. 1.375g/ 11.895g x100 = 11.559g 8. Show the calculation for obtaining the moles of dehydrated salt left after the second heating. 10.520g / 151.001 g/mol = 0.070 mol 9. Show the calculation for obtaining the moles of water that was driven off. 1.375g / 18.015 g/mol 10. Show the calculation for obtaining the empirical formula for your hydrated salt. NiSO 4 * 6H 2 0 ---> MnSO 4 * H 2 0 Answer the following questions. Show all work! 11. Give the correct chemical formulas for the following: a) sodium sulfide b) nickel(II) sulfate c) hydrobromic acid Na2s NiSO 4 HBr 12. Determine the correct chemical names of the following species: a) NH 3 b) Fe 3 (PO 3 ) 2 c) K2 CO 3 Ammonia Iron ii phosphite potassium carbonate 13. Suppose that after cooling you left the salt sit out overnight, allowing moisture back into the sample, then came and got the mass after the second heating in the morning and used that value for your calculations. How would this specifically affect the calculated percentage of water in the hydrated salt? The percentage would increase because you allowed time for water to return back to its original state. Checklist of Items to Submit _______ Hard copy of lab report printed, academic integrity code signed, stapled and ready to hand in before the start of pre-lab (if required by your instructor) ___check____ Electronic copy with academic integrity code submitted on AsULearn before the start of pre-lab under topic “Hydrate Lab Report Submission”
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