Lab 6; Friction (Report on Part 3 & 4 for Sandpaper)
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Lab 02: “Friction”; Part 3 and 4 for Sandpaper
Date Performed: Oct 21, 2023
Date Submitted: Oct 24, 2023
Student: Kyra Pell (Ann)
USM ID: w10132479
TA: Shwe Oo
Purpose
Friction is defined as the force resisting the relative motion of objects sliding against each
other, whether they be solid surfaces, fluid layers, or material elements. The purpose of this
experiment was to determine the forces and coefficients of static and kinetic friction of a
sandpaper friction block against a wooden board, as well as calculate the maximum angle of
repose of the sandpaper block. The measured physical quantities of this experiment are the mass
of the block (g), the kinetic frictional forces
F
k
(N), the static frictional forces
F
s
(N) and
finally the angles at which the sandpaper friction block starts to slide down a wooded board. The
physical quantities that are calculated are the total weight of the block and hanging weight (N)
(also known as the normal force), the average static and kinetic frictional forces of three trials, their
corresponding
coefficients (
μ
s
) and (
μ
k
), the maximum angle of repose, the
average angle of
repose regarding three trials, and finally, the precent difference (%) of said angle. The physical
principles used during this experiment are the properties of friction and frictional forces.
Introduction
As previously stated, the purpose of this experiment was to determine the forces and
coefficients of static and kinetic friction of a sandpaper friction block and its maximum angle of
repose. To do this I first needed to measure the mass (g) of the sandpaper friction block, add the
mass of a 100 (g) hanging weight, then convert the total to kilograms (see equation 1) and
calculate its weight (see equation 2). I then set the sandpaper block flat on a wooden board. After
this, I set the 100 (g) hanging weight in the center of the block and connected the block to a spring
scale set at zero. I then measured, in newtons, the kinetic friction force and the static friction force
three times each. After words I took these values and then proceeded to calculate the
corresponding avg forces (see equation 3). Using these values, I then
calculated the correlating coefficients (see equations 4 & 5). Then
using the static friction coefficient, I calculated the
maximum angle of
repose for the sandpaper friction block (see equation 6). Then after
removing the weight, and placing the block in the same starting position, I lifted the wooden board
until the friction block just started to slide, and measured the angle using a protractor, a string, and
a small hanging weight. I repeated this step three times. Using
these measured angles, I then calculated the avg angle of
repose (see equation 3). Finally, I calculated the percent
difference between the predicted maximum angle of repose
and the average measured maximum angle (see equation 7).
The
physical assumptions of this
experiment
are
that I made
accurate
measurements with my scale,
and
protractor. Also, that I made
accurate calculations.
Equation 5
Equation 6
Equation 1
Equation 2
Equation 4
Equation 7
Equation 3
A force that acts parallel to
the surface
1
Friction
A force that acts
perpendicular to the surface
2
Normal
A force that increases as applied force increases up to
some maximum value
3
Static friction
Magnitude depends on the
interacting materials
4
Coefficient of friction
A force that is constant
regardless of the applied force
5
Kinetic friction
Data, Calculations, and Questions
Physics 111L
Friction
Final Report
Student Name
Kyra Pell
Student ID
291291
Lesson
Friction
Institution
University of Southern Mississippi
Session
Fall 2023
Course
Physics 111L
Instructor
Sidney Gautrau
Test Your Knowledge
Match each term to the best description.
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1
N
2
f
4
mg sinθ
3
mg cosθ
1
2
4
3
Static friction
μ
k
Kinetic friction
μ
s
Label the force arrows on the free-body diagram.
Label the force versus time graph.
Categorize each statement as True or False.
True
False
1
2
Static friction is caused by molecular
Kinetic friction is caused by molecular
bonds.
bonds.
Friction between objects increases
Friction does not always increase the
thermal energy of both objects.
temperature of interacting objects.
Increasing in the normal force between
Increasing the surface area of
two objects increases the friction force
interaction between two objects
between them.
increases the friction force between
them.
Exploration
The force of friction always acts parallel to the surface of interaction.
True
False
When the objects are moving relative to one another, the speed of the
moving object affects the magnitude of what is known as the kinetic
friction force.
True
False
The force of static friction is always equal to the coefficient of static friction
multiplied by the normal force.
True
False
The force of kinetic friction for a particular pair of interacting objects
is always
the force of static friction.
less than
greater than
equal to
None of the above
Static friction is caused by molecular
and kinetic friction is caused by
molecular
.
attraction; bonds
attraction; repulsion
bonds; attraction
None of the above
The coefficient of static friction is related to the maximum angle of
repose by
.
μ
s
=sin
θ
ma
x
μ
s
=tan
θ
max
μ
s
=
θ
max
None of the above
The coefficient of kinetic friction is found from the equation:
.
μ
k
=
F
app
F
N
F
N
μ
k
=
z
app
μ
k
=
F
app
×
F
N
None of the above
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rce up to some maximum value. With this said, once an object starts to slide along the surface of another object, the friction force between the objects be
e nature of the interaction), the normal force (which is related to the weight of the object and the angle of the surface) and the properties of the surfaces
orce needed to move the block in either position is the same as well. Since we know that surface area has no direct effect on the forces of friction, this le
e greater the static force needed to indicate movement. This in turn, effects the static friction coefficient, meaning that the less surface area between the
The force of friction is always represented as a horizontal arrow in a
free- body diagram.
True
False
Exercise 1
Explain the difference between static friction and kinetic friction.
Discuss the relationship between friction, normal force, and surface area.
Compare the static and kinetic friction forces and coefficients
determined for the flat wooden friction block and the wooden friction
block on its side that were recorded in Data Table 1. What was the
relationship of surface area to the force and coefficient of friction
d the greater the kinetic frictional force needed to continue movement between the objects. This has led me to believe that the static and the kinetic forc
of the magnitude of a frictional force divided by the normal force’s magnitude. Meaning that the greater the normal force, the greater the static friction c
This is most likely due to human error on my part, I may have misread my spring scale.
raphs, The Static frictional coefficient was always greater than its corresponding kinetic frictional coefficient. In most cases, the coefficient of static frictio
a higher force to overcome the interlocking irregularities. Once the object is in motion, the surfaces slide more smoothly, resulting in a lower resistance to
inetic coefficient is the more accurate. This is because I made my graph using the excel software. In many cases, computers with good software are more
between the objects?
Compare the forces of static and kinetic friction and the coefficients of
static and kinetic friction that were determined for the flat wooden
friction block as the weight (and normal force) of the block changed, as
recorded in Data Table 2. What was the relationship between the normal
force and the forces and coefficients of friction between the two
Materials?
Do your experimental results support the background statement that
the coefficient of kinetic friction is always smaller than the coefficient of
static friction for the same two materials? Explain your answer by
referencing your data and graphs.
Compare the average coefficients of static and kinetic friction found for
the wooden friction block to the coefficient of static and kinetic friction
found from the graph. Do the values match? If not, which method provides
a more accurate calculation of the actual coefficient? Explain your choice.
her surface than all of the materials leading to the highest coefficients.
Note that smooth surfaces tend to have fewer points of contact on a molecular level than rough surfaces. Molecular bonds form where the surfaces do to
happens with a constant velocity. During the scenario the kinetic frictional force can be directly measured under the conditions where it is in equilibrium
se, it is necessary to measure the applied force just before the block begins to move. This allows us to determine the maximum force of static friction tha
tion opposes motion and manifests in various ways, such as static friction that keeps an object at rest, kinetic friction that acts on moving objects, rolling
Which material among the four you tested has the largest coefficients of
static and kinetic friction? Which material has the smallest? Does this
make sense? Why or why not?
When attempting to determine the coefficient of kinetic friction, why is it
necessary to move the block with constant velocity? When attempting to
determine the coefficient of static friction, why is it necessary to
measure the applied force just before the block moves? Are these two
scenarios (constant velocity and almost in motion) the only scenarios
when friction is present? Explain your answer.
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Mass (g)
Weight (N)
F
k
Trial 1(N)
F
k
Trial 2 (N)
F
k
Trial 3 (N)
Average F
k
(N)
μ
k
Flat
5.18
1.40
1.30
1.35
1.35
0.26
Side
5.18
1.30
1.40
1.35
1.35
0.26
Weight (N)
F
s
Trial 1(N)
F
s
Trial 2(N)
F
s
Trial 3(N)
Average Fs (N)
μ
s
Flat
5.18
1.90
1.80
1.85
1.85
0.36
Side
5.18
2.00
2.10
2.00
2.03
0.39
Data Table 1: Friction and Surface Area
Data Table 2: Friction and Normal Force
Weight (N)
F
k
Trial 1 (N)
F
k
Trial 2 (N)
F
k
Trial 3 (N)
Average F
k
(N)
μ
k
calc.
μ
k
calc. avg.
μ
k
graph
5.18
1.40
1.30
1.35
1.35
0.26
0.24
0.28
1.26
0.30
0.35
0.30
0.32
0.25
0.77
0.20
0.15
0.15
0.17
0.22
Weight (N)
F
s
Trial 1 (N)
F
s
Trial 2 (N)
F
s
Trial 3 (N)
Average F
s
(N)
μ
s
calc.
μ
s
calc. avg.
μ
s
graph
5.18
1.90
1.80
1.85
1.85
0.36
0.36
0.36
1.26
0.50
0.40
0.50
0.47
0.37
0.77
0.30
0.25
0.25
0.27
0.35
28.6
Graph 1: Static Friction
Graph 2: Kinetic Friction
Data Table 3: Friction and Surface Material
Material
Weight (N)
F
k
Trial 1 (N)
F
k
Trial 2 (N)
F
k
Trial 3 (N)
Average F
k
(N)
μ
k
Wood
1.26
0.30
0.35
0.30
0.32
0.25
Glass
1.53
0.15
0.15
0.10
0.13
0.08
Sandpaper
1.53
0.70
0.75
0.70
0.72
0.47
Paper
1.27
0.30
0.25
0.30
0.28
0.22
Weight (N)
F
s
Trial 1 (N)
F
s
Trial 2 (N)
F
s
Trial 3 (N)
Average F
s
(N)
μ
s
Wood
1.26
0.50
0.40
0.50
0.47
0.37
Glass
1.53
0.25
0.20
0.20
0.22
0.14
Sandpaper
1.53
0.90
0.80
0.85
0.85
0.56
Paper
1.27
0.50
0.50
0.55
0.52
0.41
Data Table 4: Maximum Angle of Repose
material
θ (°) calc.
θ (°) Trial 1
θ (°) Trial 2
θ (°) Trial 3
θ (°) Average
% Difference
Wood
20.3
30.0
27.0
29.0
28.7
8.6
Glass
8.0
13.0
15.0
13.0
13.7
13.1
Sandpaper
29.2
30.0
30.0
34.0
31.3
1.7
Paper
22.3
25.0
26.0
24.0
25.0
2.9
Competency Review
The friction force is
proportional to the normal force on an object.
inversely
directly
quadratically
None of the above
The
influences the magnitude of the static friction force.
normal force
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coefficient of static friction
applied force
All of the above
The coefficient of static friction for a certain pair of materials is
greater than the coefficient of kinetic friction for the same pair of
materials.
True
False
Smooth surfaces have more points of contact on a molecular level than
rough surfaces.
True
False
The friction force as represented in a free-body diagram always has
the same length as the applied force.
True
False
A box of tools rests in the back of a pickup truck. The truck
accelerates to the north and the box remains at rest in the truck. The
direction of the friction force on the box of tools is
.
north
south
zero
None of the Above
A block of mass 10 kg rests on an incline of 20°. The magnitude of
the friction force on the block is
N.
98
92
34
None of the above
If a go-kart's specifications indicate it can climb a slope of 35°, the
coefficient of static friction between the go-kart tires and the ramp is
.
0.8
0.6
0.7
None of the above
A block of mass 10 kg is pulled by a 30 N force at a constant velocity
along a flat surface. The coefficient of kinetic friction between the
block and the surface
.
0.31
0.47
0.33
None of the above
Extension Questions
In the sport of curling, large smooth stones are slid across an ice
court to land on a target. Sometimes the stones need to move a bit
erefore increasing the friction. Another method would be to increase the mass of the stone or to increase its weight. A way to decrease the kinetic friction
farther across the ice and other times players want the stones to stop
a bit sooner. Suggest a way to increase the kinetic friction between
the stone and the ice so that the stone stops more quickly. Next,
suggest a way to decrease the kinetic friction between the stone and
the ice so that the stone slides farther along the ice before coming to
a stop.
Me and my lab project
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My Calculations
Results
During my experiment I had to calculate the total measured mass of the sandpaper
friction block, 56.08 (g) and a 100 (g) hanging weight in (kg). This led me to a result of 0.15608
(kg). Using this value and the acceleration of gravity, 9.8 (
m
s
2
), I then calculated the
corresponding weight of 1.53 (N). I then proceeded to measure the kinetic frictional forces and
the static frictional forces of three trials.
Resulting in the kinetic frictional forces of 0.70
F
k
(N), 0.75
F
k
(N) and 0.70
F
k
(N), along with the static frictional forces of 0.90
F
s
(N),
0.80
F
s
(N), and 0.85
F
s
(N). Using these values, I then calculated the correlating avg
force values, leading me to the result of 0.72
F
k
(N) and 0.85
F
s
(N). With these average
values and the correlating total weight value, I then calculated the coefficients of the static and
kinetic friction, with the results being 0.47 (
μ
k
), and 0.56 (
μ
s
) respectfully. After this,
using the static friction coefficient value I calculated the maximum angle of repose giving me the
value of 29.2 degrees. I then measured the angle at which the sandpaper friction block started
to slide down the board, three times, giving the resulting values of 30.0 degrees, 30.0 degrees,
and 34.0 degrees respectfully. Using these values, I calculated the avg maximum angle of repose
giving me the value of 31.3 degrees. Finally, I calculated the precent difference of the predicted
maximum angle of repose value and the calculated avg maximum angle of repose, resulting in
the value of 1.7 %. Given the precent difference value is less than 5% I can conclude that this
experiment is valid.
Conclusion
Since this exercise is considered valid, I can assume that my previous assumptions are
correct. These assumptions being that I made accurate measurements with my scale and
protractor and that I made accurate calculations. I can also assume that I used the understood
properties of friction and frictional forces. As the data shows, my static force and coefficients
are higher than my kinetic ones. Also, while my predicted maximum angle of repose value,
found using my static coefficient, was not exact, it was close enough to be considered valid.
Thus, once again making this experiment valid.
Related Documents
Related Questions
Part 2
Set up a spreadsheet solution to this problem. This will require that you derive one
formula to express the relationship between the friction coefficient, the spring constant,
and the spring compression; and a second formula to find the cost of using different slide
and spring types. Set up your spreadsheet as shown below. You can fill in the
"Acceptable?" column manually, rather than using a formula. Turn in a copy of your
spreadsheet/Matlab work
(solve for $)
Friction Spring Constant Spring Compression
M
k
0.1
0.1
0.1
0.2
0.2
0.2
50
100
150
50
100
150
4
Part 3
Your boss has decided to look at a second option. The spring mechanism will be
replaced by a drop box. After leaving the slide, the blocks will travel 5 horizontal feet
through the air and pass through a hole into the drop box. Using the slide you selected
above, determine how far below the slide (h) to place the hole in the drop box.
Yo = 5.2017/5
BLADE
2
RAMPE SLIDE
8⁰
SLIDE
Acceptable?
(Yes or No)
$'
Cost
51
In
DROP…
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O Week 2- 20527 22110L
x a MasteringEngineering Mastering x
M Inbox (10,309) - usmikail@gmail x
a Product Detail Page
a Central Service Technical Manual x
O 21) YouTube
i session.masteringengineering.com/myct/itemView?assignmentProblemiD=12443395&offset=next
KHW 1
Problem 12.3
6 of 16
I Review
A particle travels along a straight line with a velocity
v = (12 – 3t2) m/s, where t is in seconds. When
t = 1 s, the particle is located 10 m to the left of the
origin.
Express your answer to three significant figures and include the appropriate units.
As =
437
Submit
Previous Answers Request Answer
X Incorrect; Try Again; 4 attempts remaining
Part C
Determine the distance the particle travels during the time period given in previous part.
Express your answer to three significant figures and include the appropriate units.
?
ST =
Value
Units
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Kindly do not re-submit your answers if you have solved the problems in this post. I post multiple questions of the same type to get an idea from other tutors. Thank you, Tutor! S.2
Statics of Rigid Bodies
Content Covered:
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Note: Please bear in mind to create 1 problem based on the topic "Method of Sections." Be careful with the calculations in the problem. Kindly double check the solution and answer if there is a deficiency. And also, box the final answer. Thank you so much!
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- Part 2 Set up a spreadsheet solution to this problem. This will require that you derive one formula to express the relationship between the friction coefficient, the spring constant, and the spring compression; and a second formula to find the cost of using different slide and spring types. Set up your spreadsheet as shown below. You can fill in the "Acceptable?" column manually, rather than using a formula. Turn in a copy of your spreadsheet/Matlab work (solve for $) Friction Spring Constant Spring Compression M k 0.1 0.1 0.1 0.2 0.2 0.2 50 100 150 50 100 150 4 Part 3 Your boss has decided to look at a second option. The spring mechanism will be replaced by a drop box. After leaving the slide, the blocks will travel 5 horizontal feet through the air and pass through a hole into the drop box. Using the slide you selected above, determine how far below the slide (h) to place the hole in the drop box. Yo = 5.2017/5 BLADE 2 RAMPE SLIDE 8⁰ SLIDE Acceptable? (Yes or No) $' Cost 51 In DROP…arrow_forwardO Week 2- 20527 22110L x a MasteringEngineering Mastering x M Inbox (10,309) - usmikail@gmail x a Product Detail Page a Central Service Technical Manual x O 21) YouTube i session.masteringengineering.com/myct/itemView?assignmentProblemiD=12443395&offset=next KHW 1 Problem 12.3 6 of 16 I Review A particle travels along a straight line with a velocity v = (12 – 3t2) m/s, where t is in seconds. When t = 1 s, the particle is located 10 m to the left of the origin. Express your answer to three significant figures and include the appropriate units. As = 437 Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Part C Determine the distance the particle travels during the time period given in previous part. Express your answer to three significant figures and include the appropriate units. ? ST = Value Unitsarrow_forwardNumber 3arrow_forward
- Kindly do not re-submit your answers if you have solved the problems in this post. I post multiple questions of the same type to get an idea from other tutors. Thank you, Tutor! S.2 Statics of Rigid Bodies Content Covered: - Method of Sections Direction: Create 1 problem based on the topic "Method of Sections" and then solve them with a complete solution. In return, I will give you a good rating. Thank you so much! Note: Please bear in mind to create 1 problem based on the topic "Method of Sections." Be careful with the calculations in the problem. Kindly double check the solution and answer if there is a deficiency. And also, box the final answer. Thank you so much!arrow_forwardLessons Discussed: Static of Rigid Bodies, Force Vector, Addition of A System of Coplanar Forces, Cartesian Vector, Position and Force Vector Direction, Equilibrium of a Particle, Reminder: Kindly show the complete step-by-step solution. Please make sure that your handwriting is understandable and the picture of the solution is clear. I will rate you with “like/upvote” after. I need the answer right away, thank you. Given Problem: Please see the attached photo.arrow_forwardLessons Discussed: Static of Rigid Bodies, Force Vector, Addition of A System of Coplanar Forces, Cartesian Vector, Position and Force Vector Direction, Equilibrium of a Particle, Reminder: Kindly show the complete step-by-step solution. Please make sure that your handwriting is understandable and the picture of the solution is clear. I will rate you with “like/upvote” after. I need the answer right away, thank you. Given Problem: Please see the attached photo.arrow_forward
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Author:Norman S. Nise
Publisher:WILEY

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ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Cengage Learning

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ISBN:9781118807330
Author:James L. Meriam, L. G. Kraige, J. N. Bolton
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