MENG_3331_Lab_2_individual_report

Figure 1 shows the tensile testing results for different materials. All specimens have an initial diameter of 12 mm and an initial gauge length of 50 mm. 300 250 Low carbon steel Network polymer 200 Crystalline polymer 150 Amorphous polymer 100 50 5 10 15 20 25 30 Strain (%) Figure 1: Stress-strain curve b. Determine the following parameters for each material: • the tensile strength the 0.2% offset yield strength the modulus of elasticity • the ductility Stress (MPa) LO

You have been given the following test sample data following mechanical testing of 15 test pieces of a modified Alumina. What is the Weibull modulus of this material? Would you advise the use of this material over one with a Weibull Modulus of 19.6 and a mean failure stress of 270 MPa, if you anticipate that the peak stress on the material could be 255 MPa? Sample 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 Select one or more: a. 185 b. No Yes □d. 49 □e. 28.6 3.7 Failure Stress (MPa) 297 293 270 300 g. 22.8 260 296 265 295 280 288 263 290 298 275

6. The following engineering stress-strain data were obtained for 0.2% C plain carbon steel. (a) Plot the engineering stress-strain curve (b) Determine the ultimate tensile strength for the alloy (c) Determine the percent elongation at fracture (d) Plot the true stress-strain curve Engineering strain, in./in. Engineering stress, ksi 30 0.001 55 0.002 60 0.005 68 0.01 72 0.02 74 0.04 75 0.06 76 0.08 75 0.1 73 0.12 69 0.14 65 0.16 56 0.18 51 0.19(fracture)

I just can't find The percent elongation at fracture.

The engineering stress-strain curve below was obtained for a precipitation hardened Aluminum alloy. What is the approximate Yield Strength for this alloy in psi? Engineering Stress Based on Original Area (psi) 50,000 45,000 40,000 35,000 30,000 25,000 20,000 15,000 10,000 5,000 0 O 0.02 0.04 0.06 Aluminum 6061-T6 0.08 0.1 0.12 Engineering Strain (in/in) 0.14 X 0.16 0.18

A 11 in. inner diameter, 0.35 " wall thickness pipe is under a pressure of 2.5 ksi where strain gages installed along axial and circumferential directions register strains of 180 and 900 micro-strains (x10^-6), respectively. A) What is the Poisson's Ratio of this material and it's Elastic Modulus? B) In a uniaxial test, the pipe's material is observed to yield at a longitudinal strain of 0.1 in/in. Assuming a factor of safety of 2, the pipe can withstand impact energy of _______ lb - in per foot without suffering permanent deformation. C) If the pipe is depressurized and then subjected to a torque of 50 lblb - ft.ft., it will experience a shear strain of ________ rad.

A 11 in. inner diameter, 0.35 " wall thickness pipe is under a pressure of 2.5 ksi where strain gages installed along axial and circumferential directions register strains of 180 and 900 micro-strains (x10^-6), respectively. A) What is the Poisson's Ratio of this material and it's Elastic Modulus? B) In a uniaxial test, the pipe's material is observed to yield at a longitudinal strain of 0.1 in/in.in/in. Assuming a factor of safety of 2, the pipe can withstand impact energy of _______ lblb - in.in. per foot without suffering permanent deformation. C) If the pipe is depressurized and then subjected to a torque of 50 lblb - ft.ft., it will experience a shear strain of ________ rad.

Flag question You have been given the following test sample data following mechanical testing of 15 test pieces of a modified Alumina. What is the Weibull modulus of this material? Would you advise the use of this material over one with a Weibull Modulus of 19.6 and a mean failure stress of 270 MPa, if you anticipate that the peak stress on the material could be 255 MPa? Sample 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 Select one or more: Failure Stress (MPa) 297 293 270 300 260 286 265 295 4 293 280 288 263 290 298 275

Please use ANSYS SOFTWARE

please wright by hand

UzNDU3NTYyMjk0/a/MjYOMzAwMjMOOTM5/details Further questions 4.The graphs show how the extension changes with stretching force for four different materials. a. Which two graphs show materials that follow Hooke's law? A B b. Which two graphs show materials that become less stiff as they are stretched? force force D C. Which graph shows a material that maintains the same stiffness throughout? force force 1. A force of 20N stretches a spring by 0.5m. The spring obeys Hooke's law. a. Calculate the spring constant including a suitable unit. b. How much force must a man use to stretch it by 1.5m? 5. A car has a weight of 240OON which is distributed equally over all four wheels. Each wheel has a spring of spring constant 400N/cm. a. Determine the force through the spring on each wheel. b. Calculate the compression of each spring when the car rests on the ground. 6.In a spring experiment the results were as follows: Force (N) Length (mpm 1 2 4 6. 7 50 58 70 74 82 9n 102 125 LELL

Results: material iron brass aluminum copper NH VINI Discussion: vickers hardnes test Load(kg) 50 50 30 30 Diameter of trace d1 d2 0.58 0.65 0.68 0.74 0.94 0.86 0.72 0.76 d1+d2 2 VHN Kg/mm² 1- Calculate the Vickers hardness number for the previous samples and compare the results and discuss them according to the table. 2- Draw a graphic relationship between the diameter of the trace and the hardness of Vickers. 3- What is the condition for using the Vickers hardness device?

5. The following data were collected from a standard 0.505-in.-diameter test specimen of a copper alloy (initial length lo= 2.0 in.). After fracture, the total length was 3.014 in. and the diameter was 0.374 in. Load (Ib) Al (in.) 00000 3,000 6,000 0.00167 0.00333 7,500 0.00417 9,000 10,500 0.0090 0.040 12,000 0.26 12,400 11,400 0.50 (maximum load) 1.02 (fracture) a) Plot the data as engineering stress versus engineering strain. b) Compute the modulus of elasticity. c) Determine the yield strength at a strain offset of 0.002. d) Determine the tensile strength of this alloy. e) What is the approximate ductility, in percent elongation? f) Compute the modulus of resilience. g) Compute from the data and plot true stress versus true strain diagram.

Viscosity (Pa-s) 400 1016 1014 1012 1010 108 105 104 10² 1 200 800 Borosilicate glass Temperature (°F) 1200 1600 2000 96% silica glass Working range Melting point 400 600 Fused silica 2400 2800 3:200 Strain point Annealing point Softening point Working point Soda-lime glass 1018 1016 1014 1012 1010 108 106 104 10² 800 1000 1200 1400 1600 1800 Temperature (°C) Viscosity (P)

A cylindrical acetal polymer bar 64 cm long and 1.27 cm in diameter is subjected to a vibrational (tension) load at a frequency of 501 vibrations per minute with a load of 4,849 N. How many hours will the part survive before breaking?  Use stress = force/area and WATCH YOUR UNITS!!

Consider the compressive strength data from the table below. Compressive Strength (in psi) of 80 Aluminum-Lithium Alloy Specimen 174 112 163 128 106 161 147 161 201 127 181 91 156 127 175 111 221 126 176 99 109 108 161 150 245 168 114 175 242 203 135 240 159 160 151 135 132 153 136 171 140 159 109 173 95 103 91 112 179 141 119 106 151 127 131 186 207 145 169 182 251 228 132 141 186 98 144 159 147 100 116 108 171 140 211 160 97 134 105 230 What proportion of the specimens exhibit compressive strength of at least 200 psi? Enter the exact answer.

solve on Excel

Mild steel 1 Young;s modulus 1219.5 Yield strain and stress (0.4101,500.08) Failure stress and strain :not able to find because the given data shows the experiment did not reach the failure point.  if the material stress and strain does not reach a failure point ,what dose it means , does it means that the material is more stronger?

For a given homogeneous, isotropic, linearly elastic material, E = 15e6 psi and v = 0.3. Solve for the shear modulus. 2.1.1 Homogeneous, isotropic, linearly elastic materials For specimens undergoing small deformations, the stress-strain diagram often ex- hibits a linear behavior. Although this is a very crude approximation to the behavior of actual materials, it is a convenient assumption that is often used for preliminary evaluation. A linear relationship between stress and strain can be expressed as 01 = E €1, (2.1) where the coefficient of proportionality, E, is called Young's modulus or modulus of elasticity. Since strains are non-dimensional quantities, this coefficient has the same units as stress quantities, i.e., Pa. This linear relationship is known as Hooke's law. The elongation of a bar in the direction of the applied stress is accompanied by a lateral contraction that is also proportional to the applied stress. The resulting defor- mations for this uniaxial state of stress…