In this double titration experiment determining composition of soda ash, you are given the following data:M HCl titrant: 0.0501 M +/- 0.0507Mass of soda ash sample, g: 0.2505 ± 2.0e-4 (Analytical Balance)Total volume of Sample Stock, mL: 75 ± 0.05 (100mL graduated cylinder)Volume of Sample Stock Aliquot, mL: 25 ± 0.3Find the missing information. Show solutions Phenolphthalein EndpointAnswer the concentrations in 3 significant figure.The tolerance or error should follow the decimal place of the value.You can use scientific notation using "e". Example: 0.0010 = 1.0e-3Note that the confidence interval is totally separate from the tolerance/errors.Trial12Net vol. of HCI7.60 ± 0.147.90 + 0.147.90 + 0.14(Vph), MLFinal titrantvolume incalculations,0.10000.10000.1000mL% composition+I+1+1 Methyl Orange EndpointAnswer the concentrations in 3 significant figure.The tolerance or error should follow the decimal place of the value.You can use scientific notation using "e". Example: 0.0010 = 1.0e-3Note that the confidence interval is totally separate from the tolerance/errors.Trial123Net vol. of HCL12.00 ± 0.14 12.20 ± 0.1412.00 ± 0.14(Vmo), mLFinal titrantvolume incalculations0.1000.1000.100% composition+1+I

For phenolphthalein Endpoint Using the molarity equation; M1V1 (for Hcl)=M2 V2 (Noda Ash)(5.05×10-2…

Answered: 05 ± 2.0e-4 (Analytical Balance) Total…

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05 ± 2.0e-4 (Analytical Balance) Total volume of Sample Stock, mL: 75 ± 0

Appl Of Ms Excel In Analytical Chemistry

2nd Edition

ISBN:9781285686691

Author:Crouch

Publisher:Crouch

Chapter3: Statistical Tests With Excel

Section: Chapter Questions

Problem 1P

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Question

In this double titration experiment determining composition of soda ash, you are given the following data:

M HCl titrant: 0.0501 M +/- 0.0507
Mass of soda ash sample, g: 0.2505 ± 2.0e-4 (Analytical Balance)
Total volume of Sample Stock, mL: 75 ± 0.05 (100mL graduated cylinder)
Volume of Sample Stock Aliquot, mL: 25 ± 0.3

Find the missing information. Show solutions

Phenolphthalein Endpoint
Answer the concentrations in 3 significant figure.
The tolerance or error should follow the decimal place of the value.
You can use scientific notation using "e". Example: 0.0010 = 1.0e-3
Note that the confidence interval is totally separate from the tolerance/errors.
Trial
1
2
Net vol. of HCI
7.60 ± 0.14
7.90 + 0.14
7.90 + 0.14
(Vph), ML
Final titrant
volume in
calculations,
0.1000
0.1000
0.1000
mL
% composition
+I
+1
+1

Methyl Orange Endpoint
Answer the concentrations in 3 significant figure.
The tolerance or error should follow the decimal place of the value.
You can use scientific notation using "e". Example: 0.0010 = 1.0e-3
Note that the confidence interval is totally separate from the tolerance/errors.
Trial
1
2
3
Net vol. of HCL
12.00 ± 0.14 12.20 ± 0.14
12.00 ± 0.14
(Vmo), mL
Final titrant
volume in
calculations
0.100
0.100
0.100
% composition
+1
+I

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