CE357 Lab 7 Direct Shear
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University of Texas *
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357
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Mechanical Engineering
Date
Dec 6, 2023
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5
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Laboratory 7
Direct Shear
To: Ahmet Mert Kavala
From: Nicholas Garcia, neg752
Partners: Jaci Vance, Mason Sirianni, Nhat Anh Jang
Date: 11/3/2023
Objective
The primary purpose of this lab exercise was to be able to perform a direct shear test on a
specimen of dense sand and loose sand. A direct shear test is used to measure the shear
stress at a failure for a corresponding normal stress as well as defining the Mohr-Coulomb
failure envelope along with the cohesion and angle of internal friction parameters. These hear
characteristics of the soil are important properties to keep in mind when doing construction work
as these properties give an indication of the soil
’
s strength.
Procedure Differences between Manual and Lab
For the most part, there weren’t really a lot of differences between our
experimental procedure
and the procedure outlined in the manual. The main difference that I observed was that in the
lab manual it called for running two tests, one for the dense sand and one for the loose sand,
whereas in the lab, we did only one test in total. Additionally, the test only ran for 10 minutes
total, whereas in the lab manual, it ran longer.
We also didn’t do as many of the calculations
and
plotting outlined in the lab manual as we were going to do them post-lab using the provided
data.
Results and Discussion
Data:
Loose Sand
Dense Sand
Plots:
Loose Sand
Dense Sand
Sample Calculations
𝐴??𝑎 𝐶??????𝑖?? 𝐹𝑎???? =
=
2
𝜋
(???
−1
(
0
63
) − (
0
63
)
√
1 − (
0
63
)
2
) = 1
𝐶???????? 𝐴??𝑎 = 𝐶??????𝑖?? 𝐹𝑎???? ∗ 𝐴??𝑎 = 1 ∗ 3,117.24531 = 3,117.24531 ??
2
𝐶???????? 𝑁???𝑎? 𝑆????? =
𝑁???𝑎? 𝑆????? ∗ 𝐴??𝑎
𝐶???????? 𝐴??𝑎
=
109.1 ∗ 3,117.24531
3,117.24531
= 109.1 ?𝑃𝑎
𝐶???????? 𝑆ℎ?𝑎? 𝑆????? =
𝑆ℎ?𝑎? 𝐹????
𝐶???????? 𝐴??𝑎
∗ 1000 =
0
3,117.24531
∗ 1000 = 0 ?𝑃𝑎
𝑆???? = tan(𝜑) −→ 𝜑 = ?𝑎?
−1
(?????) = ?𝑎?
−1
(0.4836) = 25.8
𝑜
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Related Questions
Please check if it’s correct
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Question 2
In designing prosthetic sockets, the latter will need to be experimentally tested for their
structural integrity. Figure 2 shows one such design of a prosthetic socket which is made of
carbon fibre composite. Strain gauges are installed to record the strains at various locations of
the legs during walking and the readings are recorded using a telemetry system to detemine
the critical stressed area. At a particular strain gauge location indicated in Figure 2, the
readings recorded by one of the 45° strain gauge rosettes are:
Ea = 2500 x 10*, es = 1500 x 10°, & = -950 x 10*
Using Mohr's Cicle or otherwise, detemine:
(a) the principal strains and the direction of the maximum principal strain relative to
the gauge "a".
(b) the corresponding principal stresses and sketch the results on a properly oriented
element.
You may assume that the prosthetic socket is made of polypropylene whose Young's
modulus of 1.0 GPa and Poisson ratio of 0.3.
Figure 2
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Q19 and Q20
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6. State your answers to the following questions.Strain Gauge represents the deformation of a material through a change in resistance. If so, explain how temperature will affect the strain gauge in the experimental environment.①:In this experiment, the Strain Gauge measures the strain in micro units. Explain one possible error factor when applying a load by hanging a weight on the material with the strain gauge attached. (Hint: It is easy to shake by hanging the weight using a thread)①:
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QUESTION
The following data were obtained during a tension test of a low carbon steel specimen
having a gauge length of 100 mm.
At the point where the stress strain curve deviated from linearity, the load was 35KN, the
gauge length was 102.5 mm and the diameter of the specimen was 1.6 mm. Before necking
began, loads of 45 KN and 55 KN produced gauge lengths of 103.4 mm and 107.7 mm
respectively.
Calculate
(a) The Modulus of elasticity
(b) The Strainhardening exponent
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The following data were recorded during the tensile test of a test specimen with a
diameter of 12.8 mm. The gage length is 50.8 mm. The given data are as follow;
Given:
Test specimen material: Aluminum
Diameter of test specimen: Do = 12.8 mm
Length of test specimen: Lo = 50.8 mm
Force and Elongation data for test specimen
Assumptions:
1. The given data is accurate and the material is isotropic
2. The direction of applied force is parallel to the length of the cylinder
Requirement:
To interpret and plot the stress Vs Strain curve for a given specimen
DATA:
LENGTH, mm
STRESS, MPa
LOAD, N
0
50.8
7 330
50.851
15 100
50.902
23 100
50.952
30 400
51.003
34 400
51.054
38 400
51.308
41 300
51.816
44 800
52.832
46 200
53.848
47 300
54.864
47 500
55.88
36 100
56.896
44 800
57.658
42 600
58.42
36 400
59.182
STRAIN
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At higher temperature, strength and strain hardening are increased,
whereas, ductility is decreased which permits greater plastic
deformation
True
False O
Saaly i
The strength constant (C) is increased with increasing of temperature
True O
False O
The metal is becoming weaker as strain increases, this is because of
.strain hardening (work hardening) property
True O
False O
ly
The engineering stress and strain are defined relative to the
instantaneous area and length of test specimen
True O
False O
In sheetmetal working processes, the surface area-to-volume ratio of
.w.p. is low
True O
False O
aly ihi Determine the value of the strain-hardening exponent for a metal that will
cause the average flow stress to be 70% of the final flow stress after
deformation
0.444
0.421
0.422
0.428
aaly i
For pure copper (annealed), the strength coefficient = 330 MPa and
strain-hardening exponent = 0.52 in the flow curve equation. Determine
the average flow stress that the metal experiences if it is…
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1. A tensile test was conducted on a metal "505" specimen and the following stress-strain curves
were generated, both curves generated from the same set of data. Use the graphs to fill in the
mechanical properties of the material tested in the box below. Don't forget units!
Stress vs Strain
Stress, psi
Stress, psi
80000
70000
60000
50000
40000
30000
20000
10000
0
0.00
80000
70000
60000
50000
40000
30000
20000
10000
0.02
0
0.000 0.002
0.04
0.004
0.06
0.006
0.08
0.10
Strain
Stress vs Strain
0.008
0.12
Elastic Modulus, E:
0.2% Offset Yield Strength, oo:
Tensile Strength, ou:
Breaking Strength, of:
% Elongation:
0.14
0.010 0.012 0.014
Strain
0.16
0.18
0.016 0.018
0.20
0.020
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1 %AV l.
1:Y0
A docs.google.com/forms/d/e
مختبر ميكانيك المواد
Why used two equipment in shear force
and bending moment experiment (one for
?S.F and the other to B.M)
إجابتك
What is the relationship between the
?distance from neutral axis and stress
إجابتك
Explain in steps with detail, how can find the
?Young's modulus for any unknown beam
إجابتك
What is the meaning of + S.F, -S.F, +B.M and
?- B.M
إجابتك
صفحة 4 من 5
II
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m2
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A tensile test was performed on a metal specimen with a diameter of
1/2 inch and a gage length (the length over which the elongation is meas-
ured) of 4 inches. The data were plotted on a load-displacement graph,
P vs. AL. A best-fit line was drawn through the points, and the slope of
the straight-line portion was calculated to be P/AL = 1392 kips/in. What
is the modulus of elasticity?
BI
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Answer this quick
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The following data were collected from a 12
mm diameter test specimen of Magnesium.
LOAD (N)
0
5000
10000
15000
20000
25000
26500
27000
26500
25000
GAUEGE LENGTH (mm)
30.000
30.0296
30.0592
30.0888
30.15
30.51
30.90
31.50 (maximum load)
32.10
32.79 (fracture)
After the fracture, the gauge length is 32.61 mm and
the diameter is 11.74 mm.
a) What is the elastic modulus?
b) Percent elongation at fracture?
c) Percent elongation after fracture?
d) What is the Poisson's ratio?
e)Draw the engineering stress-strain diagram
corresponding to the values in the table. Call this plot
I. Now consider this experiment is repeated at a
higher temperature with an identical sample. Draw
the new engineering stress-strain diagram, call it plot
Il and highlight the differences (on the same graph)
between I and II.
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Answer both parts
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Q9
Please provide justified answer asap
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Need help starting this assignment.
1- Determine the maximum normal stress, the maximum shear stress, the Modulus of Elasticity, the maximum bending moment and the maximum stress due to bending (also known as flexure stress) on the material, from the information provided.
2- From the results of your analysis, determine what material was used for this test. Check whether the material can withstand the different types of loading the hip implant experiences. Use a factor of safety of 4.
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Please do it fast and do both pls it's a request but please explain both and handwritten pls I will rate
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Current Attempt in Progress
X Incorrect.
Two previously undeformed cylindrical specimens of an alloy are to be strain hardened by reducing their cross-sectional areas (while
maintaining their circular cross sections). For one specimen, the initial and deformed radii are 15 mm and 12 mm, respectively. The
second specimen, with an initial radius of 14 mm, must have the same deformed hardness as the first specimen; compute the second
specimen's radius, in mm, after deformation.
r= i 8.8
eTextbook and Media
Hint
Save for Later
mm
R
Attempts: 1 of 3 used Submit Answer
C
No
Ur
Qu
Num
Units
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10. The following results were obtained in a tensile test on a mild steel specimen of original diameter
20 mm and gauge length 40 mm.
Load at limit of proportionality
80 kN
Extension at 80 kN load
0.048 mm
Load at yield point
85 kN
Maximum load
150 kN
When the two parts were fitted together after being broken, the length between gauge length was
found to be 55.6 mm and the diameter at the neck was 15.8 mm.
Calculate Young's modulus, yield stress, ultimate tensile stress, percentage elongation and percentage
[Ans. 213 kN/mm2; 270 N/mm²; 478 N/mm²; 39%; 38%]
reduction in area.
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The % of error between a theoretical shear modulus of 65 GPa and an experimental modulus of rigidity of 60235 MPa is:
Select one:
O a. 0.0791 %
O b. 7.33 %
O c. 0.0668 %
O d. 7.9 %
Torrion test is annlied to study the properties of a material subjected to tensile force.
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1. Plot the engineering stress & strain diagram of
an alloy having a tensile test result found in
Table 1. The tensile test specimen has a
diameter of 12.5mm and a gage length of
50.0mm.
The given alloy is used to make a 30.0mm diameter
cylinder, which is placed inside a hardened circular
steel casement with a 30.01mm inner diameter.
Table 1: Tensile test results of an alloy
Change In Length
(mm)
Change In Diameter
(mm)
Load (kN)
0.000
0.0000
0.0000
4.364
0.0254
0.0019
-0.0057
13.092
0.0762
21.819
0.1270
0.0095
30.547
32.729
0.1778
0.7620
34.911
3.0480
30.01 mm O
F
Rigid Plate
Cylindrical Alloy
-Steel casement
Figure k Section view of the steel casement
encapsulating the cylindrical alloy
2. Determine the required minimum value of F
such that the cylindrical alloy would touch the
walls of the steel casement.
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Question Five (5)
In an experiment to determine mechanical properties of a material, samples from the material
were subjected to a tensile force. In the process, deformations were closely monitored from the
beginning of the experiment to the point when the sample failed. The observed deformations
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were analysed and were as presented in Figure 5.1 below. Based on this figure, answer the
following questions
a) Using a well labelled sketch, explain
what stress and strain are, and give
respective SI units
b) State the material properties obtained
from the points labelledA, B, C and D
on Figure 5.1
c) Given results similar to Figure 5.1,
explain how you would determine a
material's property labelled B.
d) Given results similar to Figure 5.1,
explain how you would determine a
material's Young's modulus.
e) What measurements would you take if
you were to determine a materials'
Poisson's ratio.
D
B
Strain (%)
Figure 5.1:Tensile stress-strain behaviour of
a…
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Please show work for practice problem 12
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Related Questions
- Please check if it’s correctarrow_forwardQuestion 2 In designing prosthetic sockets, the latter will need to be experimentally tested for their structural integrity. Figure 2 shows one such design of a prosthetic socket which is made of carbon fibre composite. Strain gauges are installed to record the strains at various locations of the legs during walking and the readings are recorded using a telemetry system to detemine the critical stressed area. At a particular strain gauge location indicated in Figure 2, the readings recorded by one of the 45° strain gauge rosettes are: Ea = 2500 x 10*, es = 1500 x 10°, & = -950 x 10* Using Mohr's Cicle or otherwise, detemine: (a) the principal strains and the direction of the maximum principal strain relative to the gauge "a". (b) the corresponding principal stresses and sketch the results on a properly oriented element. You may assume that the prosthetic socket is made of polypropylene whose Young's modulus of 1.0 GPa and Poisson ratio of 0.3. Figure 2arrow_forwardQ19 and Q20arrow_forward
- 6. State your answers to the following questions.Strain Gauge represents the deformation of a material through a change in resistance. If so, explain how temperature will affect the strain gauge in the experimental environment.①:In this experiment, the Strain Gauge measures the strain in micro units. Explain one possible error factor when applying a load by hanging a weight on the material with the strain gauge attached. (Hint: It is easy to shake by hanging the weight using a thread)①:arrow_forwardQUESTION The following data were obtained during a tension test of a low carbon steel specimen having a gauge length of 100 mm. At the point where the stress strain curve deviated from linearity, the load was 35KN, the gauge length was 102.5 mm and the diameter of the specimen was 1.6 mm. Before necking began, loads of 45 KN and 55 KN produced gauge lengths of 103.4 mm and 107.7 mm respectively. Calculate (a) The Modulus of elasticity (b) The Strainhardening exponentarrow_forwardThe following data were recorded during the tensile test of a test specimen with a diameter of 12.8 mm. The gage length is 50.8 mm. The given data are as follow; Given: Test specimen material: Aluminum Diameter of test specimen: Do = 12.8 mm Length of test specimen: Lo = 50.8 mm Force and Elongation data for test specimen Assumptions: 1. The given data is accurate and the material is isotropic 2. The direction of applied force is parallel to the length of the cylinder Requirement: To interpret and plot the stress Vs Strain curve for a given specimen DATA: LENGTH, mm STRESS, MPa LOAD, N 0 50.8 7 330 50.851 15 100 50.902 23 100 50.952 30 400 51.003 34 400 51.054 38 400 51.308 41 300 51.816 44 800 52.832 46 200 53.848 47 300 54.864 47 500 55.88 36 100 56.896 44 800 57.658 42 600 58.42 36 400 59.182 STRAINarrow_forward
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- m2arrow_forwardA tensile test was performed on a metal specimen with a diameter of 1/2 inch and a gage length (the length over which the elongation is meas- ured) of 4 inches. The data were plotted on a load-displacement graph, P vs. AL. A best-fit line was drawn through the points, and the slope of the straight-line portion was calculated to be P/AL = 1392 kips/in. What is the modulus of elasticity? BIarrow_forwardAnswer this quickarrow_forward
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