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Drosophila Melanogaster Lab Experiment

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Extended Experimental Investigation | May 28
2013
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Drosophila melanogaster lab experiment
Question: How do the dominant or recessive genes in particular traits in a cross between a male and female Drosophila determine the traits of its offspring?
Aim: to establish whether characteristics produced from the offspring of a drosophila cross are recessive or dominant traits.
Hypothesis: If certain phenotypes are expressed in the offspring from the cross of certain Drosophila, then the determination or justification of recessive or dominant phenotypes can be found.
Theory review and justification of the hypothesis:
Drosophila Melanogaster are simply now generally referred as the common term “fruit fly” or “vinegar fly”. These fruit
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The chance of it being a heterozygous Wildtype male is 50%.
Genotypes= X-W X-v, X-W X-v, X-W Y, X-W Y
= 1:1:
= ½:1/2
Phenotypes= Wildtype female, Wildtype male 50% 50%
Therefore the chance of the offspring being a heterozygous Wildtype drosophila is 100%. The chance of it being a heterozygous Wildtype male is 50%.
Vile 3 consisted of one Vestigial (male) and one Wild type (female).vial 4 consisted of one Wild type (female) and an Ebony (male). If both of these vial’s flies are homozygous the offspring for botch will end up 100% heterozygous wild type as it is the dominant characteristic. This is also evident through punnet squares:
Vial 3
W – Wildtype v- Vestigial

Genotypes= X-W X-e, X-W X-e, X-W Y, X-W Y
= 1:1:
= ½:1/2
Phenotypes= Wildtype female, Wildtype male 50% 50%
Therefore the chance of the offspring being a heterozygous Wildtype drosophila is 100%. The chances of it being a heterozygous Wildtype male is 50%,
Genotypes= X-W X-e, X-W X-e, X-W Y, X-W Y
= 1:1:
= ½:1/2
Phenotypes= Wildtype female, Wildtype male 50% 50%
Therefore the chance of the offspring being a heterozygous Wildtype drosophila is 100%. The chances of it being a heterozygous Wildtype male is 50%,
Vail 4
W- Wildtype e- Ebony

Materials:
The materials used in this prac are as follows: * 2.5 grams of powder culture (8ml loose packed) + 5-7 ml of water and 4-6 grains of yeast * Necessary amount of Petri dishes to examine
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