CE357 Lab 7 Direct Shear

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School

University of Texas *

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Course

357

Subject

Mechanical Engineering

Date

Dec 6, 2023

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pdf

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5

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Laboratory 7 Direct Shear To: Ahmet Mert Kavala From: Nicholas Garcia, neg752 Partners: Jaci Vance, Mason Sirianni, Nhat Anh Jang Date: 11/3/2023 Objective The primary purpose of this lab exercise was to be able to perform a direct shear test on a specimen of dense sand and loose sand. A direct shear test is used to measure the shear stress at a failure for a corresponding normal stress as well as defining the Mohr-Coulomb failure envelope along with the cohesion and angle of internal friction parameters. These hear characteristics of the soil are important properties to keep in mind when doing construction work as these properties give an indication of the soil s strength. Procedure Differences between Manual and Lab For the most part, there weren’t really a lot of differences between our experimental procedure and the procedure outlined in the manual. The main difference that I observed was that in the lab manual it called for running two tests, one for the dense sand and one for the loose sand, whereas in the lab, we did only one test in total. Additionally, the test only ran for 10 minutes total, whereas in the lab manual, it ran longer. We also didn’t do as many of the calculations and plotting outlined in the lab manual as we were going to do them post-lab using the provided data. Results and Discussion Data: Loose Sand
Dense Sand Plots: Loose Sand
Dense Sand Sample Calculations 𝐴??𝑎 𝐶??????𝑖?? 𝐹𝑎???? = = 2 𝜋 (??? −1 ( 0 63 ) − ( 0 63 ) 1 − ( 0 63 ) 2 ) = 1 𝐶???????? 𝐴??𝑎 = 𝐶??????𝑖?? 𝐹𝑎???? ∗ 𝐴??𝑎 = 1 ∗ 3,117.24531 = 3,117.24531 ?? 2 𝐶???????? 𝑁???𝑎? 𝑆????? = 𝑁???𝑎? 𝑆????? ∗ 𝐴??𝑎 𝐶???????? 𝐴??𝑎 = 109.1 ∗ 3,117.24531 3,117.24531 = 109.1 ?𝑃𝑎 𝐶???????? 𝑆ℎ?𝑎? 𝑆????? = 𝑆ℎ?𝑎? 𝐹???? 𝐶???????? 𝐴??𝑎 ∗ 1000 = 0 3,117.24531 ∗ 1000 = 0 ?𝑃𝑎 𝑆???? = tan(𝜑) −→ 𝜑 = ?𝑎? −1 (?????) = ?𝑎? −1 (0.4836) = 25.8 𝑜
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