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Show the location of the axis of rotation and r for each force that produces torque in the diagram. Also, check calculations, I am off by 1 degree.

Problem 1: Calculate the forces in the required members of the truss shown: F1 F2 F3 H F h F4 D E C 4 @ S

T2 = 390 K Vz = ? P, = 300 kPa = 400 K v, = 20 m/sec D1 = 15 cm P1 = ? T1 m =?

Q1 Two spur gears in a simple train shown in Figure Q1 are having the same module, m = 2 and their respective number of teeth is NTm = 30 for the driver gear, and NTG = 45 for the driven gear. The inertia of the gear attached to the motor is Im = 0.1 kgm? and the inertia of the second gear is IG = 0.1 kgm?. The second gear is connected to a pulley with the radius of 30 mm. The pulley is hoisting up the 2kg load with acceleration of a = 2 ms?. Given the gear transmission efficiency is 90%. a) Based on the module and number of teeth given, examine the pitch diameter of eachgear. b) Considering acceleration of load at 2 ms-?, evaluate the torque of the motor toovercome gears inertia.

Draw SFD BMD V(x) M(x)

2. For the linkage shown in Fig. 2, determine VB and 004. auquo od to enoblog lugna adi snimateb 11 ge 200 to styd (SB048-2 in. 02 mmm. min 501 45° 3 Figure 2. 4 04 0₂04 = 4 in. 0₂A - 2.828 in 104 AB= in. 2 14.14 rad/s ccw

A deep grove ball bearing running at 5500 r.p.m is required to resist an applied radial load P of 2,500N and having an L10h life of 20,000 hours. What is the most appropriate SKF Cat.No. for a suitable bearing: Use the information in the attached diagram below. C 3 - (-) = P L 10 d 10 15 20 ▬▬▬▬▬▬▬▬▬ 2288898 25 30 35 40 45 50 60 70 80 90 100 Dimensions D mm 30 35 47 52 62 72 80 85 90 110 125 140 160 180 B 9 11 14 15 16 17 18 19 20 22 24 26 30 34 Load ratings C Co (dynamic) (static) 5.07 7.8 12.7 14.0 19.5 25.5 30.7 33.2 35.1 52.7 60.5 70.2 95.6 124 KN Speed limit rpm 24 000 2.36 3.75 19 000 6.55 15 000 7.80 12 000 10 000 9 000 8 500 7 500 7 000 6 000 11.2 15.3 19.0 21.6 23.2 36 45 55 73.5 93 5 000 4 500 3 800 3400 Mass SKF Cat No. kg 0.032 0.045 6204 0.11 0.13 6205 0.20 6206 0.29 6207 0.37 6208 0.41 6209 0.46 6210 0.78 6212 1.05 6214 1.40 2.15 3.15 6200 6202 6216 6218 6220 Mounting dimensions d₂ D₂ min. max mm 14 26 19 31 25 42 30 47 35 57 42 66 47 74 52 79 57 84 68 102 78 117 89 131…

Draw the acceleration polygon. Show Transcribed Text C U From the drawn polygon, find angular acceleration of link 2 (link BC) and the translating acceleration of the block C.

A 60 mm diameter shaft AB is rigidly attached to the beam CDFH of 30 mm by 40 mm rectangular cross-section as shown in Figure Q4. The beam is pin supported at C and H. A torque of 2 kN.m (moment about z axis) is applied to end B of the shaft. Determine: (a) the reactions at supports Cand H, (b) the rotation about z axis of end B of the shaft by using Castigliano's second theorem, (c) the slope (rotation about z axis) at point C of the beam by using Castigliano's second theorem. The shaft and the beam are made of an aluminum alloy for which E = 72 GPa and G=27 GPa. Assume that the hub DF is rigid and neglect the strain energy due to transverse shear.

In-1' 16+29 CHAPTER ENGINEERS MECHANICS STATICS り」 arc ( 24 X(x Sample Problem 6.4.2 JQ) aX9 142 i JA V4 TuS 31 An 800 N-m couple is applied to the flywheel as shown. The coefficient of belt friction is 0.20. The minimum force P required to prevent rotation of the flywheel is applied. 800 N.m dre 2.R 1. Which Tension is larger, TA or TB? Explain 2. What is the angle of contact in radians? 60 3. What is the value of the ratio TA/TB? A B X*ッー Sin=d 6+ミ 2(I+(T Tarc (2) 4)e Eら、1.2 J =3.

Which set of compatibility equations matches the following torsion members connected end-to-end in series? 30 in. O || = C a 560 8₁ a & + gap 05/0 18 in. 6 in. (2) 0 & + ₂ = 0 О ф, = фг 0 8₁ = 8₂ - 8₂ 04+₂=0 & + ₂ = constant Ta (3) 8₁ + gap = 8₂ &₁ = & + gap D. & + ₂ = constant 8 in. (2)

EFx=0= (0.433 F1) - (0.667 F2) - (0.866 F3) + (0.342 P) EFy=0= - (0.250 F1) + (0.667 F2) EFz=0= (0.866 F1) + (0.333 F2) + (0.500 F3) - (0.940 P) Find the magnitude of F1, F2, and F3

Given the following conditions: Q = 0.05 m3/s P1 = 12.5 kPa P2 = 11.5 kPa P3 = 10.3 kPa Find HL (1-3) P2 = 50 mm = 50 mm 10m P3 d. = 30 mm

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The induced nominal stress in a machine member is 28 N/mm? and the value of maximum stress near the irregularities is 61N/mm?, the value of stress concentration factor is SCF, K = Bearings are designated by a standard number internationally, the first digit in the bearing number 6409 represents type of the bearing. Select one: O True O False The value of curvature correction factor k; will be . if the spring index is 6. O a. 1.33 O b. 1.08 O c.0.,92 O d. 4.00 The figure below shows the components of normal forces, the value of radial force on the gear wheel due to a tangential force of 642 N is . N, Take pressure angle as 1420. Pitch point P. Gear driven 02 The radial force is

Which of the statements is correct about the following uniform, slender bar of mass m and length L? L/2 Z Oly > Iz O I₂ = Iy = 12mL² O I > Iy O Iz > Iy y -X

Which is the most appropriate force diagram at point A? Answer quickly. Will upvote.

Just part c

Draw V & M diagram 800 Ib 1000 Ib 4000 Ib 200 Ib 4' 6' 4' R R2

ID=47

= tan-¹ μs The Clamp: Ex.1 (Part 1/2) 24 ?w=? us= 0.3 = 16.7° a) Fon block= FP-400N Lead=4mm T=40Nm D=10mm R=10cm F = FP W F Lead angle Lead 0 -2πr- [0] Φ 10

A beam in Fig. 3a and Fig. 3b is supported by a roller at A and a pin at C. Determine the horizontal and vertical components of support reactions on the beam if a = 3 m and L = 9 m for conditions in Fig. 3a and Fig. 3b, respectively.

For the thrust bearing shown below, normal stress developed due to the loading. Please choose the correct order of average normal stress developed acorss cross section passing B, C and D.       average normal stess crossing section C > average normal stess crossing section B > average normal stess crossing section D     average normal stess crossing section C > average normal stess crossing section D > average normal stess crossing section B     average normal stess crossing section B > average normal stess crossing section C > average normal stess crossing section D     average normal stess crossing section D > average normal stess crossing section B > average normal stess crossing section C

Hello! I am looking for the maximum load rate capacity of this aluminum platform. thank you!

Please draw a FBD only for the circled yellow part known as a rubber base plate :) I don’t want the rest of the system 580N applied Then do one with the whole system

Draw FBD and determine Stress and Safety Factor of Bicycle Axle (Thru Axel)   Specification Weight of cyclist = 120 kg. Materials: Aluminum alloy (AL 6061-T6) Dimension: Length = 122 mm, Diameter = 12 mm, Thread pitch = 1.75 mm, Thread Length = 16 mm.

3 An aluminum stepped shaft (E = 10 × 10³ ksi, v = 0.35), is subjected to three axial forces as shown. For P1= 100 lb, P2 = 128 lb, P3=386 lb, L1=2.5 in, L2= 2.0 in, L3= 1.0 in, determine the elongated/shortened length of section CD. [106 in] (sign sensitive) 1.5 in. DIC L; 1 in. B P₂ 0.5 in. L₁ A₁ P₁

Q2/scale the Rhombus defined by the points p1=( 3,1), p2=(5,3), p3=(3,5) & p43(1,3) by a scale factor of 1/2 keeping the first point in the same location