_Lab 4 Document
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University of Texas *
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1404
Subject
Chemistry
Date
Apr 3, 2024
Type
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4
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Part 1: Exploration
Take some time (no more than 15 minutes) to see what happens when the carts crash into each
other. Try changing the weight of each cart, the ways in which they contact one another
(magnets, springs, etc.), and the initial motion. Do not worry about collecting any data during
this part of the lab.
Part 2: Collisions
These criteria will be used to assess your Experimental Setup and Data Tables. Each of the
scientific abilities listed here will be assessed out of ten (10) points for a total of 20 points.
Experimental Setup (assessed using rubric):
Make an annotated sketch of your set up in the space provided on the data sheet, including the
location of measurement devices, e.g., motion detectors or video recorder. Include information
that someone would need in order to reproduce this experiment on their own.
As you include elements and information in your sketch, also explain why it is important to
include such information. For example, if you have indicated the mass of a cart, be sure to
explain why the mass is important information to include. (You can put a screen shot of the
simulation and explain why each of the initial conditions are important, then explain step by step
how you are using the simulations to collect data)
Data Tables (assessed using rubric):
Use the data table below for your collision trials. Add vertical lines to separate the table into
additional columns. Make a column for each type of data that you measured, making sure to
include units, and record values for each trial. Please identify which of the measured quantities
are independent and dependent variables.
Measured Data Create the data table:
Trial
m
1
(kg)
m
2
(kg)
v
1
(m/s)
v
2
(m/s)
v
\
1
(m/s)
v
\
2
(m/s)
1
23 kg
23 kg
3.00 m/s
0 m/s
0.00 m/s
3.00 m/s
2
23 kg
23 kg
3.50 m/s
0 m/s
0.00 m/s
3.50 m/s
3
23 kg
23 kg
2.00 m/s
0 m/s
0.00 m/s
2.00 m/s
4
23 kg
23 kg
1.50 m/s
0 m/s
0.00 m/s
1.50 m/s
5
23 kg
23 kg
4.50 m/s
0 m/s
0.00 m/s
4.50 m/s
Independent Variable:
Initial velocity 1
Dependent Variables:
Final velocity 1 and 2
Calculated Data Create the Data Table(Create a data table or tables with all your
calculated data):
Trial
p
1
p
2
p
+
p
\
1
p
\
2
p
\
+
p
\
+
-p
+
1
69
0.00
69
0.00
69
69
0.00
2
80.5
0.00
80.5
0.00
80.5
80.5
0.00
3
46
0.00
46
0.00
46
46
0.00
4
34.5
0.00
34.5
0.00
34.5
34.5
0.00
5
103.5
0.00
103.5
0.00
103.5
103.5
0.00
Your preview ends here
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Trial
KE
1
KE
2
KE
+
KE
\
1
KE
\
2
KE
\
+
KE
\
+
- KE
+
1
103.50 J
0.00 J
103.50 J
0.00 J
103.50 J
103.50 J
0.00 J
2
140.68 J
0.00 J
140.68 J
0.00 J
140.68 J
140.68 J
0.00 J
3
46.00 J
0.00 J
46.00 J
0.00 J
46.00 J
46.00 J
0.00 J
4
25.88 J
0.00 J
25.88 J
0.00 J
25.88 J
25.88 J
0.00 J
5
232.88 J
0.00 J
232.88 J
0.00 J
232.88 J
232.88 J
0.00 J
Sample Calculations:
Momentum:
( 23 * 3 = 69), ( 23 * 3.5 = 80.5), ( 23 * 2 = 46), ( 23 * 1.50 = 34.5) ( 23 * 4.50 = 103.5)
Change in Momentum:
(69 - 69 = 0),(80.5 - 80.5 = 0), (46 - 46= 0), (34.5 - 34.5= 0), (103.5 - 103.5= 0)
Kinetic Energy:
(.5* 23 *(3^2)) = 103.5, (.5* 23*(3.5^2)) = 140.68, (.5* 23 *(2^2)) = 46.00, (.5* 23 *(1.5^2)) =
25.88, (.5* 23*(4.5^2)) = 232.88
Change in Kinetic Energy:
( 103.5 - 103.5 = 0), ( 140.68 - 140.68 = 0),( 46.00 - 46.00 = 0),( 25.88 - 25.88 = 0),(232.88 -
232.88 = 0)
Question 1 (20 points)
a. What is the change in momentum for each trial? You can the values here or make an
additional column in the table above.
0 (See Table Above )
b. What is the average change in momentum across all trials (Show your work)?
0 ( See table Above)
c. What is the change in energy for each trial? Again, feel free to make an additional column
in the table if needed.
0 (See Table Above)
d. What is the average change in energy across all trials?(Show your work)
0 (see Table Above)
Question 2 (10 points).
a. Apply what you’ve learned about measurement statistics, specifically, standard
uncertainty and confidence intervals. Is momentum conserved for these collisions? Why
or why not?
Yes, based on my confidence intervals my change in momentum was zero meaning that my
momentum was conserved for the collisions
b. Is energy conserved for these collisions? Why or why not?
Yes, based on my confidence intervals my change in energy was zero meaning that my energy
was conserved for the collisions
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